What are the limitations of determining a function’s average rate of change by examining the function’s graph?

Answers

Answer 1
When using the graph of a function, it is possible to find the average rate of change over only those intervals whose endpoints are visible on the graph. you can also get only approximate values of f(x) from the graph.
Answer 2
Final answer:

The limitations of determining a function's average rate of change by examining the function's graph include incomplete information, the need for tangent lines, and limited interval-specific data.

Explanation:

When determining a function's average rate of change by examining the function's graph, there are several limitations to consider.

The graph may not provide enough information about the function's behavior between plotted points, leading to an inaccurate estimation of the average rate of change.A curved graph may require the use of tangent lines to calculate the instantaneous rate of change, which may not accurately represent the average rate of change.The graph may not show the function's behavior in different intervals or at certain points, making it difficult to determine the average rate of change for specific intervals or points.

These limitations highlight the importance of understanding the limitations of graph analysis and considering alternative methods, such as calculus, to accurately calculate the average rate of change of a function.


Related Questions

You are interviewing an applicant for a sales agent position in your company. Based on the company’s record, almost every company sales agent makes a total revenue of 150x-x² pesos for selling x products in a week. If the applicant confidently assures you that he/she can easily make ₱10,000 weekly revenue, how many products should he/she sell to meet this quota?

Answers

Using the revenue model for most company sales agents y = 150x - x^2, and the weekly revenue of $10,000 assured by the applicant, you get:

150x - x^2 = 10,000

From which you can solve for x:

x^2 - 150x + 10,000 = 0

When you use the quadratic equation you find that the equation does not have real solution driving to the conclusion that the agent is not tellling the true.

Chase makes 2 gallons of soup for a dinner party. He serves 10 cups of soup to his guests. How many cups of soup will be have left over?

Answers

2 gallons equal 32 cups

32-10= 22

22 cups will be left
He will have 22 cups left. 2 gallons = 32 cups minus 10.

Kenya plans to make a down payment plus monthly payments in order to buy a motorcycle. At one dealer she would pay $2,500 down and $150 each month. At another dealer, she would pay $3,000 down and $125 each month. After how many months would the total amount paid be the same for both dealers? What would that amount be?

Answers

Let us say that the total amount paid in the first dealer is P1 and the total amount paid to the second dealer is P2. So that:

P1 = 2500 + 150 t

P2 = 3000 + 125 t

Where t is the total number of months

Now we are asked when the total amount paid would be equal for the two dealers, this means P1 = P2, therefore equating the two:

2500 + 150 t = 3000 + 125 t

25 t = 500

t = 20 months

 

Therefore the total amount paid for both dealers would be equal after 20 months.

10 employees in an office were absent. Of these absentees constitutes 25% of the employees, what is the total number of employees?

Answers

25% is 1/4, it looks like 10*4 = 40 is the total number, right?

Bradley is returning home from a place that is 2 kilometers away. The function y = 2,000 − 90x represents Bradley's distance from home in meters, y, in relation to the number of minutes he walks, x. Which statements about this function are true?

Answers

Final answer:

The function y = 2,000 - 90x shows Bradley's distance from home decreases by 90 meters for every minute walked, starting from 2,000 meters away. The graph of this equation is a straight line with a negative slope, indicating constant speed.

Explanation:

The equation y = 2,000 - 90x represents Bradley's distance from home in meters, y, as a function of the time x in minutes that he walks. This equation is a linear function where the initial value 2,000 meters represents the distance from home at the start, and -90 meters/minute is the rate at which this distance decreases as Bradley walks home. As time increases by 1 minute, the distance from home decreases by 90 meters. This relationship shows that Bradley travels at a constant speed since the slope of the line representing the equation (which is the rate of change of distance with respect to time) is constant.

If we graph this function, we would get a straight line that starts at 2,000 meters on the y-axis when t=0 and has a negative slope of 90. Therefore, the graph shows that as time passes, Bradley gets closer to home at a steady pace. This also reflects that the total distance Bradley would walk is 2,000 meters, and the time it would take for him to return home can be found by setting the function equal to zero and solving for x.

