What effect did printing with movable type have on people during the Renaissance?

Answer:

Electrolytes are considered ions when placed in a solution and allow for adequate conduction of particle charges.

Explanation:

Electrolytes are substances that, when are dissolved in solution, separates into electrical positive charges (cations) and electrical negative charges (anions) which are known as ions.

These ions have an adequate capacity to conduct particle charges and, therefore electricity.

Sodium, calcium, phosphate and potassium, are examples of electrolytes.  

Hence, the correct answer is:

Electrolytes are considered ions when placed in a solution and allow for adequate conduction of particle charges.

I hope it helps you!

Answer:

When flying the LNAV Approach, the missed approach point (MAP) would be indicated by reaching:

C. the RW30 waypoint.

Explanation:

The missed approach point (MAP) during an LNAV approach is indicated by reaching the RW30 waypoint.

When flying the LNAV approach, the missed approach point (MAP) would be indicated by reaching the RW30 waypoint. During an LNAV approach, which is a type of non-precision instrument approach procedure, pilots use lateral navigation to align with the runway. The MAP is typically defined by a waypoint and not by reaching a particular altitude or distance to the runway. Unlike precision approaches that can bring an aircraft to a lower minimum descent altitude or decision height based on a glideslope, LNAV approaches only provide lateral guidance and rely on predetermined waypoints to establish the MAP.

Answer:

u = 20.33 m/s

Explanation:

given,

mass of Toyota car = 950 Kg

mass of Cadillac = 2200 Kg

distance to stop = 4.8 m

coefficient of friction = 0.4

initial speed of the Toyota = ?

we know,

F = ma

and frictional foce

F = μ N = μ m g

where N is normal force

now equating both the equation

ma  = μ m g

 a = μ g

 a = 0.4 x 9.8

 a = 3.92 m/s²

using equation of motion

v² = u² + 2 a s

v² = 0² + 2 x 3.92 x 4.8

v = 6.13 m/s

above given velocity is the combined velocity of the Toyota and Cadillac

now, using conservation of momentum

m u = (M + m) v

950 x u = (2200+ 950) x 6.13

u = 20.33 m/s

The speed of Toyota before impact is equal to u = 20.33 m/s

Final answer:

The speed of the Toyota at the moment of impact is 0 m/s.

Explanation:

To find the speed of the Toyota at the moment of impact, we can use the principle of conservation of momentum. The momentum before the collision is equal to the momentum after the collision.

The momentum of an object is given by the product of its mass and velocity. So, we can write:

massT * velocityT = massC * velocityC

where massT and velocityT are the mass and velocity of the Toyota, and massC and velocityC are the mass and velocity of the Cadillac.

The mass of the Toyota is 950 kg, and the mass of the Cadillac is 2200 kg. The velocity of the Cadillac is 0 m/s because it is stopped. Solving for the velocity of the Toyota:

velocityT = (massC * velocityC) / massT

velocityT = (2200 kg * 0 m/s) / 950 kg = 0 m/s

Therefore, the speed of the Toyota at the moment of impact is 0 m/s.

Final answer:

The question pertains to the rotational kinetic energy of a rolling spherical object with non-uniform density and how it compares to the total kinetic energy using its moment of inertia.

Explanation:

The student is asking about the rotational kinetic energy of a spherical object with non-uniform density in comparison to its total kinetic energy. The given moment of inertia for the object is 0.59 M R2, where M is the mass, and R is the radius of the sphere. Using the formula for rotational kinetic energy, Krot = (1/2) I ω2, and the formula for translational kinetic energy, Ktrans = (1/2) m v2, we can find the energy components. However, because the spherical object rolls without slipping, there is a relationship between linear velocity (v) and angular velocity (ω) which is v = ωR. This allows us to compare the rotational kinetic energy to the total kinetic energy.

Answer:

d) An object that is speeding up always has a positive acceleration, regardless of the direction it travels.

Explanation:

a ) a) An object that is slowing down while traveling in the negative x-direction always has a positive acceleration.

