Option (a) 3H⁺(aq) + Al(OH)₃(s) → Al³⁺(aq) + 3H₂O(l) is the net ionic equation for the reaction between nitric acid and aluminum hydroxide. This equation represents the primary species undergoing chemical change. It excludes spectator ions to show only the substances involved in the actual chemical reaction.
Among the given options, the correct net ionic equation is:
(a) 3H⁺(aq) + Al(OH)₃ (s) → Al³⁺(aq) + 3H₂O(l)
Here is the explanation:
The complete molecular equation is:3HNO₃(aq) + Al(OH)₃(s) → Al(NO₃)₃(aq) + 3H₂O(l)This equation shows that nitric acid (HNO₃) reacts with aluminum hydroxide (Al(OH)₃) to form aluminum nitrate (Al(NO₃)₃) and water (H₂O).To find the net ionic equation, we focus on the species that actually participate in the reaction, excluding spectator ions:H⁺(aq) and OH⁻(aq) ions form water:3H⁺(aq) + Al(OH)₃ (s) → Al³⁺(aq) + 3H₂O(l)Thus, option (a) is the net ionic equation for this reaction.
Complete Question:
Which one of the following is the net ionic equation for the reaction of nitric acid with aluminum hydroxide?
(a) 3H⁺(aq) + Al(OH)₃ (s) → Al³⁺(aq) + 3H₂O(l)
(b) 3HNO₃ (aq) + Al(OH)₃ (s) → 3Al(NO₃)₃ (aq) + 3H₂O(C)
(c) 2H⁺(aq) + Al(OH)₂ (s) → Al²⁺ (aq) + 2H₂O(l)
(d) H⁺(aq) + OH⁻(aq) → H₂O(l)
(e) 3NO₃⁻(aq) + Al³⁺(aq) → Al(NO₃)₃ (aq)
What was the problem with Rutherford's model? a. It described a nucleus. c. It could not explain the chemical properties of elements. b. It did not include electrons d. It described quantums.
What components did you collect to convert your two molecules of pyruvate to acetyl-coa?
Final answer:
In biology, high school students learn about the conversion process of pyruvate into acetyl CoA for the Krebs cycle. The components involved include Pyruvate Dehydrogenase Enzyme, Acetyl CoA, and Oxaloacetate.
Explanation:
In the process of converting three-carbon pyruvate molecules into two-carbon acetyl groups for entry into the Krebs cycle, several components are involved:
Pyruvate Dehydrogenase Enzyme: This enzyme catalyzes the conversion of pyruvate into acetyl Coenzyme A (acetyl CoA) in the mitochondrial matrix.
Acetyl CoA: The two-carbon molecule formed from the conversion of pyruvate, ready to enter the Krebs cycle.
Oxaloacetate: A four-carbon molecule in the Krebs cycle that combines with acetyl CoA to initiate the cycle by forming citrate.
Which ion channel opens in response to a change in membrane potential and participates in the generation and conduction of action potentials?
The voltage-gated ion channel opens in response to a change in membrane potential and is involved in the generation and spreading of action potentials. As the membrane depolarizes, voltage-gated sodium channels open, allowing sodium ions to enter the muscle fiber, leading to the spread of action potential.
Explanation:The ion channel that opens in response to a change in membrane potential and participates in the generation and conduction of action potentials is known as a voltage-gated ion channel. As the membrane depolarizes, voltage-gated sodium channels are triggered to open. Sodium ions then enter the muscle fiber initiating a process known as excitation-contraction coupling which results in an action potential, a transmission of an electrical signal, swiftly spreading along the entire membrane. This mechanism is critical to the function of neurons and muscle fibers.
Typically, the voltage of the inner portion of the membrane is negative. When this voltage becomes less negative, the voltage-gated channel allows ions to cross the membrane. It is also worth noting, that voltage-gated channels can become inactivated for a brief period after activation, during which they will not open in response to a signal.
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In which process is glucose oxidized to form two molecules of pyruvate?
Glycolysis is the biological process where glucose is oxidized to form two molecules of pyruvate. Here, glucose is broken down using ATP and NAD+, generating energy for the cell and creating substrates for the Krebs cycle in the presence of oxygen.