Which of the following rational functions is graphed below?

Answers

I can't see all the answers. Could u take a better pic so I could help because I'd love to!

The solution is, Option A. is correct.

F(x) = 1/ (x-1)(x+4)

What is rational fraction?

A rational fraction is an algebraic fraction such that both the numerator and denominator are polynomials.

Here, we have,

a graph is given .

We need to find which of the given rational functions is graphed in image.

On x-axis, 1 unit = 2 units

Clearly, we can see the graph is not defined at point x = - 4 and at x = 1.

Corresponding to x = - 4, factor is (x+4) .

Corresponding to x = 1, factor is (x-1) .

So, this graph is of the rational fraction

F(x) = 1/ (x-1)(x+4)

Hence, Option A. is correct.

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what is the value of the fourth term in a geometric sequence for which a1=15 and r=1/3
express your answer as a fraction

Answers

nth term = a1r^(n-1)

4th term =  15* (1/3)^3  =  15/27 =  5/9

Answer:  The required fourth term in the given geometric sequence is [tex]\dfrac{5}{9}.[/tex]  

Step-by-step explanation:  We are given to find the fourth term of a geometric sequence with the following first term and common ratio :

[tex]a=15,~~r=\dfrac{1}{3}.[/tex]

We know that

the nth term of a geometric sequence with first term a and common ratio r is given by

[tex]a_n=ar^{n-1}.[/tex]

Therefore, the forth term of the given geometric sequence is

[tex]a_4=ar^{4-1}=ar^3=15\times\left(\dfrac{1}{3}\right)^3=15\times\dfrac{1}{27}=\dfrac{5}{9}.[/tex]

Thus, the required fourth term in the given geometric sequence is [tex]\dfrac{5}{9}.[/tex]  

Four times the sum of a number and 15 is at least 120. Find all possible solutions for x

Answers

First translate the English phrase "Four times the sum of a number and 15 is at least 120" into a mathematical inequality.

"Four times..." means we're multiplying something by 4.

"... the sum of a number and 15..." means we're adding an unknown and 15 and then multiplying the result by 4.

"... is at least 120" means when we substitute the unknown for a value, in order for that value to be in the solution set, it can only be less than or equal to 120.

So, the resulting inequality is 4(x + 15) ≤ 120.

Simplify the inequality.

4(x + 15) ≤ 120
4x + 60 ≤ 120 <-- Using the distributive property
4x ≤ 60 <-- Subtract both sides by 60
x ≤ 15 <-- Divide both sides by 4

Now that we have the inequality in a simplified form, we can easily see that in order to be in the solution set, the variable x can be no bigger than 15.

In interval notation it would look something like this:

[15, ∞)

In set builder notation it would look something like this:

{x | x ∈ R, x ≤ 15}

It is read as "the set of all x, such that x is a member of the real numbers and x is less than or equal to 15".

The graph below represents which system of inequalities? graph of two infinite lines that intersect at a point. One line is solid and goes through the points 0, 2, negative 2, 0 and is shaded in below the line. The other line is dashed, and goes through the points 0, 6, 3, 0 and is shaded in below the line. y < −2x + 6 y ≤ x + 2 y ≤ −2x + 6 y < x + 2 y < 2 over 3x − 2 y ≥ 2x + 2 None of the above

Answers

(0,2)(-2,0)
slope = (0 - 2) / -2 - 0) = -2/-2 = 1
(0,2)...x = 0 and y = 2
sub and find b, the y int
2 = 1(0) + b
2 = b
equation is : y = x + 2......solid line, means there is an equal sign....shaded below the line means less then....
ur inequality for this line is : y < = x + 2

(0,6)(3,0)
slope = (0 - 6) / (3 - 0) = -6/3 = -2

y = mx + b
slope(m) = -2
(0,6)...x = 0 and y = 6
sub and find b, the y int
6 = -2(0) + b
6 = b

ur equation is : y = -2x + 6....dashed line means there is no equal sign...and shading below the line means less then...
so ur inequality of this line is : y < -2x + 6

In summary, ur 2 inequalities are : y < = x + 2 and y < -2x + 6

To solve the problem we should know about the Equation of a line and slope of a line.