It has negative acceleration in  the negative x-direction.

b) An object that is speeding up while traveling in the negative x-direction always has a positive acceleration.

It has a positive acceleration in the negative x-direction'

c) An object that is slowing down always has a negative acceleration, regardless of the direction it travels.

It has a positive  acceleration in opposite direction.

e ) An object that is slowing down always has a positive acceleration, regardless of the direction it travels.

It has a positive acceleration only in opposite direction .

Based on the information given, it should be noted that the y component of the induced electric field will be E = -Bv.

An induced electric field simply means a nonconversative field that is generated due to a changing magnetic field.

The force that acts on the charge moving with the velocity is given. In this case, the component of the induced electric field will be E = -Bv.

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Answer:

+ 3.0 m

Explanation:

displacement is shortest distance from fixed point O in particular direction . in diagram shortest distance at end from O is 3 m and it is right of O so +. HENCE +3.0m

Answer:

dr/dt = -2 cm/s.

Explanation:

The volume of a cone is given by:

[tex]V=\frac{1}{3} \pi r^{2}h[/tex] (1)

Let's take the derivative with respect to time in each side of (1).

[tex]\frac{dV}{dt}=\frac{1}{3} \pi \frac{d}{dt}(r^{2}h)=\frac{1}{3} \pi \left(2r\frac{dr}{dt}h+r^{2}\frac{dh}{dt} \right)[/tex] (2)

We know that:

We can calculate how fast is the radius changing using the above information.

[tex]0=\frac{1}{3} \pi \left( 2\cdot 4\cdot \frac{dr}{dt} \cdot 10 + 4^{2}\cdot 10)\right[/tex]  

Therefore dr/dt will be:

[tex]\frac{dr}{dt}=-\frac{160}{80}=-2 cm/s[/tex]

The minus signs means that r is decreasing.

I hope it helps you!

Answer:

I = 1.21x10^-5 A

Explanation:

You are missing the first part of the problem. This is an example, but it will give you the idea of how to solve yours with your data.

The first part is like this:

A      4.0 cm  diameter parallel plate capacitor has a  0.44 m  m    gap. What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000 V/s?

Now with this, we can solve the problem.

In order to do this, we need to use the following expression:

q = CV (1)

Where:

C: Capacitance of a parellel capacitor (in Faraday)

q: charge of plate or capacitor (In coulombs)

V: voltage in Volts.

However, we need is the current, and we have data of potential difference, so, all we have to do is divide the expression between time so:

q/t = CV/t

And the current is q/t, thus:

I = C * V/t (2)

And finally, Capacitance C with two plates of area A separated by a distance d is:

C = Eo*A/d (3)

Where:

Eo = constant equals to 8.85x10^-12 F/m.

A = Area of the plate, in this case, πr²

d = gap of the capacitor.

Let's calculate first the Capacitance using equation (3):

C = 8.85x10^-12 * π * (0.04/2)² / 0.00046 = 2.42x10^-11 F

Now, it's time to use equation (2) and solve for I:

I = 2.42x10^-11 * 500,000

I = 1.21x10^-5 A

Answer:

A = 2 cm ,   λ = 8 cm

Explanation:

The amplitude of a wave is the maximum height it has, in this case the height is measured by the vertical ruler,

We are told the balance point is in the reading of 5 cm, that the maximum reading is 3 cm and the Minimum reading is 7 cm. Therefore, the distance from the ends of the ridge to the point of equilibrium is

          d = 7-5 = 2 cm

          d = 5-3 = 2 cm

          A = 2 cm

The wavelength is the minimum horizontal distance for which the wave is repeated, that is measured by the horizontal ruler.

The initial reading for 4 cm and the final reading for 8 cm, this distance corresponds to a crest of the wave, the complete wave is formed by two crests whereby the wavelength is twice this value

          Δx = 8-4 = 4 cm

          λ = 2 Δx

          λ = 8 cm

The amplitude of the wave is approximately [tex]2cm[/tex], measured from the equilibrium to the crest or trough. The wavelength of the wave is approximately [tex]8cm[/tex].

