which one of the following ia a characteristic of a metal?

Answer: coefficient for aluminum is 2.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The skeletal equation is:

[tex]Al+FeS\rightarrow Al_2S_3+Fe[/tex]

The balanced equation for single displacement reaction is:

[tex]2Al+3FeS\rightarrow Al_2S_3+3Fe[/tex]

Thus the coefficient for aluminum when the chemical equation is balanced is 2.

The equation that represents the process of photosynthesis is: 

6CO2+12H2O+light->C6H12O6+6O2+6H2O

Photosynthesis is the process in plants to make their food. This involves the use carbon dioxide to react with water and make sugar or glucose as the main product and oxygen as a by-product. Since we are not given the mass of CO2 in this problem, we assume that we have 1 g of CO2 available. We calculate as follows:

1 g CO2 ( 1 mol CO2 / 44.01 g CO2 ) ( 12 mol H2O / 6 mol CO2 ) ( 18.02 g / 1 mol ) = 0.82 g of H2O is needed

However, if the amount given of CO2 is not one gram, then you can simply change the starting value in the calculation and solve for the mass of water needed.

Final answer:

Photosynthesis involves converting carbon dioxide and water into glucose and oxygen with sunlight. The balanced chemical equation indicates a 6:1 mole ratio of water to glucose. The mass of water consumed would be six times the molecular weight of water times the moles of glucose formed.

Explanation:

Photosynthesis is a fundamental biological process in which green plants use sunlight to convert carbon dioxide (CO₂) and water (H₂O) into glucose (C₆H₁₂O₆) and oxygen (O₂). The balanced chemical equation for photosynthesis is:

6CO₂ + 6H₂O + sunlight → C₆H₁₂O₆ + 6O₂

The question asks about the mass of water consumed in the reaction with carbon dioxide to form glucose during photosynthesis. To determine this, you need to know the mole ratio between water and glucose from the balanced equation, which is 6:1, meaning six molecules of water are needed to produce one molecule of glucose. To find the specific mass of water used, you would multiply the molecular weight of water (18.01528 g/mol) by the number of moles of water consumed (which is typically six times the moles of glucose formed).

Since the sample size is below 30, in this case we use the t statistic. The formula for t score is:

t = (x – u) / (σ / sqrt n)

where,

x = the level l = unknown

u = sample mean = 120 mg / dl

σ = standard deviation = 20 mg / dl

n = sample size or number of results = 5

Using the standard distribution tables for t, we can find the value of t given the probability (P = 0.15) and degrees of freedom (DOF).

t  = 1.036

Going back to the formula for t score:

1.036 = (x – 120) / (20 / sqrt 5)

x = 129.27 mg / dl = l

Final answer:

To find the glucose level such that the probability of the mean of 5 tests being above it is 0.15, we calculate the reduced standard deviation for the mean of the tests, find the corresponding z-score for a cumulative probability of 0.85, and apply the formula for the mean's distribution. The level l is found to be 129.267 mg/dl.

Explanation:

The question asks for the level l such that there is only a 0.15 probability that the mean glucose level of 5 test results falls above l, given that Sheila's glucose level after a sugary drink follows a normal distribution with a mean (μ) of 120 mg/dl and a standard deviation (σ) of 20 mg/dl.

To solve for l, we first need to recognize that the distribution of the mean of several test results (in this case, 5) will also be normally distributed, with the same mean but with a reduced standard deviation that is equal to the original standard deviation divided by the square root of the number of tests (σ/√n). For 5 tests, the new standard deviation (σnew) is 20/√5 = 8.9443 mg/dl.

The next step involves determining the z-score that corresponds to a probability of 0.85 (since 1 - 0.15 = 0.85) in the standard normal distribution. Consulting a z-table or using statistical software, we find that the z-score corresponding to 0.85 is approximately 1.036. Using the formula l = μ + z σnew, we calculate:

l = 120 + (1.036)(8.9443) = 120 + 9.267 = 129.267 mg/dl.

Therefore, the level l such that there is a probability of only 0.15 that the mean glucose level of 5 test results falls above l is 129.267 mg/dl.

The concentration of Na ion in the final solution is 0.66 M.

To calculate the concentration of Na ions in the solution, the moles of [tex]\rm Na_2SO_4[/tex] in the solution have been calculated.

Moles = molarity [tex]\times[/tex] volume (L)

The molarity of [tex]\rm Na_2SO_4[/tex] solution given is = 0.4

Volume of [tex]\rm Na_2SO_4[/tex] solution = 100 ml = 0.1 L.

