write all names that apply to each number 121/121

Answers

Answer 1
121/121



one

etc

hope this helps
Answer 2
1/1, 2/2, 3/3, and so on.


Related Questions

Please help. Should only have two terms, this means you have to combine like terms and simplify. Take a look at photo.

Answers

The yard is a rectangle, and the shed is also a rectangle.
You need to find the areas of the two rectangles.
Then, subtract the area of the shed from the area of the yard.
Yard: length = 13x - 4; width = 5x
Shed: length = 2x + 4; width = 2x

Area of yard:
A = LW = (13x - 4)(5x) = 65x^2 - 20x

Area of shed:
A = LW = (2x + 4)(2x) = 4x^2 + 8x

Area of lawn = area of yard - area of shed

Area of lawn = (65x^2 - 20x) - (4x^2 + 8x)
                     = 65x^2 - 20x - 4x^2 - 8x
                     = 61x^2 - 28x

The area of the lawn is 61x^2 - 28x

Assume ABC=DEF. if AB=18, BC=10, and AC=25, what is the length of DF?

Answers

The answer is D. 25

It’s easiest to find the solution by drawing out the triangles side by side with the lengths. It is what I did to find the answer

The length of DF is equal to 25 units. Then the correct option is D.

What is a triangle?

Triangle is a shape made of three sides in a two-dimensional plane. the sum of the three angles is 180 degrees.

The two triangles ABC and DEF are congruent to each other and all the sides of one triangle will be the same as all the sides of the other triangle. The value of DF is equal to AC. AC is 25 so DF is equal to 25.

Hence, option D is correct.

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on a suspension bridge the roadway is hung from cables hanging between support towers. the cable of one bridge segment of the parabola y=.1x^2-7x +150 where y is the height of the cable in feet above the roadway at the distance x feet from a support tower. what is the closest the cable comes to the roadway? how far from the support towers does this occur

Answers

The parabola opens upward and is symmetric to the y-axis. Its general form is: . y \;=\;ax^2 + c Its y-intercept is (0, 10) . . . Hence: . y \;=\;ax^2 + 10 It passes through (200, 100). We have: . 100 \:=\:a\cdot200^2 + 10 \quad\Rightarrow\quad a \:=\:\frac{9}{4000} Hence: . y \;=\;\tfrac{9}{4000}x^2 + 10 When x = \pm50,\;\;y \:=\:\tfrac{9}{4000}(50^2) + 10 \:=\:\frac{125}{8} Therefore, 50 feet from the center, the cable is 15\tfrac{5}{8} feet high.

The library is 0.96 mile away from Theo’s home. Write this distance as a fraction in simplest from.

Answers

24/25 in fraction and simplest form. Hope this helps!

A football team has attempted 6 running plays. The change in field position resulting from each play is shown in the table.


Running Play Outcomes
Play 1
–3 yards
Play 2
2 yards
Play 3
–1 yard
Play 4
–2 yards
Play 5
–3 yards
Play 6
1 yard

What is the average change in field position per running play?
–6 yards per play
–1 yard per play
0 yards per play
1 yard per play

Answers

Answer:

–1 yard per play

Step-by-step explanation:

To find the average, add together all of the outcomes and divide by the number of plays, 6:

(-3+2+-1+-2+-3+1)/6 = -6/6 = -1

Answer: -1 yard per play

Step-by-step explanation:

The average of a data set is given by :-

[tex]\text{Average}=\frac{\text{Sum of all data values}}{\text{Total number of values}}[/tex]

Given: The total number of plays =6

Sum of the change in field position resulting from each play is given by :-

[tex]\text{Sum}=-3+2+(-1)+(-2)+(-3)+1=-3+2-1-2-3+1=-6[/tex]

Now, the average change in field position per running play is given by :-

[tex]\text{Average}=\frac{\text{Sum}}{\text{Total plays}}\\\\=\frac{-6}{6}=-1[/tex]

Hence, the average change in field position per running play is -1 yard per play.