To determine the wavelength and amplitude of the given wave, we need to analyze the provided measurements.

The crest rises from the equilibrium position of [tex]5 cm `[/tex] to just before [tex]3 cm[/tex] , giving an amplitude measurement of approximately [tex]2 cm (5 cm - 3 cm)[/tex] .

Similarly, the trough falls from the equilibrium of [tex]5 cm[/tex] to just before [tex]7 cm[/tex], again giving a vertical displacement of approximately [tex]2 cm (7 cm - 5 cm)[/tex].

The horizontal distance from the start of the first crest to the start of the next crest should be measured. According to the provided data, the first crest aligns from [tex]0[/tex]  to just under [tex]4 cm[/tex] , and the next crest starts just under [tex]8 cm[/tex].

The wavelength is the horizontal distance covering one complete cycle, measuring just less than [tex]8 cm[/tex]. Therefore, the wavelength is approximately [tex]8 cm[/tex] .

Hence,

Answer:

[tex]v_{f}[/tex] = 0  miles/h

Explanation:

This exercise should be resolved with the moment. The system is formed by the two cars. Let's write the moment

Initial. Before the crash

           p₀ = m v₁ - m v₂

The sign is because they go in the opposite direction

Final. After the crash

          [tex]p_{f}[/tex] = (m + m) [tex]v_{f}[/tex]

The moment is preserved

         p₀ = [tex]p_{f}[/tex]

         m v₁- m v₂ = 2m [tex]v_{f}[/tex]

         [tex]v_{f}[/tex] = m / 2m (v₁-v₂)

But the speed of the cars is the same v1 = v2 = 50 liters / h

       [tex]v_{f}[/tex] = 0

so the two faces do not move after the crash

Answer:

T=2.94*10^-10  N/m.

Explanation:

Biologists think that some spiders "tune" strands of their web to give enhanced response at frequencies corresponding to those at which desirable prey might struggle. Orb spider web silk has a typical diameter of 20μm, and spider silk has a density of 1300 kg/m³.

To have a fundamental frequency at 150Hz , to what tension must a spider adjust a 14cm -long strand of silk?

l=length of the spider silk, 14cm

velocity of wave = √(T/μ)          

where T = tension and

μ = mass per unit length)

λ/2=l

for fundamental frequency λ/2 =14cm    

 (λ= wavelength of standing wave;  as there will be no node

   except the endpoints of silk strand)

               λ = 28 cm = 0.28 m

and since frequency * wavelength = speed of wave. we have,

                  150 * 0.28 = √(T/μ)                                        ..................(#)

now μ = mass/length = [volume * density]/length = [(length*area) * density] / length = area * density

         = [π * (10 * 10^(-6))²] * 1300  = 13π * 10^(-8).

now putting this in equation (#) we get

    150 * 0.28 = √(T/[13π * 10^(-8)]).

thus T = [13π * 10^(-8)] * (42)²     =  

2.94*10^-10  N/m.

Answer:

The number of bright fringes per unit width on the screen is, [tex]x=\dfrac{\lambda D}{d}[/tex]      

Explanation:

If d is the separation between slits, D is the distance between the slit and the screen and [tex]\lambda[/tex] is the wavelength of the light. Let x is the  number of bright fringes per unit width on the screen is given by :

[tex]x=\dfrac{n\lambda D}{d}[/tex]

[tex]\lambda[/tex] is the wavelength

n is the order

If n = 1,

[tex]x=\dfrac{\lambda D}{d}[/tex]

So, the the number of bright fringes per unit width on the screen is [tex]\dfrac{\lambda D}{d}[/tex]. Hence, the correct option is (B).

Final answer:

The number of bright fringes per unit width in a Young's double-slit experiment is given by the reciprocal of the fringe spacing, which is d/(Dλ), corresponding to answer choice E.