Moles of [tex]\rm Na_2SO_4[/tex] = 0.4 [tex]\times[/tex] 0.1

Moles of [tex]\rm Na_2SO_4[/tex] = 0.04

The dissociation of [tex]\rm Na_2SO_4[/tex] will be as follows:

[tex]\rm Na_2SO_2\;\rightarrow\;2\;Na^+\;+\;SO_4^2^-[/tex]

1 mole of [tex]\rm Na_2SO_4[/tex] = 2 moles of Na ions.

0.04 moles of [tex]\rm Na_2SO_4[/tex] = 0.04 [tex]\times[/tex] 2

0.04 moles of [tex]\rm Na_2SO_4[/tex] = 0.08 moles of Na ions.

The moles of Na ions in NaCl solution will be:

Given, molarity of NaCl solution = 0.6 M

Volume of NaCl solution = 200 ml = 0.2 L.

Moles of Na ions in NaCl solution = 0.6 [tex]\times[/tex] 0.2

Moles of Na ions in NaCl solution = 0.12.

The dissociation of NaCl will be as follows:

[tex]\rm NaCl\;\rightarrow\;Na^+\;+\;Cl^-[/tex]

1 mole of NaCl = 1 mole of Na ions

0.12 moles of NaCl gives = 0.12 moles of Na ions.

Thus the total Na ions = Na ion in [tex]\rm Na_2SO_4[/tex] + Na ions in NaCl

Total moles of Na ions = 0.08 + 0.12

Total moles of Na ions = 0.2 moles.

The total volume of solution will be :

0.1 L [tex]\rm Na_2SO_4[/tex] + 0.2 L NaCl

= 0.3 L.

Concentration of Na ion in the final solution = [tex]\rm \dfrac{moles}{volume\;(L)}[/tex]

The concentration of Na ion in the final solution =  [tex]\rm \dfrac{0.2}{0.3}[/tex] M

Concentration of Na ion in the final solution = 0.66 M.

The concentration of Na ion in the final solution is 0.66 M.

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The solution would be like this for this specific problem:

Given:

66.0 g of carbon monoxide

In the given reaction moles of carbon are needed to produce 66.0 g of carbon monoxide is 2.35 moles.

Moles of any substance will be calculated as:

n = W/M, where

W = given mass

M = molar mass

Given chemical reaction is:

2C + O₂ → 2CO

Moles of 66g of CO = 66g / 28g/mol = 2.35 mol

2 moles of CO = produced by 2 moles of carbon

2.35 moles of CO = produced by 2.35 moles of carbon

Hence, required moles of carbon are 2.35 moles.

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There are various kind of elements that are present in periodic table. Some elements are metals, some are non metals, some are metalloids. Therefore, the activity series of metals compares the strength of reactivity of metals.

Metals are those elements which is hard, conduct electricity, ductile, lustrous and malleable.

Lets take property

1.Since metals have free electrons that's why they can conduct electricity

2. Since atoms in metals are very closely packed in a definite crystal solid. It is not brittle that is it can not be broken down easily.

3. It does not react with water.

4.It is denser than water hence it sink in water.

The activity series of metals compares the strength of reactivity of metals.

Therefore, the activity series of metals compares the strength of reactivity of metals.

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The periodic table can be used to recall the ionic charge of alkali metals, alkaline earth metals, and aluminum by understanding the trends in the table.

You can use the periodic table to recall the ionic charge of an alkali metal, alkaline earth metal, or aluminum by understanding the trends in the periodic table. The alkali metals (group 1) have a 1+ charge, alkaline earth metals (group 2) have a 2+ charge, and aluminum (group 13) has a 3+ charge. The ionic charges are determined by the number of electrons lost by the element.

For example, sodium, an alkali metal, has an atomic number of 11. It loses one electron and forms a cation with a 1+ charge. Calcium, an alkaline earth metal, has an atomic number of 20. It loses two electrons and forms a cation with a 2+ charge. Aluminum, in group 13, has an atomic number of 13. It loses three electrons and forms a cation with a 3+ charge.

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We can calculate for temperature by assuming the equation for ideal gas law:

P V = n R T

Where,

P = pressure = 1.80 atm

V = volume = 18.2 L

n = number of moles = 1.20 moles

R = gas constant = 0.08205746 L atm / mol K

Substituting to the given equation:

T = P V / n R

T = (1.8 atm * 18.2 L) / (1.2 moles * 0.08205746 L atm / mol K)

T = 332.70 K

We can convert K unit to ˚C unit by subtracting 273.15 to Kelvin, therefore

T = 59.55 ˚C

In Ba(NO3)2, the ratio of barium ions (Ba²⁺) to nitrate ions (NO₃⁻) is 1:2. This is because each formula unit of this compound contains one Ba²⁺ ion and two NO₃⁻ ions.

