A solution that is 0.20 m in hcho2 and 0.15 m in nacho2 find ph

Answers

Answer 1
Final answer:

The pH of a buffer solution such as the one presented, made of a weak acid and its salt, is calculated using the Henderson-Hasselbalch equation. However, without the Ka value (acid dissociation constant) for the weak acid, the exact pH cannot be calculated.

Explanation:

This question is relating to the concept of buffer solutions in chemistry, particularly the pH calculation of a buffer solution made from a weak acid (HCHO2) and its salt (NaCHO2). The pH of a buffer solution is calculated using the Henderson-Hasselbalch equation, which is pH = pKa + log ([A-]/[HA]). That said, the exact pH cannot be calculated without the given Ka (acid dissociation constant) value for HCHO2. However, with the PH and Ka values, one would substitute the values in the equation to obtain the final pH of the solution.

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Answer 2

To find the pH of a solution containing 0.20 M HCHO₂ and 0.15 M NaCHO₂, use the Henderson-Hasselbalch equation. Given the pKa of 3.75 for formic acid, the pH is calculated to be approximately 3.63.

Calculating the pH of a Solution Containing HCHO₂ and NaCHO₂

To determine the pH of a solution that is 0.20 M in HCHO₂ and 0.15 M in NaCHO₂, we can use the Henderson-Hasselbalch equation:

pH = pKa + log ([A⁻]/[HA])

For formic acid (HCOOH, also denoted as HCHO₂), the pKa is approximately 3.75.

Step-by-Step Calculation:

Identify the concentration of the acid (HCHO₂) and its conjugate base (CHO₂⁻, provided by NaCHO₂).

Substitute the values into the Henderson-Hasselbalch equation:

Given: [HCHO₂] = 0.20 M, [NaCHO₂] = 0.15 M, pKa = 3.75

pH = 3.75 + log (0.15 / 0.20)

3. Calculate the log term:

log (0.15 / 0.20) = log (0.75) ≈ -0.125

4. Add the terms together:

pH = 3.75 - 0.125 = 3.625

Therefore, the pH of the solution is approximately 3.63.


Related Questions

Matter appears to be conserved in chemical reactions but not in nuclear reactions because:

A. the law of conservation of matter only applies to a limited number of chemical and nuclear reactions

B. the law of conservation of mass-energy applies only to nuclear reactions

C. in nuclear reactions, particles move too quickly to have their masses measured

D. in nuclear reactions the changes in mass are large enough to be detected

I think it's A? Just tell me if I'm right, and if I'm wrong, point me in the right direction :)

Answers

a. the law of conservation of matter only applies to a limited number of chemical and nuclear reactions. 

What does mass measure?

Answers

Mass is the amount of matter in an object. Move to a different planet and an object's weight will change, but its mass will be the same. 
Mass is the amour of weight and or matter in an object or person

A certain weak acid, ha, has a ka value of 8.4×10−7. calculate the percent ionization of ha in a 0.10 m solution

Answers

To determine the percent ionization of the acid given, we make use of the acid equilibrium constant (Ka) given. It is the ratio of the equilibrium concentrations of the dissociated ions and the acid. The dissociation reaction of the HF acid would be as follows:

HA = H+ + A-

The acid equilibrum constant would be expressed as follows:

Ka = [H+][A-] / [HA] = 8.4 x 10^-7

To determine the equilibrium concentrations we use the ICE table,
         HF             H+              A-
I      0.10           0                 0
C      -x              +x               +x
---------------------------------------------
E    0.10-x        x                   x 

8.4 x 10^-7= [H+][A-] / [HA] 
8.4 x 10^-7 = [x][x] / [0.10-x] 

Solving for x,

x = 0.0002894 = [H+] = [A-]

percent ionization = 0.0002894 / 0.10 x 100  = 0.289%

What is the molar mass of (NH4)2O? Explain how you calculated this value.

Answers

Atomic masses  :

N =14 a.m.u
H = 1 a.m.u
O =16 a.m.u

Therefore:

( NH₄)₂O = (14 * 2) + (1 * 4 *2) + (16* 1) => 52.0 g/mol


The molar mass of (NH₄)₂O (ammonium oxide) is 52.10 g/mol.