Explanation:

In a Young's double-slit experiment, to find the number of bright fringes per unit width on the screen, we consider the separation between the slits (d), the distance from the slits to the screen (D), and the wavelength of light used (λ). The distance between adjacent bright fringes, or fringe spacing, is given by Δy = Dλ/d. From this relation, the number of bright fringes per unit width can be obtained by taking the reciprocal of the fringe spacing, which implies 1/Δy = d/(Dλ).

Therefore, the correct formula to calculate the number of bright fringes per unit width on the screen is the reciprocal of Δy, which is d/(Dλ), matching answer choice E.

Answer:

1.81779 m/s in the same direction as the car

0.43220 m/s in the same direction

Explanation:

[tex]m_1[/tex] = Mass of van= 1055 kg

[tex]m_2[/tex] = Mass of car = 715 kg

[tex]u_1[/tex] = Initial Velocity of van = 0 m/s

[tex]u_2[/tex] = Initial Velocity of car = 2.25 m/s

[tex]v_1[/tex] = Final Velocity of van

[tex]v_2[/tex] = Final Velocity of car

As momentum and Energy is conserved

[tex]m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}[/tex]

[tex]{\tfrac {1}{2}}m_{1}u_{1}^{2}+{\tfrac {1}{2}}m_{2}u_{2}^{2}={\tfrac {1}{2}}m_{1}v_{1}^{2}+{\tfrac {1}{2}}m_{2}v_{2}^{2}[/tex]

From the two equations we get

[tex]v_{1}=\dfrac{m_1-m_2}{m_1+m_2}u_{1}+\dfrac{2m_2}{m_1+m_2}u_2\\\Rightarrow v_1=\dfrac{1055-715}{1055+715}\times 0+\dfrac{2\times 715}{1055+715}\times 2.25\\\Rightarrow v_1=1.81779\ m/s[/tex]

The final velocity of the van is 1.81779 m/s in the same direction as the car

[tex]v_{2}=\dfrac{2m_1}{m_1+m_2}u_{1}+\dfrac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\dfrac{2\times 1055}{1055+715}\times 0+\dfrac{1055-715}{1055+715}\times 2.25\\\Rightarrow v_2=0.43220\ m/s[/tex]

The final velocity of the car is 0.43220 m/s in the same direction

Answer:

(a). The final velocity of the car is -0.432 m/s.

(b). The final velocity of the van is 1.82 m/s.

Explanation:

Given that,

Mass of van = 1055 kg

Mass of car = 715 kg

Initial velocity of car= 2.25 m/s

(a). We need to calculate the final velocity of the car

Using formula of velocity

[tex]v_{c}=\dfrac{m_{v}-m_{c}}{m_{v}+m_{c}}\times u_{c}[/tex]

Put the value into the formula

[tex]v_{c}=\dfrac{715-1055}{715+1055}\times2.25[/tex]

[tex]v_{c}=-0.432\ m/s[/tex]

(b). We need to calculate the final velocity of the van

Using formula of velocity

[tex]v_{v}=\dfrac{2m_{v}}{m_{v}+m_{c}}\times u_{c}[/tex]

Put the value into the formula

[tex]v_{v}=\dfrac{2\times715}{715+1055}\times2.25[/tex]

[tex]v_{v}=1.82\ m/s[/tex]

Hence, (a). The final velocity of the car is -0.432 m/s.

(b). The final velocity of the van is 1.82 m/s.

Answer:

d) kinetic energy transformed to mechanical energy

Explanation:

Wind energy comes from its movement, so kinetic energy

         Em = K = ½ m v²2

This energy spins the mill aspadle that this movement of the rotor within a magnetic field creates electricity in accordance with Faraday's law.

Consequently, from the above we should make a graph of the wind speed (kinetic energy) according to the electricity produced

The correct answer is d

kinetic energy transformed to mechanical energy this best completes the chart. Hence option D is correct.

Kinetic energy is the energy associated with a motion of a body. When a body is in motion having mass m then it has kinetic energy. Kinetic energy is denoted by K or T. it is expressed in joules. Kinetic energy is given by,

K = 1/2 mv²

Hence an object having zero mass or zero velocity have zero kinetic energy.