In a sample of solid Ba(NO3)2, the ratio of barium ions (Ba²⁺) to nitrate ions (NO₃⁻) is 1:2. This is because in each formula unit of Ba(NO3)2, there is one Ba²⁺ ion and two NO₃⁻ ions.

The subscript '2' after NO₃ in the formula indicates that two nitrate ions are associated with every one barium ion in this compound. Hence, for every single barium ion, there are two nitrate ions.

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Answer: The balanced chemical equation is written below.

Explanation:

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on the product side. These equations follow law of conservation of mass.

The chemical equation for the reaction of iron (III) oxide with carbon follows:

[tex]2Fe_2O_3(s)+3C(s)\rightarrow 3CO_2(g)+4Fe(l)[/tex]

By Stoichiometry of the reaction:

2 moles of solid iron (III) oxide reacts with 3 moles of pure carbon to produce 3 moles of carbon dioxide gas and 4 moles of molten iron

Hence, the balanced chemical equation is written above.

Final answer:

To determine the number of moles of NaOH from 20 grams, calculate the substance's molar mass (39.997 g/mol) and divide the given mass by the molar mass, resulting in 0.5001 moles of NaOH.

Explanation:

The question asks about calculating the moles of sodium hydroxide (NaOH) from its mass in grams. To find moles, one has to use the molar mass of the substance.

First, calculate the molar mass of NaOH:
Na (1 x 22.990 g/mol) + O (1 x 15.999 g/mol) + H (1 x 1.008 g/mol) = 39.997 g/mol.

Next, use this molar mass to find the number of moles:
Given: 20.0 g NaOH,
Desired: moles NaOH
Since 1 mole of NaOH weighs 39.997 g, then:
moles of NaOH = mass (20 g) ÷ molar mass (39.997 g/mol) = 0.5001 moles.

The balanced equation for the generation of sugar from sunlight water and CO₂ is

6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

carbon dioxide + water → sugar + oxygen

The process of photosynthesis occurs when the chlorophyll present in the leaves of plants absorb sunlight to make food in the presence of carbon dioxide (enters through the stomata of leaves) and water (absorbed from the roots). As a result of this reaction sugar and oxygen is formed. After that sugar is converted in to starch and oxygen is released into air.

Photosynthesis is the biological process that transforms sunlight, water, and CO2 into glucose and oxygen. The balanced equation for photosynthesis is 6CO₂ + 6H₂O + light energy --> C6H12O6 + 6O2. The process includes intermediate reactions that eventually form simple carbohydrate molecules.

The process that generates sugar from sunlight, water, and CO2 is called photosynthesis. The balanced chemical equation for photosynthesis is 6CO₂ + 6H₂O + light energy --> C6H12O6 + 6O2.

During photosynthesis, plants use sunlight energy to convert carbon dioxide gas (CO2) and water (H2O) into glucose (C6H12O6) and oxygen (O2). This process is complex and involves intermediate reactions and products.

Glyceraldehyde-3-phosphates, which are simple carbohydrate molecules that can be converted to glucose and various other sugar molecules, are formed during the course of the reaction.

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Nitrogen fertilizers are added to soil to provide readily available forms of nitrogen that plants can use. However, when these fertilizers enter aquatic ecosystems through runoff, they can cause eutrophication and harm aquatic fauna.

Nitrogen fertilizers are added to soil despite the dangers they pose to aquatic ecosystems because atmospheric nitrogen is not readily available for plants to use. Most plants require nitrogen in the form of nitrate or ammonium, which can be obtained from fertilizers. However, when these fertilizers enter aquatic ecosystems through runoff, they can cause eutrophication, leading to the overgrowth of microorganisms and the depletion of dissolved oxygen levels, which can be harmful to aquatic fauna.

A phase diagram is a temperature vs pressure plot from which the phase of a compound can be deduced under the given temperature and pressure conditions. The 3 equilibrium curves: Solid-Gas, Liquid-Gas and Solid-Liquid separate the compound into the three states of matter. The 3 states can however coexist at a unique point referred to as the triple point.

Based on the phase diagram for CO2 (which is readily available online), at -70 C and 5.5 atm, CO2 exist as a solid.