[tex]3/2y+12=7/5y-20[/tex]

Answers

[tex]\bf \cfrac{3}{2y}+12=\cfrac{7}{5y}-20\impliedby \begin{array}{llll} \textit{now, let's multiply both sides by 10y}\\ \textit{thus, getting rid of the denominators} \end{array} \\\\\\ 10y\left( \cfrac{3}{2y}+12 \right)=10y\left( \cfrac{7}{5y}-20 \right)\implies 15+120y=14+200y \\\\\\ 1=200y-120y\implies 1=80y\implies \boxed{\cfrac{1}{80}=y}[/tex]

Convert the decimal number 625 to binary using addition/subtraction method

Answers

1001110001=625 in binary hope this helps

What is the product of a number and it’s reciprocal

Answers

The product of a number is always one. Both numbers cancel each other in the numerator and denominator. 

For example: 1/3*3= 1   1/4*4=1
The product of a number and it's reciprocal is simply 1.

3/4g=-12 I need help solving this

Answers

That is the answer of ur problem
3/4g = -12
/3/4      /3/4
g = -16

v=1/3πr2h solve for r

Answers

See photo for worked out solution.
Hope this helps!

Final answer:

To solve V =[tex](1/3)\pi r^2h[/tex] for r, multiply both sides by 3, then divide by πh, and finally take the square root of both sides to get r = √(3V / (πh)).

Explanation:

The student has asked to solve the equation V = [tex](1/3)\pi r^2h[/tex] for r, where V is the volume of a cylinder, r is the radius, and h is the height. To do this, we will isolate r on one side of the equation:

Multiply both sides of the equation by 3 to get rid of the fraction: 3V = [tex]\pi r^2h[/tex].

Divide both sides of the equation by πh to solve for [tex]r^2[/tex]: [tex]r^{2}[/tex] = 3V / (πh).

Take the square root of both sides to solve for r: r = √(3V / (πh)).

This gives us the formula for r in terms of V and h.

During a particular baseball​ season, a team averaged​ 41,602 fans per home game. suppose attendance during the season follows the normal probability distribution with a standard deviation of​ 9,440 per game. what is the probability that a randomly selected game during the season had an attendance greater than​ 50,000 people?

Answers

Final answer:

By calculating the z-score for an attendance of 50,000 and referring to the z-table, we find that the probability that a randomly selected game had an attendance greater than 50,000 is approximately 18.67%.

Explanation:

In this question, we are given that the average attendance for a baseball season is 41,602 with a standard deviation of 9,440. We are asked to find the probability that a randomly selected game had an attendance greater than 50,000.

First, we have to find the z-score, which is calculated as: z = (X - μ) / σ , where X is the value from our dataset (in this case, 50,000), μ is the mean (41,602), and σ is the standard deviation (9,440). Plugging the numbers in, we get: z = (50000 - 41602) / 9440 ≈ 0.89.

Typically, the area to the right (greater than) of z = 0 is 0.5 in a standard normal distribution. However, we are interested in the area to the right of z = 0.89. To find this area, we can look at a z-table or use a calculator with a normal distribution function. The area to the right of z = 0.89 is approximately 0.1867, which means that the probability a randomly selected game had an attendance greater than 50,000 is roughly 18.67%.

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What is 9 (3 x 4)??????

Answers

if you are doing order of operations than it would be 108 but if you were doing distributive property it would be 27 x 36 which is 972 

HOPE THIS HELPS!!
Is 108 do what’s in parentheses first (3x4)=12 then you do 9x12 witch is 108. Hope this helps

  What is the volume of the pyramid? 
11*11*12 are the missing dimensions 
 
       A. 420 cm3   B. 139 cm3   C. 142 cm3   D. 484 cm2

Answers

always use y=mx+b !!!! 11= 11x +12 

The number of feet between 2 objects varies directly as the number of miles. If the distance between 2 objects is 2 1/2 miles or 13,200 feet how many feet are equivalent to a distance of 7 miles

Answers

[tex]\bf \qquad \qquad \textit{direct proportional variation}\\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array}\\\\ -------------------------------[/tex]

[tex]\bf \stackrel{feet}{f}=k\stackrel{miles}{m}\textit{ we also know that } \begin{cases} m=2\frac{1}{2}\\ f=13200 \end{cases}\implies 13200=k\cdot 2\frac{1}{2} \\\\\\ 13200=k\cfrac{5}{2}\implies \cfrac{13200\cdot 2}{5}=k\implies 5280=k \\\\\\ \boxed{f=5280m} \\\\\\ \textit{when m = 7, what is \underline{f}?}\qquad \qquad f=5208(7)[/tex]

Solve the simultaneous equations 2x+3y=13
4x-y=-2

Answers

2x + 3y = 13
4x - y = -2

In the second equation, subtract 4x from both sides.