In line with Faraday's law, when the mill asp rotates under the influence of this energy, electricity is generated.

In light of the foregoing, we should create a graph showing the wind speed (kinetic energy) in relation to the power generated.

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Answer:

D. Graphing the force as a function of distance and calculating the area under the curve.

Explanation:

Answer:

The correct option is (D). "Graphing the force as a function of distance and calculating the area under the curve"

Explanation:

1) As we know from the definition of Work done which is Work = Force × Displacement. Time doesn't have any use in the mentioned equation and thus the stop watch is of no use to us.

2) Using the meter stick, we can measure the distance for which the block is pulled horizontally i.e "Displacement"

3) Using the spring scale, we can calculate the "Force" applied on the block of wood to move it horizontally.

4) For example, lets say that for a constant force of 4 Newtons, the wooden block is pulled horizontally 4 meters. Plotting Force vs Displacement on a graph would yield a horizontal line as shown in the attachment. Area under the F vs D graph will give us the total work done.

Answer:

a)W = 116800 J

b)KE=132496 J

c)P=4154.93 W

Explanation:

Given that

m= 800 kg/min

h= 14.6 m

v= 18.2 m/s

a)

Work done required ,W= m g h

h=height of the well

m=mass

W= 800 x 14.6 x 10                 ( take g= 10 m/s²)

W = 116800 J

b)

kinetic energy = KE

[tex]KE=\dfrac{1}{2}mv^2[/tex]

m=mass

v=velocity

[tex]KE=\dfrac{1}{2}\times 800\times 18.2^2[/tex]

KE=132496 J

c)

Pump power given as

[tex]P=\dfrac{W'}{t}[/tex]

W'=Total work done

t=time

[tex]P=\dfrac{116800+132496}{60}[/tex]

P=4154.93 W

The work done per minute in lifting the water is 114,464 J. The kinetic energy given to the water when it is ejected is 132,488 J. The power output of the pump is 4116.2 W.

The subject of this question is Physics, specifically the topic of work, energy, and power.

To calculate the work done in lifting the water, we can use the formula:

Work = Force × Distance

The force required to lift the water can be calculated using the formula:

Force = Mass × Gravity

(a) To find the work done per minute in lifting the water, we multiply the weight of the water by the height it is lifted. The weight of the water is mass times gravity, which is

Force =800 kg * 9.8 m/s^2 = 7840 N.

So, the work done is 7840 N * 14.6 m = 114,464 J.

(b) To find the kinetic energy given to the water when it is ejected, we use the formula for kinetic energy, which is 1/2 * mass * speed^2.

So, the kinetic energy = 1/2 * 800 kg * (18.2 m/s)^2

                                     = 132,488 J.

(c) The power output of the pump is the total work done per minute divided by the time, which is

Power =(114,464 J + 132,488 J) / 60 s

           = 4116.2 W.

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Answer:

B. Wave-like way with a pattern that is wave-like

Explanation:

The double slit experiment when performed with electromagnetic waves, gives a pattern of light lines and dark areas, equally spaced.

In the case of electrons we must use Broglie's duality principle that states that all things have the characteristics of particles and waves together. The characteristic observed in a given experiment depends on the type of experiment, using the relationship

          p = h /λ

Where p is the amount of motion of the particle and λ the wavelength associated with this particle

In consequence of the previous one to the screen it should arrive as a wave with a wave type pattern

Let's review the answer.

A) False. The pattern is wave type

B) True. The whole process is with undulating characteristics

C) False. A wave arrives

D) False. A wave arrives

Answer:

d=1.49×1011m

Explanation:

Velocity is defined as the rate of travel, and can be found using the distance formula.

velocity=distancetime

Rearranging this formula we can solve for distance given velocity and time of travel.

d=vt

We are given velocity and time, and so can solve for distance, but if we plug in the values given;

d=(3.00×108m/s)(8.3minutes)

We can see that the units do not match up. Since seconds are the SI unit for time, we will need to convert 8.3 minutes to seconds.

t=(8.3minutes)(60seconds/minute)=(498s)

Now our units work out and we can solve for distance.