Explanation:The process in which glucose is oxidized to form two molecules of pyruvate is known as glycolysis. In the presence of ATP and NAD+, glucose is broken down into pyruvate, yielding a net gain of two ATP and two NADH molecules. These molecules carry high-energy electrons that are used later to produce even more ATP in the mitochondria. If oxygen is present, the pyruvate continues to the Krebs cycle (also known as the citric acid cycle) for further processing and energy extraction. Thus, glycolysis is a crucial step in cellular metabolism, converting glucose into usable energy and preparing it for further oxidation in the Krebs cycle if aerobic conditions are met.
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Write 578,000,000 in scientific notation.
To write 578,000,000 in scientific notation, move the decimal point to the left until there is only one non-zero digit to the left of the decimal point, resulting in 5.78 × 10^8.
Explanation:To write 578,000,000 in scientific notation, we need to move the decimal point to the left until there is only one non-zero digit to the left of the decimal point. In this case, we can move the decimal point 8 places to the left, resulting in 5.78 × 108.
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The human body obtains 835 kJ of energy from a chocolate chip cookie. If this energy were used to vaporize water at 100 ∘C, how many grams of water could be vaporized? The heat of vaporization of water at 100 ∘C is 40.7 kJ/mol. Assume that the density of water is 1.0 g/mL.
Answer:
Amount of water that can be vaporized = 369 g
Explanation:
Heat content of the cookie (q) = 835 kJ
Latent heat of vaporization of water (ΔHvap) = 40.7 kJ/mol
Density of water = 1 g/ml
Calculation:
Heat content of cookie = Heat absorbed by water
q = n(ΔHvap)
n = moles of water
n = q/ΔH = 835 kJ/ 40.7 kJ/mol = 20.516 moles
Molar mass of water = 18 g/mol
Mass of water = moles * molar mass = 20.516 moles * 18 g/mol = 369.3 g
Write a possible full set of quantum numbers for the electron gained when a bromine atom (br) becomes a bromide ion (br−).
The possible values of all quantum numbers for the electron gained by Br atom to form [tex]{\text{B}}{{\text{r}}^-}[/tex] is [tex]\boxed{n=4,\;l=1,\;{m_l}=1,\;{m_s}=-\frac{1}{2}}[/tex]
Further explanation:
Quantum numbers:
Quantum numbers govern the size, energy, shape, and orientation of an orbital. The four quantum numbers are as follows:
1. Principal Quantum Number (n): It denotes the principle electron shell. The values of n are positive integer (1, 2, 3,…).
2. Angular Momentum Quantum Number (l): It represents the shape of an orbital. The value of l is an integer from 0 to (n-1). (Refer to the table in the attached image)
3. Magnetic Quantum Number[tex]\left( {{m_l}} \right)[/tex]: This quantum number represents the orientation of the orbital in space. The value of [tex]{m_l}[/tex]lies between –l to +l. The formula to calculate the value of [tex]{m_l}[/tex] is as follows:
[tex]{m_l}=-l,(-l+1),.....,0,1,2,.....,(l-1),l[/tex]
Therefore, the total number of [tex]{m_l}[/tex] values for a given value of l is 2l+1.
4. Electron Spin Quantum Number[tex]({m_s})[/tex]: It represents the direction of the electron spin. Its value can be [tex]+ \frac{1}{2}[/tex]or[tex]- \frac{1}{2}[/tex].
The atomic number of bromine (Br) is 35 and its electronic configuration is [tex]\left[ {{\text{Ar}}} \right]\;3{d^{10}}4{s^2}4{p^5}[/tex]. When it gains an electron, it forms [tex]{\text{B}}{{\text{r}}^ - }[/tex] whose electronic configuration becomes [tex]\left[ {{\text{Ar}}} \right]\;3{d^{10}}4{s^2}4{p^6}[/tex].
The principal electron shell in [tex]{\text{B}}{{\text{r}}^ - }[/tex] is 4p. So its principal quantum number for the added electron in [tex]{\text{B}}{{\text{r}}^ - }[/tex] is 4.
The angular momentum quantum number for p orbital is 1. So the value of l for the added electron in [tex]{\text{B}}{{\text{r}}^ - }[/tex] is 1.