To calculate the molar mass of (NH₄)₂O (ammonium oxide), we need to determine the total sum of the atomic masses of all the atoms in the chemical formula.

The atomic masses are as follows:

N (Nitrogen) = 14.01 g/mol

H (Hydrogen) = 1.01 g/mol

O (Oxygen) = 16.00 g/mol

Now, let's calculate the molar mass of (NH₄)₂O:

Molar mass of (NH₄)₂O = (2 x N) + (8 x H) + (1 x O)

Molar mass of (NH₄)₂O = (2 x 14.01 g/mol) + (8 x 1.01 g/mol) + (1 x 16.00 g/mol)

Molar mass of (NH₄)₂O = 28.02 g/mol + 8.08 g/mol + 16.00 g/mol

Molar mass of (NH₄)₂O = 52.10 g/mol

So, the molar mass of (NH₄)₂O (ammonium oxide) is approximately 52.10 g/mol.

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What observations would lead you to believe that the ink is actually a mixture?

Answers

When using filter paper chromatography to separate ink, one will observe that more colours are mixed into darker inks. The darker an ink is, the more the colours that will be separated out during chromatography process. Thus,  the observation that the darker the ink, the more colours are mixed into it will lead one to believe that ink is a mixture. 

QUESTION 5

In their compounds, metals:

are assigned positive oxidation numbers

are assigned negative oxidation numbers

are assigned oxidation numbers of zero

can be assigned any oxidation number that balances the equation

QUESTION 6

In the reaction, Zn (s) + Fe+2 (aq) Imported Asset Zn+2 (aq) + Fe (s), the oxidizing agent is:

the Zn

the Fe

the Zn+2

the Fe+2

Answers

For the first question, the correct answer would be the first option. In their compounds, metals are assigned positive oxidation numbers. They have positive oxidation reactions since when in their compounds they are the one to donate their electrons making them positive from their neutral state. For the second question, the correct answer would be the last option. The oxidizing agent would be the iron ion or the Fe2+. The oxidizing agent is the one that is being reduced in the reaction since it accepts the electrons given by the reducing agent. The reducing agent would be the zinc metal.

In compounds, metals have positive oxidation numbers; for instance, iron has a +2 oxidation number in FeO. In the reaction Zn + Fe2+  → Zn2+ + Fe, Fe2+ is the oxidizing agent as it gains electrons and is reduced.

In their compounds, metals are generally assigned positive oxidation numbers because they tend to lose electrons and form cations. For example, in FeO, iron has an oxidation number of +2 (Fe2+), correctly balancing the -2 charge from oxygen to result in a neutral compound.

Regarding the reaction Zn (s) + Fe2+ (aq) → Zn2+ (aq) + Fe (s), the oxidizing agent is the species that is reduced by gaining electrons. In this case, Fe2+ is the oxidizing agent because it gains electrons from Zn to form Fe (s). The Zn is oxidized to Zn2+, making it the reducing agent.

The Valence Electrons of an Atom of Which Element would feel a Greater Effective Nuclear Charge than the Valence?
The Valence Electrons of an Atom of which element would feel a greater effective Nuclear Charge than the valence electrons of a Boron (B) atom?

Aluminum (Al)
Beryllium (Be)
Hydrogen (H)
Carbon (C)

Answers

Final answer:

Carbon's valence electrons feel a greater effective nuclear charge than those of a Boron atom because Carbon has one more proton without significantly increasing the shielding effect, leading to a stronger pull on the valence electrons.

Explanation:

The question asks which element's valence electrons feel a greater effective nuclear charge than those of a Boron (B) atom. To answer this, one must understand how shielding and effective nuclear charge work. As we go from left to right across a period in the periodic table, while the number of core electrons remains the same, the nuclear charge increases. This means the valence electrons feel a stronger pull from the nucleus since they are not effectively shielded by the same number of core electrons. Comparing Boron with Aluminum (Al), Beryllium (Be), Hydrogen (H), and Carbon (C), we find that Carbon, having one more proton than Boron, does not increase the shielding effect significantly, which leads to its valence electrons feeling a greater effective nuclear charge than Boron's. Therefore, Carbon (C) is the correct response.