= 15.85

(8.3 min)/(1 AU) = (T)/(1.52 AU)

(8.3 min)x(1.52 AU) = (T x 1 AU)

T = (8.3 min x 1.52 AU) / (1 AU)

T = 12.62 minutes

Answer:

a. Technician A

Explanation:

Technician A says that a MAF sensor is a high-authority sensor and is responsible for determining the fuel needs of the engine based on the measured amount of air entering the engine. Technician B says that a cold wire MAF sensor uses the electronics in the sensor itself to heat a wire 20°C below the temperature of the air entering the engine. Who is right

MAF wich stands for  mass airflow sensor determines the mass of air flowing into the engine's air intake system. ... , the wire cools When air flows past the wire, decreasing its resistance, thereby more current flows through the circuit. When the MAf goes bad, it can not sense the amount of air intake into the engine.

The ratio of the low temperature to the high temperature in the Carnot engine, given that the real engine's efficiency is 55% of a Carnot engine's efficiency, is calculated to be 0.3535.

The question involves thermodynamics and specifically deals with the operation and efficiency of a Carnot engine.

The given heat engine absorbs 450 J of heat from the high-temperature reservoir and expels 290 J to the low-temperature reservoir. The efficiency (efficiency) of this engine is given as 55% of a Carnot engine's efficiency. Using the first law of thermodynamics, wecan calculate the work done (W) by the engine:

W = Qh - Qc = 450 J - 290 J = 160 J.

The efficiency of the engine is the ratio of the work done to the heat absorbed:

efficiency = W / Qh = 160 J / 450 J = 0.3556, or 35.56%.

Now, the efficiency of a Carnot engine is defined as:

efficiencyCarnot = 1 - (Tc / Th).

The problem states that the engine's efficiency is 55% of a Carnot engine's efficiency, which means:

0.3556 = 0.55 * efficiencyCarnot

From this equation, we can solve for efficiencyCarnot and then use it to calculate the ratio of the low temperature to the high temperature in the Carnot engine:

efficiencyCarnot = 0.3556 / 0.55

efficiencyCarnot = 0.6465, or 64.65%

Thus:

0.6465 = 1 - (Tc / Th)

Tc / Th = 1 - 0.6465 = 0.3535.

Therefore, the ratio of the low temperature to the high temperature in the Carnot engine is 0.3535.

The ratio of the low temperature to the high temperature in the Carnot engine is  [tex]\( \frac{1}{3} \)[/tex].

The correct ratio of the low temperature to the high temperature in the Carnot engine is given by:

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = 1 - \frac{W_{\text{actual}}}{Q_{\text{in}}} \cdot \frac{1}{\eta_{\text{Carnot}}} \][/tex]

where [tex]\( W_{\text{actual}} \)[/tex] is the work done by the actual engine, [tex]\( Q_{\text{in}} \)[/tex] is the heat absorbed from the high-temperature reservoir, and [tex]\( \eta_{\text{Carnot}} \)[/tex]  is the efficiency of the Carnot engine.

First, we calculate the actual efficiency of the given heat engine using the provided values:

[tex]\[ W_{\text{actual}} = Q_{\text{in}} - Q_{\text{out}} \][/tex]

[tex]\[ W_{\text{actual}} = 450 \, \text{J} - 290 \, \text{J} \][/tex]

[tex]\[ W_{\text{actual}} = 160 \, \text{J} \][/tex]

The actual efficiency [tex]\( \eta_{\text{actual}} \)[/tex] is then:

[tex]\[ \eta_{\text{actual}} = \frac{W_{\text{actual}}}{Q_{\text{in}}} \][/tex]

[tex]\[ \eta_{\text{actual}} = \frac{160 \, \text{J}}{450 \, \text{J}} \][/tex]

[tex]\[ \eta_{\text{actual}} = \frac{16}{45} \][/tex]