The value of magnetic quantum number for the electron in [tex]{\text{B}}{{\text{r}}^ - }[/tex] ranges from -1 to 1, including 0. But by convention this electron is added to [tex]{p_z}[/tex] orbital so the value of [tex]{m_l}[/tex] for the added electron in [tex]{\text{B}}{{\text{r}}^ - }[/tex] is 1.
The spin quantum number has two values, either [tex]+ \frac{1}{2}[/tex] or [tex]- \frac{1}{2}[/tex]. But the electron added in Br is the second electron being added to [tex]{p_z}[/tex] orbital so by convention, the value of [tex]{m_s}[/tex] for the added electron in [tex]{\text{B}}{{\text{r}}^-}[/tex] is [tex]{\mathbf{ - }}\frac{{\mathbf{1}}}{{\mathbf{2}}}[/tex].
The possible set of four quantum numbers for the electron gained by Br atom to form [tex]{\text{B}}{{\text{r}}^ - }[/tex] is n = 4, l = 1, [tex]{m_l} = 1[/tex] and [tex]{m_s} = - \frac{1}{2}[/tex].
Learn more:
1. Allowed values of [tex]{m_l}[/tex]: https://brainly.com/question/2920448
2. Calculation of volume of gas: https://brainly.com/question/3636135
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Structure of the atom
Keywords: quantum numbers, Br, Br-, electron, 35, electronic configuration, n, l, ml, ms, principal quantum number, angular momentum quantum number, electron spin quantum number, magnetic quantum number, n = 4, ml=1, ms=-1/2, l=1.
Which description below represents a hydrocarbon?
a. an organic compound that contains only carbon and hydrogen atoms
b. an organic compound that contains the maximum number of hydrogen atoms
c. an organic compound that contains fewer than the maximum number of hydrogen atoms
d. a group of compounds in which there is a constant increment of change in molecular structure from one compound in the series to the next?
Calculate the average molar bond enthalpy of the carbon-hydrogen bond in a ch4 molecule.
Answer:
415.825 kJ/mol.
Explanation:
Average enthalpy = [tex]\Delta H_f(CH_4)-4\Delta H_f(H)-\Delta H_f(C)[/tex]
Now, [tex]\Delta H_f(CH_4)=-74.6 kJ/mol[/tex]
[tex]\Delta H_f(H)=218 kJ/mol[/tex]
[tex]\Delta H_f(C)=716.7 kJ/mol[/tex]
( SOURCE INTERNET)
Putting all these values above.
We get,
Average enthalpy=-1663.3 kJ.
Therefore, averagemolar bond enthalpy= [tex]\dfrac{1663.3 }{4}=415.825\ kJ/mol.[/tex]
Hence, this is the required solution.
Why can't calcium hydroxide be written caoh2?
Which part of a watershed is the high point of land that separates adjacent watersheds?
A dividing ridge or watershed divide separates adjacent watersheds, like the Continental Divide in North America where rivers flow in opposite directions. Mount Elbert is the highest point on this divide, and Longs Peak is a notable mountain along it.
Explanation:The high point of land that separates adjacent watersheds is known as a dividing ridge or watershed divide. This feature determines the direction in which water flows across the landscape. In North America, the Continental Divide is a well-known example of a watershed divide where the line of the highest points marks the separation between rivers flowing eastward and westward. The highest point along this line is Mount Elbert, and a prominent mountain along the Continental Divide is Longs Peak.
Watershed divides can be found in various forms around the world, such as the Western Highlands in Europe, which provide natural separations for watersheds. The concept of watersheds is vital not only for understanding water flow but also for environmental management, as it affects the collection and distribution of water resources.
Will 1 gram of sugar or 1 gram of salt dissolve more quickly which one
Which atoms in the cfc molecule can destroy thousands of ozone molecules in the upper atmosphere?
What chemical property distinguishes a metal from a nonmetal?
Electronegativity is the chemical property that distinguishes a metal from a nonmetal. Metals have low electronegativity and tend to lose electrons, while nonmetals have high electronegativity and tend to gain electrons.