What volume of 0.0250 m calcium hydroxide is required to neutralize 33.50 ml of 0.0200 m nitric acid?

Answers

The chemical formula for calcium hydroxide is Ca(OH)₂ and that of nitric acid is HNO₃. By these chemical formula it can be deduced that the number of equivalents per mole of Ca(OH)₂ is 2 because of 2 OH⁻ and for HNO₃ is 1 because of H⁺.

For the neutralization reaction, the number of equivalents should be equal. 
             V₁n₁ = V₂n₂

Substituting the known values and with the incorporation of the concept above,
     (V₁)(0.0250 mol/L)(2 equivalents/mol) = (33.50 mL)(0.020 mol/L)(1 equivalent/mol)

         V₁ = 13.4 mL

Hence, the volume of calcium hydroxide needed is approximately equal to 13.4 mL. 

An elixir of ferrous sulfate contains 220 mg of ferrous sulfate in each 5 ml. if each milligram of ferrous sulfate contains the equivalent of 0.2 mg of elemental iron, how many milligrams of elemental iron would be represented in each 5 ml of the elixir?

Answers

To determine the mass of elemental iron in the elixir, we need to understand the given values given above. We are given the following:

Mass of ferrous sulfate = 220 mg
Volume of the elixir = 5 mL
Mass of elemental iron / mass of ferrous sulfate = 0.2 mg Fe / mg ferrous sulfate

Therefore, from the given values, we simply multiply the mass of the ferrous sulfate in the elixir and the equivalent mass of elemental iron per mass of ferrous sulfate. We do as follows:

Mass of Fe = 220 mg ferrous sulfate  ( 0.2 mg Fe / mg ferrous sulfate )
Mass of Fe = 44 mg
Final answer:

Each 5 ml of the ferrous sulfate elixir contains 44 milligrams of elemental iron.

Explanation:

The question is asking for the amount of elemental iron in 5 ml of ferrous sulfate elixir. Given that each milligram of ferrous sulfate contains 0.2 mg of elemental iron and there's 220 mg of ferrous sulfate present in every 5 ml, a simple multiplication would give the quantity of elemental iron in each 5 ml of the elixir.

Formula: Ferrous Sulfate (mg) x Elemental Iron/Ferrous Sulfate = Elemental Iron (mg)  

Using the given values, it goes as follows: 220 mg x 0.2 = 44 mg. Consequently, each 5 ml of the elixir contains 44 milligrams of elemental iron.

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What elements make up molecules of sugar?

Answers

The predominant elements that compose or make up sugar or similar molecules of glucose, fructose, sucrose etc, are mainly made of Carbon, Hydrogen, Oxygen.

Consider the reaction cl2(g) + br2(g) <=> 2 brcl(g), which is endothermic as written. what would be the effect on the equilibrium position of removing cl2(g)?

Answers

The equilibrium means that the forward reaction and the reverse reation happen at the same rate.

Forward reaction Cl2(g) + Br2 (g) ----> 2BrCl(g)

Reverse reaction 2BrCl(g) ----> Cl2(g) + Br2(g).

When one of the reactants in an equilibrium rection is removed, the equation results out of equilibrium, and the products will increase their reaction to restart the equilibrium producing more of the reactants species.

That is named by telling that the equilibrium is displaced to the left (side of the reactants).

What is the molarity of the solution made by dissolving a 5.67 g of potassium chloride in enough water to make 100 mL of the solution

Answers

There are a number of ways to express concentration of a solution. This would include the molarity. It is expressed as the number of moles of solute per volume of the solution. For example, we are given a solution of 2M NaOH this describes a solution that has 2 moles of NaOH per 1 L volume of the solution. We calculate as follows:

molarity = 5.67 g KCl ( 1 mol KCl / 74.55 g KCl ) / (100 mL solution) ( 1 L / 1000 mL ) = 0.76 mol KCl / L solution or 0.76 M

Therefore, the molarity of the given solution above would be 0.76 M.