Given that the efficiency of the actual engine is 55% of the efficiency of a Carnot engine operating between the same two temperatures, we can write:

[tex]\[ \eta_{\text{actual}} = 0.55 \cdot \eta_{\text{Carnot}} \][/tex]

The efficiency of a Carnot engine is given by:

[tex]\[ \eta_{\text{Carnot}} = 1 - \frac{T_{\text{low}}}{T_{\text{high}}} \][/tex]

Combining the two equations, we get:

[tex]\[ \frac{16}{45} = 0.55 \left( 1 - \frac{T_{\text{low}}}{T_{\text{high}}} \right) \][/tex]

Solving for [tex]\( \frac{T_{\text{low}}}{T_{\text{high}}} \)[/tex]:

[tex]\[ \frac{16}{45} = 0.55 - 0.55 \cdot \frac{T_{\text{low}}}{T_{\text{high}}} \][/tex]

[tex]\[ 0.55 \cdot \frac{T_{\text{low}}}{T_{\text{high}}} = 0.55 - \frac{16}{45} \][/tex]

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = \frac{0.55 - \frac{16}{45}}{0.55} \][/tex]

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = \frac{0.55 \cdot \frac{45}{45} - \frac{16}{45}}{0.55} \][/tex]

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = \frac{\frac{24.75}{45} - \frac{16}{45}}{0.55} \][/tex]

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = \frac{\frac{8.75}{45}}{0.55} \][/tex]

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = \frac{8.75}{45 \cdot 0.55} \][/tex]

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = \frac{8.75}{24.75} \][/tex]

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = \frac{1}{3} \][/tex]

Answer:

B. increasing the temperature of the atmosphere

Explanation:

Generally, atmospheric loss can be defined as the loss of the gases in the atmosphere to outer space. This process usually occur through either thermal escape or non-thermal escape. Atmospheric loss of gases to outer space by thermal escape occurs when the molecular velocity due to thermal energy is considerably high. One of the factors that can lead to increase in thermal energy and ultimately increase in atmospheric loss is increase in the temperature of the atmosphere. Therefore, the correct answer is option B.

Explanation:

The infographic lacks a possible solution to the issue, but it does explain where plastics emerge from, how they get into the marine, what they will do to marine wildlife, and how they will be removed to eliminate ocean plastic waste.

According to estimates reported in 2015 in the journal Science, between 4.8 million and 12.7 million tons of plastic enter the ocean every year. As large, identifiable items or as micro plastics, plastic can enter the ocean-pieces of less than five millimeters in length.

Answer:

TRUE

Explanation:

It is TRUE that pedestrians, bicyclists and slow-moving vehicles are not allowed on expressways because expressways have minimum speed limit requirements that these travelers cannot reach. This minimum limit of speed varies country to country.

In America, the minimum speed limit in Rural Areas is 40 mph (miles per hour) i.e. 65km/h (kilometer per hour) while in Urban Areas it is 55mph i.e. 90km/h which cannot be met by pedestrians and by-cycles easily.

The work done by air resistance on a skydiver with a constant velocity is -2.93 × 10⁵ J, as the air resistance force is equal but opposite to the gravitational force, and work is calculated as force times distance in the direction of the force.

The work done by a nonconservative force such as air resistance can be calculated as the product of the force and the distance over which it acts, in the direction of the force. Since the skydiver is falling with a constant velocity, the force of air resistance must be equal and opposite to the gravitational force acting on the skydiver, resulting in no net force and therefore no acceleration. The work done by air resistance is thus equal to the gravitational force times the distance fallen, with a negative sign because the force of air resistance acts in the opposite direction to the displacement.

First, we need to calculate the gravitational force acting on the skydiver:

F_gravity = mass × acceleration due to gravity

F_gravity = 92.0 kg × 9.8 m/s²

F_gravity = 901.6 N

Now, we can calculate the work done by air resistance:

Work = force × distance × cos(ϸ)

Since the angle (ϸ) between the force of air resistance and the direction of displacement is 180 degrees (opposite directions), cos(ϸ) is -1. Therefore:

Work = -901.6 N × 325 m × -1

Work = -2.93 × 10⁵ J

The correct answer is D) -2.93 times 10⁵ J, which means the work done by air resistance is negative because it acts in the direction opposite to the displacement.