Explanation:The chemical property that distinguishes a metal from a nonmetal is electronegativity. Electronegativity is the tendency of an atom to attract electrons towards itself in a chemical bond. Metals generally have low electronegativity, which means they tend to lose electrons and form positive ions. Nonmetals, on the other hand, have high electronegativity and tend to gain electrons to form negative ions.
For example, consider sodium, a metal, and chlorine, a nonmetal. Sodium has a low electronegativity and readily loses an electron to become a sodium ion with a positive charge. Chlorine, on the other hand, has a high electronegativity and readily gains an electron to become a chloride ion with a negative charge.
Electronegativity is an important property for understanding the behavior and reactivity of elements, as it determines how atoms interact with each other in chemical reactions and the formation of compounds.
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The property that distinguishes a metal from a nonmetal is conductivity.
Explanation:The chemical property that distinguishes a metal from a nonmetal is conductivity.
Metals are good conductors of heat and electricity, while nonmetals are poor conductors. The ability of metals to conduct electricity is due to the presence of free or delocalized electrons that are able to move easily throughout the metal structure.
In contrast, nonmetals do not have these free electrons and therefore do not conduct electricity well.
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Explain why an atom may go through nuclear decay but another won't? use examples to support your answer.
True or false: if two atoms are in the same group they have the same number of electron shells.
Hey Brainly Student! Your answer us true, SUPRISE FACT ABOUT ATOMS!!: When you think of an atom what do you think of? Problily a small circle with afew rings around it right? Well, actually an atom doesnt look like that at all!! An atom looks sort of like the Solar System, and the little rights are like the rotation the planets spin in, also the little star like balls/dots dont actually go around the atom's center, but go in many diffrent places it can be far from the atom, or can be very close! An atom is unpredictable, so there is no correct answer to where the atom's little balls/dots will end up next. I hope this helped, and also hope you liked/loved the Fun-Fact!! Your fellow Brainly user, GalaxyGamingKitty
If a thermometer outside your classroom indicates a temperature of 61 degrees Fahrenheit, what is the temperature in degrees Celsius
Answer:That would be 16.1 degrees Celsius
If samples of silver and lead each had volumes equal to 1cm3 which sample would have the greater mass and what would the difference in the masses be
Density of Silver = 10.5 g / cm^3
Density of Lead = 11.34 g / cm^3
So the masses of each given a volume of 1 cm^3 is:
mass of Silver = 10.5 grams
mass of Lead = 11.34 grams
So we see that Lead has greater mass for similar volume.
The difference is:
11.34 – 10.5 = 0.84 grams
If a solution contains 1 x 106 hb molecules, how many o2 binding sites are available? if the solution of hb is 50% saturated with o2, how many binding sites are occupied by o2? if the hb solution is 23% saturated with o2, how many binding sites are occupied by o2?
Actually each molecule of Hb can bind four oxygen molecules. So given 1 x 10^6 Hb, so there are 4 x 10^6 binding sites available.
If only 50% of the Hb are bound, so this means that 2 x 10^6 binding sites are occupied by O2. However we must remember that hemoglobin binding is an all-or-nothing phenomenon. Meaning that each molecule of Hb binds four molecules of oxygen or zero at all.
If 23% is saturated, so the number of binding sites occupied is 0.92 x 10^6 binding sites or 9.2 x 10^5 binding sites.
What is the mass number of an oxygen isotope that has nine neutrons? what is the name of this isotope?
Isotopes are the forms of same element with same atomic number but different mass number due to different number of neutrons. The name of isotope of oxygen is Oxygen-17.
What is element?Element generally consist of atoms or we can atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same. Different element have different types of atoms.
Oxygen-16 has atomic number 8, which means number of electron is 8 , number of proton is 8 and number of neutron is also 8. If we increase the number of neutron by 1 that is 9 then the mass number of oxygen will be increased by 1 that is 17. Now the new element is oxygen-17 which is an isotope.
Therefore, the name of isotope of oxygen is Oxygen-17.
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Which of these was a characteristic of the rutherford model of the atom, but not the thomson model?
During combustion, chemical energy stored in fossil fuels is converted into _____ energy.
I do believe is Mechanical Energy
What is one characteristic of a sample of matter that indicates it is a pure substance?
A) It can be separated using by a physical means, such as filtering.
B) The components in a pure substance do not have to be in definite ratios.