What is the only subatomic particle that is directly involved in the chemical reactions?

Answers

it is an electron i hope this helps

What is the H+ if the pH of a solution is 1.65?

Answers

The pH of a solution is measure of the acidity of a certain solution based from the concentration of the hydrogen ions. It is associated with the hydrogen ion dissolved in the solution. It is expressed as pH = -log [H+]. We calculate the concentration of the hydrogen ions from this expression.

 pH = -log [H+]
1.65 = -log [H+]
antilog [- 1.65] = [H+]
[H+] = 10^-1.65
[H+] = 0.0224 M

Answer:

[H⁺]  = 2.2 × 10⁻²

Explanation:

pH = -log [H⁺]

10∧-pH = [H⁺]

[H⁺]  = 10⁻¹°⁶⁵

[H⁺]  = 0.0224

[H⁺]  = 2.2 × 10⁻²

So the concentration of hydrogen in solution of 1.65 pH is  2.2 × 10⁻².

Calculate the pressure in atmospheres exerted by 10.0moles of hydrogen gas at 293 kelvins if it is stored in a 7.50 liter container. Your value should be a decimal number written to three significant figures. Given: R= 0.08205 liter x atmosphere/mole x kelvin

Answers

To determine the pressure of the gas, we need an equation which would relate pressure to the values given like the number of moles, temperature and the volume of the system. For simplicity, we can assume that the hydrogen gas is an ideal gas so we use the equation PV=nRT where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant and T is the temperature. 

PV = nRT
P = nRT / V
P = 10.0 mol  (0.08205 L - atm / mol-K) (293 K) / 7.50 L
P = 32.0542 atm

 Therefore, the pressure of the system would be 32.054 atm

Answer:

The correct answer is 32.1 atm. If you rearrange the ideal gas law equation to find pressure (P) and substitute the known values for the rest of the variables (n, T, and V), we get pressure equal to 32.1 atm.

Explanation:

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What is the molarity of a sodium hydroxide solution if 35.4 ml of this solution is neutralized by 24.2 ml of 1.19 m sulfuric acid solution?

Answers

The item above can be calculated by equating the equivalents of the solutions. 

The equivalent of the solution is calculated by through normality. Normality is equal to molarity if the compound has only 1 equivalent.
  
                           1.19 M H2SO4 = 2.38 N H2SO4

                             N1V1 = N2V2

For sodium hydroxide, NaOH, molarity is equal to normality.
 
                        (N1)(35.4 mL) = (2.38)(24.2 mL)
                                N1 = 1.627 N = 1.627 M

Thus, the molarity of the NaOH solution is equal to 1.627. 
Final answer:

The molarity of the sodium hydroxide solution is approximately 0.818 M.

Explanation:

To determine the molarity of the sodium hydroxide solution, we can use the equation for the reaction between sodium hydroxide and sulfuric acid: 2NaOH + H₂SO4 → Na₂SO4 + 2H₂O. From the balanced equation, we can see that the ratio of NaOH to H₂SO4 is 2:1. Thus, if 24.2 mL of 1.19 M sulfuric acid solution neutralizes 35.4 mL of the sodium hydroxide solution, we can set up the following equation:

Molarity of NaOH × Volume of NaOH = Molarity of H₂SO4 × Volume of H₂SO4

Molarity of NaOH × 35.4 mL = 1.19 M × 24.2 mL

Rearranging the equation, we get:

Molarity of NaOH = (1.19 M × 24.2 mL) / 35.4 mL

Calculating the molarity of NaOH, we find that it is approximately 0.818 M.

Which of the following changes requires an oxidizing agent?
O2 yields 2O2-
SO3 yields SO42-
2F- yields F2
MnO2 yields Mn2+

Answers

2F⁻ → F₂ + 2e⁻

(mainly electrochemical oxidation)

Answer : The correct option is, [tex]2F^-\rightarrow F_2+2e^-[/tex]

Explanation :

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In the oxidation reaction, the oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Oxidizing agent : It is defined as the substance which has ability to oxidize the other substances by gaining electrons.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In the reduction reaction, the oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the substance which has ability to reduce the other substances by losing electrons.