Answer:C. 10N

Explanation:

The applied force needed to maintain a constant velocity is 10N. This is because the moving force acting on the body will always be equal to the frictional force if the velocity of the body is constant.

But note that this is not the case if the body ia accelerating. If the body is accelerating then the frictional force will not be able to overcome the moving force acting on the body and such the moving force will be greater than the frictional force in that regards.

The applied force needed to maintain a constant velocity is 10 N.

The given parameters;

The net horizontal force on the object is calculated by applying Newton's second law of motion as shown below;

∑F = ma

[tex]F- F_k = ma[/tex]

where;

At constant velocity, the acceleration of the object is zero.

[tex]F-F_k = m(0)\\\\F-F_k = 0\\\\F= F_k\\\\F = 10 \ N[/tex]

Thus, the applied force needed to maintain a constant velocity is 10 N.

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Answer:3-Sonar

Explanation:

Sonar system is used to detect the under water objects by using the deflection of sound waves.

Sonar is an acronym of Sound navigation ranging.Two types of sonar sets are used for working: active and passive. The active sonar system pushes out sound signals called pings, and then absorbs the return sound echo. Passive sound sets obtain sound echoes without transmitting their actual sound signals. Submarines are using sonar to track other vessels.    

Final answer:

The speed of sound in the metal is 444.44 m/s.

Explanation:

To determine the speed of sound in the metal, we can use the information given and the speed of sound in air. The pulse traveling through the metal arrives 9ms earlier than the pulse traveling through air. From this, we can calculate the time difference it takes for the pulses to travel through the length of the metal bar. The speed of sound in air is given as 343 m/s. We can use the formula: speed = distance/time. Rearranging the formula, we have: time = distance/speed. As the distance is given as 4.00 m and the time difference is given as 9 ms (0.009 s), we can calculate the speed of sound in the metal by dividing the distance by the time difference: speed = 4.00 m / 0.009 s = 444.44 m/s.

Answer:

a. P1=200235pa

b. h=26.91m

Explanation:

The main water line enters a house on the first floor. The line has a gauge pressure of 2.64 x 105 Pa.

(a) A faucet on the second floor, 6.50 m above the first floor is turned off. What is the gauge pressure at this faucet?

(b) How high could a faucet be before no water would flow from it, even if the faucet were open?

pressure is the force per unit area.

force is that which tends to change a boy's state of rest or uniform motion in a straight line

rho stands for the density of water which is 1000kg/m3

p2=p1+rhogh

p1=p2-rhogh

the gauge pressure at 6.5m

will be:

2.64 x 10^5 Pa-100kg/m3*9.81*6.5

P1=200235pa

b. How high could a faucet be before no water would flow from it, even if the faucet were open?

b.h=p2-p1/(grho)

h=2.64 x 105 Pa/(1000*9.81)

h=26.91m

To find the gauge pressure and height limit of a faucet on the second floor compared to the first floor in a house with a main water line.

(a) To find the gauge pressure at the faucet on the second floor, we can use the equation: P2 = P1 + ρgh. Here, P1 = 2.64 x 105 Pa, ρ is the density of water, g is the acceleration due to gravity, and h is the height difference between the first and second floor. Plugging in the values, we get: P2 = 2.64 x 105 + (1000 kg/m3) x (9.8 m/s2) x 6.50 m. Solving for P2 gives us the gauge pressure at the faucet on the second floor.

(b) To find the maximum height a faucet could be before no water would flow from it, we can equate the gauge pressure to zero in the equation: P2 = P1 + ρgh. Solving for h, we can find the maximum height.

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Answer:

False

Explanation:

A 24 year old motorcycle driver would not be required to wear protective eyewear when riding in Florida,This is a False statement.

The law is all riders would have to wear protective eyewear when riding in Florida.