The equations are (y≤ x+2) and (y< -2x+6).

Given to us

One line is solid and goes through the points (0, 2), and (-2, 0) and is shaded below the line.The other line is dashed, goes through the points (0, 6) and (3, 0), and is shaded below the line.

For the first line,

Given the points (0, 2), and (-2, 0), therefore,

[tex]x_2=0\\y_2=2\\x_1=-2\\y_2=0[/tex]

Substituting the values in the formula of the slope,

[tex]m=\dfrac{(y_2-y_1)}{(x_2-x_1)}[/tex]

[tex]m=\dfrac{2-0}{0-(-2)} = \dfrac{2}{2} = 1[/tex]

Substitute the value of slope and a point in the formula of line,

[tex]y = mx+c\\y_2 = mx_2+c\\2 = (1)0 +c\\c = 2[/tex]

Thus, the equation of the line is y=x+2, but as given the line is solid and is shaded below the line. therefore,

y≤ x+2

For the Second line,

Given the points (0, 6) and (3, 0), therefore,

[tex]x_2=0\\y_2=6\\x_1=3\\y_2=0[/tex]

Substituting the values in the formula of the slope,

[tex]m=\dfrac{(y_2-y_1)}{(x_2-x_1)}[/tex]

[tex]m=\dfrac{6-0}{0-3} = \dfrac{6}{-3} = -2[/tex]

Substitute the value of slope and a point in the formula of line,

[tex]y = mx+c\\y_2 = mx_2+c\\6 = (-2)0 +c\\c = 6[/tex]

Thus, the equation of the line is y=-2x+6, but as given the line is shaded below the line. therefore,

y< -2x+6

Hence, the equations are (y≤ x+2) and (y< -2x+6).

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If a train travels one mile (5,280 feet) while climbing a hill at an angle of five degrees, approximately how many vertical feet has the train climbed?

Answers

to calculate the vertical height multiply the hypotenuse ( 5280) by the sin of the angle (5)

5280 x sin(5) = 460.1823

round off to 460 feet

angle ABD and angle DBC are supplementary. Find the value of x.

A. 6
B. 8
C. 4
D. 10

Answers

Angle ABD and angle DBC are supplementary
so
14x+8x+4 = 180
22x = 176
x = 8

answer B. 8
The answer is B because if you substitute 8 to x and add them all up you will get 180 degrees.

Find the domain of the following piecewise function

Answers

domain is the numbers you can use

see, we have -1≤x<0 and 0≤x<5

so if it is in the range of -1 to 5, then it is in the function

it includes -1 but not 5 because we gots -1≤x but x<5

remember, in interval notation, [] is includes and () is not include
or
[] is ≤≥ and () is <>

so
[-1,5)

Find the simple interest paid for 8 years on a $850 loan at 7.5% per year.

Answers

The formula is
I=pre
I interest paid?
P principle 850
R interest rate 0.075
T time 8 years
I=850×0.075×8
I=510

The simple interest paid for 8 years on a $850 loan at a 7.5% annual interest rate is $510.

To calculate simple interest, you can use the formula:

Simple Interest (SI) = Principal (P) × Rate (R) × Time (T)

Where:

- Principal (P) is the initial amount of the loan.

- Rate (R) is the annual interest rate (in decimal form).

- Time (T) is the number of years.

In this case:

- Principal (P) = $850

- Rate (R) = 7.5% = 0.075 (decimal form)

- Time (T) = 8 years

Now, plug these values into the formula:

SI = $850 × 0.075 × 8

SI = $510

The simple interest paid for 8 years on a $850 loan at a 7.5% annual interest rate is $510.