From the given options, we conclude that

(1) [tex]O_2+4e^-\rightarrow 2O^{2-}[/tex]

(2) [tex]SO_3+H_2O\rightarrow SO_4^{2-}+2H^+[/tex]

(3) [tex]MnO_2+4H^++2e^-\rightarrow Mn^{2+}+2H_2O[/tex]

The reaction 1, 2 and 3 shows the reduction reaction. So, it requires a reducing agent.

(4) [tex]2F^-\rightarrow F_2+2e^-[/tex]

The reaction 4 shows the oxidation reaction. Therefore, it requires an oxidizing agent.

Therefore, the correct option is, [tex]2F^-\rightarrow F_2+2e^-[/tex]

Describe one chemical property of Group 1 metals that results from the atoms of each metal having only one valence electron.

Answers

Their ability to lose that electron easily. This property is electronegativity. Once that electron is taken away, the atom becomes an ion with a charge of +1. The ion would be much more stable than the atom, because once the electron is lost, the shell underneath will already have 8 electrons that resembles the configuration of a noble gas.

A chemical property of Group 1 metals that results from the atoms of each metal having only one valence electron is electronegativity.

Group 1 elements are also known as alkali metals. They include sodium, lithium, potassium, cesium, francium, and rubidium. They can be found in seawater.

A chemical property of Group 1 metals that results from the atoms of each metal having only one valence electron is electronegativity. This means the tendency for the atoms to be able to attract electrons.

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Nuclear fusion of hydrogen into helium occurs in the

Answers

There are types of nuclear reaction: nuclear fusion and nuclear fission. The difference is that fusion is a combination of two elements while fission is the breaking up of the subatomic particles of an element creating a new element. The limiting element to this is Iron. Iron-26 is the most stable element. As a result, elements lighter than Fe-26 are generally fusible. This includes hydrogen and helium.

This reaction is common in the stars, most especially the Sun. The energy of the Sun comes from its abundant hydrogen composition which becomes fusible into Helium. This occurs at a temperature of 14 million Kelvin. The nuclear reaction is a not a one-way step process as shown in the picture.

Nuclear fusion of hydrogen into helium occurs in the core of stars, specifically in their stellar cores.

This process is known as stellar nucleosynthesis and is the primary source of energy production in stars. The intense heat and pressure in the core of a star allow hydrogen nuclei (protons) to overcome their mutual electrostatic repulsion and undergo fusion reactions. It results in the formation of helium nuclei.

The most common fusion reaction in stars is the proton-proton chain, which involves a series of steps leading to the conversion of four hydrogen nuclei into one helium nucleus.

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What is the average kinetic energy of a gas at 285 kelvin? (R = 8.314 J/K-mol)

Answers

the answer would be 3.55 x 10^3 j/mol

Answer:

The average KE = 312 J/mol

Explanation:

Given:

Temperature of the gas, T = 285 K

Gas constant, R = 8.314 J/K-mol

To determine:

The average kinetic energy of the gas

Explanation:

Based on the kinetic theory of gases, the average kinetic energy is given as:

[tex]KE = \frac{3}{2} RT\\[/tex]

In this case:

[tex]KE = \frac{3}{2} *8.314\ J/K-mol * 285\ K = 312 J/mol[/tex]

The national drug code number (NDC) of the drug is included in this section of a drug monograph

Answers

How supplied(page 42-45)

The solubility of silver chloride can be increased by dissolving it in a solution containing ammonia. agcl (s) ag+ (aq) + cl- (aq) k1 = 1.6 x 10-10 ag+ (aq) + 2nh3 (aq) ag(nh3)2+ (aq) k2 = 1.5 x 107 what is the value of the equilibrium constant for the overall reaction? agcl (s) + 2nh3 (aq) ag(nh3)2+ (aq) + cl- (aq) knet = ?