-y = -2 - 4x

Divide both sides by -1.

y = 2 + 4x

Put this into the first equation in place of y.

2x + 3(2 + 4x) = 13

Multiply everything in the parenthesis by 3.

2x + 6 + 12x = 13

Combine like terms.

14x + 6 = 13

Subtract 6 from both sides.

14x = 7

Divide 14 on both sides.

x = 7 / 14

x = 0.5

Put this into the second equation in place of x.

4(0.5) - y = -2

2 - y = -2

Subtract 2 from both sides.

-y = -4

Divide both sides by -1.

y = 4

So x = 0.5 and y = 4.

Hope this helps!

The value of x and y are 0.5 and 4 respectively.

2x+3y=13 ..... i

4x-y=-2 ...... ii

Multiply equation i by 4

Multiply equation ii by 2

8x + 12y = 52 ..... iii

8x - 2y = -4 ...... iv

Subtract iv from iii

14y = 56

Divide both side by 14

14y/14 = 56/14

y = 4

Since 4x-y=-2

4x - 4 = -2

4x = -2 + 4.

4x = 2

x = 2/4 = 0.5

Therefore, x = 0.5 and y = 4

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using three data points (x,y) that we know Evil passed through and the general quadratic equation, create three corresponding equations:

Answers

The general quadratic equation is y = ax^2 + bx + c.

Let's see whether it's possible to invent 3 separate points thru which the graph of a quadratic passes and then to create 3 equations in a, b and c:

Suppose the points are (-3,2), (-1,1) and (2,4).

Focus on (-3,2):  Here x= -3 and y= 2.  Then 2 = a(-3)^2 + b(-3) + c, or
                                                                        2 = 9a - 3b + c

Do the same thing for the other 2 points, (-1,1) and (2,4).

When you're done, you'll have 3 linear equations in the variables a, b and c.

You were not asked to solve for a, b and c.

If you want, however, we could go thru that process.

100 equals 15 minus a number all divided by 5

Answers

100 = (15 - x)/5

100(5) = (15-x/ 5)5

500 = 15 - x

500 - 15 = 15 (-15) - x

485/-1 = -x/-1

x = -485

hope this helps

bob has $180 deducted from his paycheck. his taxable rate is 18%. write a function deduction and write a functiontaxable

Answers

32.4 is what is deducted from his paycheck because 18% of 180 is 32.4

Determine the solution set of (x + 1)2 = 25.

Answers

(x + 1) 2 = 25

2x + 2 = 25

2x +2 - 2 = 25 - 2

2x/2 = 23/2

x = 23/2

hope this helps

Answer:The real answer is actually {-6,-4}

Step-by-step explanation: There's the answer hope that helps

China's population is 1.446×10^9 . Marshall Islands's population is 6.025×10^4 . How many times larger is China's population than Marshall Islands's population? Drag and drop the values into the boxes to represent the answer in scientific notation.

Answers

(1.446×10^9) ÷ (6.025×10^4)
= 0.24 x 10^5
= 2.4 x 10^4

answer

2.4 x 10^4

China's population is 2.4 x 10^4 times larger than Marshall Islands's population.

How does scientific notations work?

The number is written in the form  [tex]a \times 10^b[/tex] where we have   [tex]1 \leq a < 10[/tex]. The number b shows the order, which is the most important figure for which scientific notation is used. It tells us how much order large or small a value is in powers of 10. Scientific notations have some of the profits as; Better readability due to compact representation. Its value in terms of power of 10 is known, which helps in easy comparison of quantities differing by a large value.

We have given that

China's population = 1.446 × [tex]10^9[/tex]. Marshall Islands's population is 6.025× [tex]10^4[/tex]).