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Is the following expression shown the exact answer? 144π - 216√3

true or false

Answers

   
[tex]144\pi - 216\sqrt{3} \\\\ 144 = 2^4 \times 3^2\\\\ 216 = 2^3 \times 3^3\\\\ \Longrightarrow~~\text{Common factor } = 2^3 \times 3^2 = 8 \times 9 = 72\\\\ \Longrightarrow~~ 144\pi - 216\sqrt{3} = \boxed{72\Big(2\pi - 3\sqrt{3} \Big)}[/tex]



EF=5x+15, FG=53 And EG=143 find the value of x
And can you please tell me how to do it?

Answers

I'm assuming EFG is a triangle. In order to solve this problem, you do not have all the information to solve for x in a numerical form. However, if you let variable P equal the perimeter. You can solve for x in terms of P. Perimeter is the sum of all the sides of a shape. First, let's add together all the sides of the triangle. (P = 5x+15+53+143). Add together the common variables so that (5x+211=P). Our next job is to isolate the x. We start by subtracting 211 from both sides. (5x=P-211) Next we divide by 5. [x=(P-211)/5] Therefore, [x=(P-211)/5], assuming P = perimeter

write a numerical sentence that illustrates the commutative property of multiplication

Answers

24 x 15 = 15 x 24

I think that this is an example...
commutative property of multiplication states : ab = ba.....what it is basically saying is u can " commute " the numbers....move them around, and it will not change the result. Example : 4 * 3 = 3 * 4....even though u switched them, they will still equal the same number.

so ur answer can be : 4 * 3 = 3 * 4.....or 2(3x + 5) = (3x + 5) * 2....u get the idea, right ?

On a number line, the directed line segment from Q to S has endpoints Q at –14 and S at 2. Point R partitions the directed line segment from Q to S in a 3:5 ratio. Which expression correctly uses the formula to find the location of point R?

Answers

Final answer:

To find the location of point R on the number line, you can use the formula for finding a point on a line segment given the endpoints and the ratio. In this case, the ratio is 3:5 and the endpoints are -14 and 2.

Explanation:

To find the location of point R, you can use the formula for finding a point on a line segment given the endpoints and the ratio. In this case, the formula is:

R = Q + r(QS)

where Q is the starting point, S is the ending point, r is the ratio between Q and S, and QS is the displacement vector from Q to S. In this problem, Q is -14, S is 2, and the ratio is 3:5. So we can substitute these values into the formula and solve:

R = -14 + (3/8)(2 - (-14)) = -14 + (3/8)(16) = -14 + 6 = -8

Therefore, the location of point R is -8 on the number line.

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The location of point R is -8. The correct answer is option a. [tex]\frac{3}{3+5}(2-(-14))+(-14)[/tex]

To find the location of point R which partitions the directed line segment from Q to S in a 3:5 ratio, we use the section formula. The formula is:

[tex]R =\frac{m}{m+n}(x_2-x_1)+x_1[/tex]

Here, m = 3 and n = 5, while Q is at [tex]x_1 =[/tex] -14 and S is at [tex]x_2 =[/tex] 2.

Plugging in the values, we have:

[tex]R =\frac{3}{3+5}(2-(-14))+(-14)[/tex][tex]R = \frac{3}{8}(2+14)-14[/tex][tex]R = \frac{3}{8} (16)-14[/tex][tex]R = \frac{48}{8}-14[/tex][tex]R = 6-14[/tex]R = -8

Therefore, the location of point R is at -8 on the number line and it is calculated by the expression [tex]R =\frac{3}{3+5}(2-(-14))+(-14)[/tex].

The complete question is:
On a number line, the directed line segment from Q to S has endpoints Q at –14 and S at 2. Point R partitions the directed line segment from Q to S in a 3:5 ratio. Which expression correctly uses the formula [tex]R =\frac{m}{m+n}(x_2-x_1)+x_1[/tex] to find the location of point R?

a. [tex](\frac{3}{3+5})(2-(-14))+(-14)[/tex]

b. [tex](\frac{3}{3+5})(-14-2)+2[/tex]

c. [tex](\frac{3}{3+5})(2-14)+14[/tex]

d. [tex](\frac{3}{3+5})(-14-2)-2[/tex]

2(-4^2) - 2(2^4) + 3^2 - -4^2 + 2^4 = ? Please explain, I got 41 but I highly doubt I'm right.