The pH range of acid is between 0-7 on pH scale while for base pH range is from 7-14. pH is a unitless quantity. The relationship between pH and hydrogen ions is pH=-log[H⁺].

pH is a measurement of amount of hydronium ion H₃O⁺ in a given sample. More the value of hydronium ion concentration, more will be the solution acidic. pH scale used to determine pH of a solution.

Mathematically the relation between hydrogen ion and pH is given as

pH=-log[concentration of hydrogen ion]

pH=-log[H⁺]

On subtracting pH from 14, we get pOH which measures the concentration of hydroxide ion in a given solution. pH depend on the temperature. At room temperature pH scale is between 0 to 14. pH of neutral solution is 7.

Therefore, the relationship  between pH and hydrogen ions is pH=-log[H⁺].

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Answer:

Moles of H2O produced = 13.8

Explanation:

Given:

Moles of KMnO4 reacted = 3.45

To determine:

moles of H2O produced

Explanation:

Given reaction:

2KMnO4 + 16HCl →2KCl + 2MnCl2 + 8H2O + 5Cl2

Based on the reaction stoichiometry:

2 moles of KMnO4 produces 8 moles of H2O

Therefore, moles of H2O produced when 3.45 moles of KMnO4 react is:

[tex]= \frac{3.45\ moles\ KMnO4 * 8\ moles\ H2O}{2\ moles\ KMnO4} = 13.8[/tex]

To solve this problem, we should recall that the change in enthalpy is calculated by subtracting the total enthalpy of the reactants from the total enthalpy of the products:

ΔH = Total H of products – Total H of reactants

You did not insert the table in this problem, therefore I will find other sources to find for the enthalpies of each compound.

ΔHf CO2 (g) = -393.5 kJ/mol

ΔHf CO (g) = -110.5 kJ/mol

ΔHf Fe2O3 (s) = -822.1 kJ/mol

ΔHf Fe(s) = 0.0 kJ/mol

Since the given enthalpies are still in kJ/mol, we have to multiply that with the number of moles in the formula. Therefore solving for ΔH:

ΔH = [3 mol ( − 393.5 kJ/mol) + 1 mol (0.0 kJ/mol)] − [3 mol ( − 110.5 kJ/mol) + 2 mol ( − 822.1 kJ/mol)]

ΔH = 795.2 kJ

Answer:

Calcium chloride

Explanation:

Colligative  property depends upon number of particles. The colligative property is independent of the nature of solute present in a solution.

More the number of particles larger the colligative property.

The following are colligative property

a) depression in freezing point

b) elevation in boiling point

c) relative lowering of vapor pressure

d) osmotic pressure

Thus if we wish to melt the we will take calcium chloride as it will give more number of ions per molecules as compared to sodium chloride.

The vapor pressure is EQUAL TO the outside air pressure.

Answer: Option (c) is the correct answer.

Explanation:

In an open system, the vapor pressure is equal the outside air pressure because there can be mass transfer or energy transfer from the atmosphere to the system as the system is open.

Whereas in a closed system there cannot be mass transfer or energy transfer from the system to the surrounding or vice versa.

Thus, we can conclude that option (c) is the correct answer.

To the prepared solution at  [tex]\rm 20^\circ C[/tex] the extra mass of x to be added to the solution at  [tex]\rm 30^\circ C[/tex] will be 4.44 g.

The complete question has given:

Solubility of x/100 g water at [tex]\rm 20^\circ C[/tex] = 11

Solubility of x/100 g water at [tex]\rm 30^\circ C[/tex] = 23

Now, since the saturated solution at [tex]\rm 20^\circ C[/tex]  will use 37 g of water. The mass of x in the saturated solution will be :

Mass of x =  [tex]\rm \dfrac{solubility\;of\;x\;\times\;mass\;of\;water}{100}[/tex]

Mass of x at [tex]\rm 20^\circ C[/tex] = [tex]\rm \dfrac{11\;\times\;37}{100}[/tex] g

Mass of x at [tex]\rm 20^\circ C[/tex]  = 4.07 g.

The mass of solute at [tex]\rm 30^\circ C[/tex] will be = [tex]\rm \dfrac{23\;\times\;37}{100}[/tex] g.

The mass of solute at[tex]\rm 30^\circ C[/tex]  = 8.51 g.

The extra mass of x to be added to the solution will be = 8.51 - 4.07 g.

The extra mass of x to be added to the solution will be 4.44 g.

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