Then ;

(1.446 × [tex]10^9[/tex]) ÷ (6.025 × [tex]10^4[/tex])

= 0.24 x 10 power of 5

= 2.4 x [tex]10^4[/tex]

Therefore, China's population is 2.4 x 10^4 times larger than Marshall Islands's population.

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A total of
682

tickets were sold for the school play. They were either adult tickets or student tickets. There were 68 fewer student tickets sold than adult tickets. How many adult tickets were sold?

Answers

If we make [tex]a[/tex] an integer that represents the adults that bought tickets, and [tex]s[/tex] the number of students, then we have the equations [tex]a+s=682[/tex], and [tex]a=68+s[/tex]. 

Using the second equation, we find that [tex]s=a-68[/tex], so we plug this value of [tex]s[/tex] into the first equation to get [tex]a+(a-68)=682[/tex]. We simplify to find [tex]2a=750[/tex]. We divide by [tex]2[/tex] to isolate the desired variable to get [tex]a=\boxed{375\text{ adult tickets were sold}}[/tex]. 
Final answer:

The problem is solved by forming and solving algebraic equations derived from the provided information. After manipulating the equations, we find that 375 adult tickets were sold.

Explanation:

This problem can be solved using algebraic equations. Let's denote the number of adult tickets sold as x and the number of student tickets as y. From the problem, we know two things:

The total number of tickets sold, which is x + y = 682.There were 68 fewer student tickets sold than adult, that gives us y = x - 68.

Now we can substitute the second equation into the first to get rid of y:

x + (x - 68) = 682.

This simplifies to 2x - 68 = 682. Adding 68 to both sides gives 2x = 750. Dividing both sides by 2 results in x = 375. This means that 375 adult tickets were sold.

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Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
A(n)=-6+(n-1)(6)
A. 0, 18, 54
B. –6, 18, 54
C. 6, 18, 54
D. –6, 12, 48

Answers

the firs term
A(1)=-6+(1-1)(6)
A(1)=-6+(0)(6)
A(1)=-6



The fourh term
A(n)=-6+(n-1)(6)
A(4)=-6+(4-1)(6)
A(4)=-6+(3)(6)
A(4)=-6+18
A(4)=12


The tenth term
A(10)=-6+(10-1)(6)
A(10)=-6+(9)(6)
A(10)=-6+54
A(10)=48

Answer: 
D.  -6,12,48

replace n with 1, 4 and 10 and solve the equations:

 answers would be D. –6, 12, 48


-6+(1-1)*6 = -6

-6+(4-1)*6 = 12

-6+(10-1)*6 = 48

A local gym offers a trial membership for 3 months. It discounts the regular monthly fee x by $25. If the total cost of the trial membership is less than $100, you will consder signing up. What inequality can yu use to determine whether you should sign up?

Answers

3(x - 25) < $100.  We're not req'd to solve this.


Aubrey can run at a pace of 6 miles per hour. Running at the same rate how many miles can she run in 90 minutes

Answers

Aubrey can run 9 miles in 90 minutes at her pace of 6 miles per hour.

To find how many miles Aubrey can run in 90 minutes, we can use the formula:

[tex]\[ \text{Distance} = \text{Speed} \times \text{Time} \][/tex]

Given that Aubrey can run at a pace of 6 miles per hour and there are 90 minutes in 1.5 hours:

[tex]\[ \text{Distance} = 6 \, \text{miles/hour} \times 1.5 \, \text{hours} \]\[ \text{Distance} = 9 \, \text{miles} \][/tex]

Therefore, Aubrey can run 9 miles in 90 minutes at her pace.

The table represents a linear function.

Answers

Answer:

the slope of the function is -6

Step-by-step explanation:

Hello

You could  use the slope formula to find the slope of this linear function.  

just two points are needed,let´s take these ones

p1(-1,2)  and p2(0,-4)

[tex]s=\frac{y2-y1}{x2-x1} \\s=\frac{-4-2}{0-(-1)} \\s=\frac{-6}{1} \\s=-6[/tex]

so, we have that the slope of the line is -6

I hope it helps you

Have a fantastic day

The slope of the line is -6, the first option.