Answers

PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)
Parenthesis
(-4^2) - inside that we do Exponents first. That makes it (-16). 

(2^4)=2*2*2*2=16

Next, we have Exponents 

3^2=9, 4^2=16, and 2^4=16

Putting that all together so far, we have 2(-16) -2(16) +9 - -16 +16

Taking Multiplication next, we have 2(-16)=-32 and 2(16)=32. 

Then, we have -32 - -32 +9 - -16 +16

Making the double negatives positive (-1*-1=1), we get

-32+32+9+16+16

After that, we add -32 and 32 together to get 0, add 16 and 16 to get 32, then add 9 to 32 and get 41.

Congratulations - you got it right!

Find the probability of drawing a king from a standard deck of cards and then drawing a queen after the first card is replaced in the deck. None of the above 1/26 1/13 1/2704 2/13

Answers

52 cards in a deck

 4 kings

 4 queens

 King = 4/52 reduces to 1/13

Queen = 4/52 reduces to 1/13

1/13 *1/13 = 1/169

 so none of the above

With replacement:

P(K,Q)=(1/13)(1/13)

P(K,Q)=1/169

So none of the above.

Find the lateral area for the prism. L.A. =
Find the total area for the prism. T.A. =

Answers

The lateral area of the prism is given by:
LA=[area of the two triangles]+[area of the lateral rectangles]
hypotenuse of the triangle will be given by Pythagorean:
c^2=a^2+b^2
c^2=6^2+4^2
c^2=52
c=sqrt52
c=7.211'
thus the lateral area will be:
L.A=2[1/2*4*6]+[6*8]+[8*7.211]
L.A=24+48+57.69
L.A=129.69 in^2

The total are will be given by:
T.A=L.A+base area
base area=length*width
=4*8
=32 in^2
thus;
T.A=32+129.69
T.A=161.69 in^2

Answer:

Part 1) [tex]LA=(80+16\sqrt{13})\ in^{2}[/tex]

Part 2) [tex]TA=(104+16\sqrt{13})\ in^{2}[/tex]

Step-by-step explanation:

Part 1) Find the lateral area of the prism

we know that

The lateral area of the prism is equal to

[tex]LA=Ph[/tex]

where

P is the perimeter of the base

h is the height of the prism

Applying the Pythagoras Theorem

Find the hypotenuse of the triangle

[tex]c^{2}=4^{2}+6^{2}\\ \\c^{2}=52\\ \\c=2\sqrt{13}\ in[/tex]

Find the perimeter of triangle

[tex]P=4+6+2\sqrt{13}=(10+2\sqrt{13})\ in[/tex]

Find the lateral area

[tex]LA=Ph[/tex]

we have

[tex]P=(10+2\sqrt{13})\ in[/tex]

[tex]h=8\ in[/tex]

substitutes

[tex]LA=(10+2\sqrt{13})*8=(80+16\sqrt{13})\ in^{2}[/tex]

Part 2) Find the total area of the prism

we know that

The total area of the prism is equal to

[tex]TA=LA+2B[/tex]

where

LA is the lateral area of the prism

B is the area of the base of the prism

Find the area of the base B

The area of the base is equal to the area of the triangle

[tex]B=\frac{1}{2}bh[/tex]

substitute

[tex]B=\frac{1}{2}(6)(4)=12\ in^{2}[/tex]

Find the total area of the prism

[tex]TA=LA+2B[/tex]

we have

[tex]B=12\ in^{2}[/tex]

[tex]LA=(80+16\sqrt{13})\ in^{2}[/tex]

substitute

[tex]TA=(80+16\sqrt{13})+2(12)=(104+16\sqrt{13})\ in^{2}[/tex]




How could you find the y-coordinate of the midpoint of a vertical line segment with endpoints at (0,0) and (0,-12)

Answers

I think it should be -6, because line segment equals 12 and it's midpoint will be 12/2 = 6, so you must go down by 6 from (0,0) point on y axis which is 0-6=-6

So the point will be (0, -6) 