Answers

Final answer:

To calculate the net equilibrium constant for the dissolution of silver chloride in ammonia, the individual constants for the dissolution of AgCl and the formation of  [tex][Ag(NH_3)_2]^+[/tex] are multiplied, yielding Knet = 2.4 x 10^-3.

Explanation:

The solubility of silver chloride (AgCl) in ammonia solution can be analyzed using the concept of equilibrium constants. The equilibrium constant (K) for the dissolution of AgCl in water is given as 1.6 x 10-10, and the formation constant (K2) of the complex ion [tex][Ag(NH_3)_2]^+[/tex] is 1.5 x 107. To find the net equilibrium constant (Knet) for the overall reaction where AgCl dissolves in the presence of NH3 to form the complex ion and release Cl-, we can multiply the individual constants: K1 * K2. Thus, Knet = (1.6 x 10-10)(1.5 x 107) = 2.4 x 10-3.

Which pair of elements is most apt to form an ionic compound with each other?

Answers

Ionic compounds are compounds that are formed together by a cation and an anion. A cation is an ion with a positive charge. For example, Na+ and Ca2+. An ion has a negative charge, like Cl- and OH-. There is a greater chance of forming an ionic compound when they have a great difference in electronegativity, the ability to attract electrons toward itself. In the periodic table, elements that are opposite to each other, more likely found in opposite sides, would be more apt to form an ionic compound. Example would be NaCl and CaCl2 or Ca(OH)2.

A chemist dissolves 192.mg of pure sodium hydroxide in enough water to make up 150.ml of solution. calculate the ph of the solution.

Answers

Sodium hydroxide (NaOH) is a strong base, which means it should dissociate (more or less) fully. This means there's a 1:1 ratio of Na to OH⁻, making concentration calculations easy. 
First, use the molar mass to calculate how many moles of OH⁻ is in 192 mg of NaOH. (The molar mass of NaOH is approximately 40.0 g/mol.) 
192 g NaOH × 1 mol / 40.0 g NaOH = 4.80 mol NaOH (and OH⁻)
Then, find the concentration by dividing that by by the volume of liquid. We must first convert it to liters: 
150. mL × 1 L / 1000 mL = 0.150 L 
4.80 mol OH⁻ / 0.150 L = 32.0 mol/L OH⁻
Then, we apply −㏒ to the concentration.
−㏒32.0 = −1.505.

We are not done. This is pOH, and we want pH. There's a few ways to find pH, but the easiest one (given that the solution's at STP) is to subtract the answer from 14 (pH + pOH = 14).
14 − (−1.505) = 15.505 (note that with pH, only the figures after the decimal point count as significant figures).

Another way is to take the concentration of OH- and find the concentration of H₃O⁺. We take Kw (1.0 x 10⁻¹⁴) and divide it by 32.0, since [OH⁻] x [H₃O⁺] = Kw.
1.0 x 10⁻¹⁴ / 32.0 M OH⁻ = 3.13 x 10⁻¹⁶ M H₃O⁺
Then apply −㏒ to the concentration:
−㏒3.13 x 10⁻¹⁶ = 15.505. 

The answer is pH = 15.505.

Brainliest if answered in the next 5 minutes.

Identify the balanced combination equation.

Cl2O5 + H2O ⟶ 2HClO3

2Fe(OH)3 ⟶ Fe2O3 + 3H2O

Cl2O5 + 3H2O ⟶ HClO3

2Fe(OH)3 ⟶ 2FeO3 + 3H2O

Answers

Cl2O5 + 3H2O ⟶ HClO3 

Answer: The correct answer is [tex]Cl_2O_5+H_2O\rightarrow 2HClO_3[/tex]

Explanation:

Combination reaction is defined as the type of reaction in which teo smaller compounds join or combine together to form a large compound.

General representation is given by:

[tex]A+B\rightarrow AB[/tex]

A balanced chemical equation always follow law of conservation of mass. The law states that the total number of individual atoms on the reactant side is always equal to the total number of atoms on the product side.

From the given options:

The equation that is an example of balanced combination reaction is

[tex]Cl_2O_5+H_2O\rightarrow 2HClO_3[/tex]

what is the percent composition in chloric acid (HClO3)?