What is the slope?

If a line has two points (x₁, y₁) and (x₂, y₂), then the slope of the line is given by:

a = (y₂ - y₁)/(x₂ - x₁)

Here we can use the first two points (-2, 8), (-1, 2) to get:

a = (2 - 8)/(-1 + 2) = -6

The correct option is the first one.

20 points Copper Creek Pizza is having a special. If you order a large pizza for the regular price of 17 dollars you can order any number of additional large pizzas for 8.50 dollars each

a) Complete the table to show the cost of ordering up to 4 large pizzas

Number of Large Pizzas: 1 | 2 |3 | 4
Total Cost:

b) Write an explicit and a recursive rule for the cost of placing an order for n large pizzas

c) What is the cost of placing an order for 20 large pizzas

d) Five people each make an order for 3 large pizzas. How much money would they have saved if they placed one order for 15 pizzas? Explain

Answers

Final answer:

To calculate the cost of pizzas at Copper Creek Pizza with their special offer, we use provided formulas for up to 4 pizzas, and extend those to 20 pizzas. The total cost for 20 pizzas would be $178.50. If a group ordered together, they could save $34 by placing one order for 15 pizzas instead of separate orders.

Explanation:

To complete the table showing the cost of ordering up to 4 large pizzas from Copper Creek Pizza, we calculate the total cost based on the special deal provided. For any additional large pizza after the first one, the price is $8.50 each.

Number of Large Pizzas: 1 | Total Cost: $17Number of Large Pizzas: 2 | Total Cost: $17 + $8.50 = $25.50Number of Large Pizzas: 3 | Total Cost: $17 + $8.50 + $8.50 = $34Number of Large Pizzas: 4 | Total Cost: $17 + $8.50 + $8.50 + $8.50 = $42.50

The explicit rule for the cost of n large pizzas is Cost = 17 + 8.50(n - 1), where n is the number of pizzas ordered.

The recursive rule is Costn = Costn-1 + 8.50, with the initial condition Cost1 = 17.

For part (c), the cost of ordering 20 large pizzas is calculated as: Cost = 17 + 8.50(20 - 1) = 17 + 8.50(19) = 17 + 161.50 = $178.50.

For part (d), if five people each make an order for 3 large pizzas, the total cost would be 5 x ($17 + 2 x $8.50) = 5 x ($34) = $170. If they placed one order for 15 pizzas, the cost would be $17 + 14 x $8.50 = $136. Therefore, they would have saved $170 - $136 = $34.

For the line that has the equation 4x1 + 8x2 = 88, an axis intercept is:

Answers

The given equation is
4x + 8x² = 88

That is,
8x² + 4x - 88 = 0
or
2x² + x - 22 = 0
The x-axis intercepts are determined by the solution of the quadratic equation as
x = (1/4) [-1 +/- √(1+176)] = 3.076 or -3.376

Answer: 3.076 or -3.376

You are working as a clinical chemist in charge of testing of the blood samples. you are required to fix a sodium chloride solution with water in the ratio of 2:3 .

a) starting with 580ml of the sodium chloride solution, how much water needs to be added?

B) Give your answer in standard form to the appropriate number of significant figures

Answers

[tex]\bf \cfrac{sodium~chloride}{water}\qquad 2:3\qquad \cfrac{2}{3}\implies \cfrac{2\cdot \frac{580}{2+3}}{3\cdot \frac{580}{2+3}}\implies \cfrac{2\cdot 116}{3\cdot 116}\implies \cfrac{232}{348}[/tex]

Chuck combines 6.42 liters of red paint with 6.87 liters of blue paint to make purple paint. He pours the paint equally into 3 containers, and has 2.64 liters of paint left over. How many liters of paint are in each container?

Answers

it would be 4.005
hope im right

What is the solution to the proportion 6-10 = 9-x

Answers

First 6-10=-4
So then you get -4=9-X
Now you subtract 9 on both side
-4=9-X
-9. -9
----------
-13= -X
Now make the X positive basically get rid of the negative on both sides
x=13
Check by substituting in 13 for X
9-13= -4
6-10= -4
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