C) If the composition of a sample varies, the sample is a pure substance.
D) If the composition of a sample is fixed, the sample is a pure substance.
Answer:
The answer is D) on USA Test prep
Explanation:
What is the concept of galactic recycling?
Acceleration is best defined as the rate of change of ____ of an object.
1. velocity
2. force
3. position
4. speed
What are the first ten elements of the periodic table?
When patterning a shotgun, what is a sufficient percentage of pellets within a 30-inch circle? at least 25% of the load, concentrated in the center at least 35% of the load, with even distribution at least 45% of the load, concentrated in the center at least 55% of the load, with even distribution?
When patterning a shotgun, a sufficient percentage of pellets within a 30-inch circle depends on the specific shooting requirements and preferences. However, a commonly recommended standard is to have at least 55% of the load with an even distribution within the 30-inch circle.
Having 55% of the load with an even distribution within the 30-inch circle ensures a dense and consistent pattern, increasing the chances of hitting the target effectively. It is important to note that individual shooting styles and the intended use of the shotgun may vary, so it is advisable to pattern the shotgun and adjust the load distribution accordingly for optimal performance.
Hence, at least 55% of the load, with even distribution, is prescribed.
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using hooke's law F spring equals K triangle X find the force needed to stretch a spring 2cm if it has an elastic constant of 3 N/cm
Data:
Hooke represented mathematically his theory with the equation:
F = K * x
On what:
F (elastic force) = ?
K (elastic constant) = 3 N/cm
x (deformation or elongation of the elastic medium) = 2cm
Solving:
[tex]F = K * x[/tex]
[tex]F = 3\:\dfrac{N}{\diagup\!\!\!\!\!\!cm}*2\:\diagup\!\!\!\!\!\!cm[/tex]
[tex]\boxed{\boxed{F = 6N}}\end{array}}\qquad\checkmark[/tex]
Answer:
C. 6 N
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The force needed to stretch the spring 2 cm is 6 N.
Hooke's Law states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position, and this force is expressed as [tex]\( F = k \Delta x \),[/tex] where [tex]\( F \)[/tex] is the force exerted by the spring, [tex]\( k \)[/tex] is the spring constant (elastic constant), and [tex]\( \Delta x \)[/tex] is the displacement from the spring's equilibrium position.
Given:
- The displacement [tex]\( \Delta x \)[/tex] is 2 cm.
- The spring constant [tex]\( k \)[/tex] is 3 N/cm.
Using Hooke's Law, we can calculate the force [tex]\( F \)[/tex] as follows:
[tex]\[ F = k \Delta x \] \[ F = (3 \, \text{N/cm}) \times (2 \, \text{cm}) \] \[ F = 6 \, \text{N} \][/tex]
Therefore, the force needed to stretch the spring 2 cm is 6 N.
What is the difference between applied and pure chemistry?
Will platinum (pt) metal react with a lead(ii) nitrate solution?
To answer this question, we must first look at the reactivity series table. From the table, we can see that those which are located above are the most reactive while those below are less reactive. Which means that elements cannot replace those elements which are above them.
From the series, platinum is below lead, hence there will be no reaction.
Answer:
No reaction
Final answer:
Platinum (Pt) does not react with a lead(II) nitrate solution because of its low reactivity, indicated by its position near the bottom of the activity series, which means it will not displace lead to form a new compound.
Explanation:
Platinum metal (Pt) is a highly inert metal and does not react easily with other substances. In the activity series, which is a list of metals arranged in order of their reactivity with acids and water, platinum is near the bottom, indicating very low reactivity. Considering the context provided about reactions of lead compounds, such as the reaction of lead(II) nitrate with potassium iodide to form a precipitate of lead(II) iodide, we can infer a similar lack of reactivity would apply to platinum in this case.
While lead(II) nitrate reacts with potassium iodide to form a precipitate of lead(II) iodide, such a double-replacement reaction is not likely to occur between platinum and lead(II) nitrate. The reason is that platinum will not displace lead from its salt because lead is above platinum in the activity series. Therefore, no reaction between Pt metal and lead(II) nitrate solution would be expected. Since the question appears to be about the reaction profiles of different metals, we have determined that there is no reactive interaction between these specific substances.