Answers

total weight = 1 + 35.45 + 3 * 16 = 84.45

H = 1 / 84.45 * 100% = 1.18%
Cl = 35.45 / 84.45 * 100% = 41.98%
O = 48 / 84.45 * 100% = 56.84%

Determine the [oh] concentration in a 0.169 m ca(oh)2 solution. 0.338 m 0.169 m 5.92 x 10-14 m 2.96 x 10-14 m 0.298 m

Answers

Answer: 0.338
Explanation
Ca(OH)2 , also known as calcium hydroxide, is a strong base although it is not very soluble in water.
Therefore the concentration of 1 OH is equal to 0.169 m,
Since Ca(OH)2 contains two OH, therefore, concentration of O[OH] is given as:
[OH] = 2 x 0.169 = 0.338 m 
Final answer:

The [OH-] concentration in the 0.169 M Ca(OH)2 solution is 0.0088 M. The pOH of the solution is 2.055, and the pH is 11.945.

Explanation:

We begin by determining the concentration of hydroxide ions, [OH-], in the Ca(OH)2 solution. Since Ca(OH)2 is a strong base, there are two OH ions for every formula unit dissolved, so the concentration of OH- is 2 times the concentration of Ca(OH)2. Therefore, [OH-] = 2 × 0.0044 M = 0.0088 M.

The concentration of hydroxide ions can be used to calculate the pOH of the solution. The pOH is obtained by taking the negative logarithm of [OH-]. In this case, pOH = -log(0.0088) = 2.055.

To calculate the pH of the solution, subtract the pOH from 14. pH = 14 - 2.055 = 11.945.

An organic compound in which a carbonyl group is bonded to two different carbon atoms is a(n) amide. aldehyde. ketone. ester.

Answers

An organic compound in which a carbonyl group is bonded to two different carbon atoms is a ketone. The ketones are organic compounds in which a carbonyl group (C=O) is bonded to two carbon atom. A carbonyl group is a carbon-oxygen double bond. Ketones are of great importance in industry and in biology, as solvents, polymer precursors, and pharmaceuticals.

Answer: ketone

Explanation:

Functional groups are specific group of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules.

1. Amides have functional group [tex]-O=C-NH_2[/tex].

Example: Ethanamide with molecular formula [tex]CH_3CONH_2[/tex]

2. Aldehydes have functional group [tex]-O=CH[/tex].

Example: Ethanal with molecular formula [tex]CH_3CHO[/tex]

3. Ketones have functional group [tex]-C=O[/tex].

Example: Propanone with molecular formula [tex]CH_3COCH_3[/tex]

4. Esters have functional group [tex]-O=C-OR[/tex].

Example: methyl ethanoate with molecular formula [tex]CH_3COOCH_3[/tex]

which statement best describes why specific heat capacity is often more useful than heat capacity for scientists while comparing two materials

Answers

its Specific heat capacity is an intensive property and does not depend on sample size.

Answer:

A.

key words: intensive, does not depend on sample size

Explanation:

Predict how the addition of a catalyst would affect the rate of the reaction below, and explain your prediction. h2 (g) + i2 (g) 2hi

Answers

The reaction will start sooner and maybe come to an end sooner than if no catalyst was added.
This can be explained as follows:
For the chemical reaction to occur, the minimum required activation energy must be available in the system.
A catalyst decreases this activation energy resulting in an earlier start and maybe an earlier termination of the reaction.

Explanation:

A catalyst helps in increasing the rate of a chemical reaction without itself getting consumed in the reaction.

Basically, a catalyst decreases the activation energy so that reactant molecules can easily participate in the reaction.

For example, when a catalyst is added to [tex]H_{2}(g) + I_{2}(g) \rightarrow 2HI[/tex] then there will be a decrease in activation energy and both reactants (hydrogen and iodine) can easily participate in the chemical reaction.

As a result, formation of product (HI) becomes faster.

Thus, we can conclude that a catalyst helps in increasing the rate of a reaction.

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