From a deck of 52 cards, one card is drawn at random. Match the following subsets with their correct probabilities.
1. P(face card)
2. P(seven of hearts)
3. P(no black)
4. P(king)
5. P(diamond)

Answers

1.3/13(if you mean jacks queens and kings)
2.1/52
3.1/2
4.1/13
5.1/4

Answer:

P(face card)=3/13 P(seven of hearts)=1/52P(no black)=1/2P(king)=1/13P(diamond)=1/4

Step-by-step explanation:

We know that there are a total 52 cards out of which:

There are 12 face cards ( 4 kings,4 queen and 4 jack)

There are 4 pack:

13- spades     13- club     13-heart     13-diamond.

Out of which there are 26 black cards( 13 spade and 13 club)

There are 26 red cards( 13 heart and 13 diamond)

Now , we are asked to find the probability of each of the following,

1)

P(face card)

Since there are total 12 face cards out of 52 playing cards.

Hence,

P(face card)=12/52=3/13

2)

P( seven of hearts)

As there is just 1 seven of heart out pf 52 cards.

Hence,  P(seven of hearts)=1/52

3)

P(no black)

This means we are asked to find the probability of red card.

As there are 26 red card.

Hence P(no black)=26/52=1/2

4)

P(king)

As there are 4 kings out of 52 cards.

Hence, P(king)=4/52=1/13

5)

P(diamond)

As there are total 13 cards of diamond.

Hence,

P(diamond)=13/52=1/4

Eighty seven decreased by three times a number is greater than one hundred sixty five

Answers

87-3x>165

-3x> (165-85)

-3x>80

80/-3 = -26.666

check;

87-3*(-26)=165

so x < -26

WILL GIVE A BRAINLIEST IF THE ANSWER IS CORRECT!!! PLEASE HELP ASAP!!

Find the value of x in the expression (2a^4b^2)^x=4a^8b^4.

A.
x = 2
B.
x = 3
C.
x = 4
D.
x = 5

Answers

remember
[tex](ab)^c=(a^c)(b^c)[/tex]
and
[tex](a^b)^c=a^{bc}[/tex]
so

[tex](2a^4b^2)^x=(2^x)(a^{4x})(b^{2x})[/tex]

so
[tex](2^x)(a^{4x})(b^{2x})=4a^8b^4[/tex]
we can see from the 2^x=4 that x=2
and 4 times 2=8
and 2 times 2=4

x=2
answer is A

Graph y=-1/2x^2-1. Identify the vertex of the graph. tell whether it is a minimum or maximum. (To clarify, 1/2 is a fraction *x^2)

1. (-1,0);minimum
2.(-1,0);maximum
3.(0,1);maximum
4.(0,-1);minimum

Answers

[tex]y= -\frac{1}{2} x^{2}-1[/tex] is a quadratic function, so its graph is a parabola.

Notice that the coefficient of x is 0, this always means that the axis of symmetry is the y-axis.

That is, the vertex of the parabola is in the y-axis, so the x-coordinate of the vertex is 0.

for x=0, y=-1. So the vertex is (0, -1)

The coefficient of [tex] x^{2} [/tex] is negative. This means that the parabola opens downwards, so the vertex is a maximum.


Answer: (0, -1) , maximum (none of the choices)

The equation y = -1/2x^2 - 1 represents a downward opening parabola with the vertex at (0, -1), making it a maximum point.

Graph: The given equation is y = -1/2x^2 - 1. This represents a downward opening parabola.

Vertex: The vertex of the parabola is at (0, -1), making it a maximum point.

Conclusion: The correct answer is option 4: (0, -1); minimum.

Tim enlarged a picture with a width of 5.5 inches and a length of 8 inches by a scale factor of 3. What are the dimensions of the enlargement?

a. width: 24 in.; length: 16.5 in.b. width: 16.5 in.; length: 24 in.c. width: 14.5 in.; length: 22 in.d. width: 19.5 in.; length: 25 in.

Answers

It is B. 8*3 = 24. 5.5*3 = 16.5

Answer:

Option b. width = 16.5 inches and length = 24 inches

Step-by-step explanation:

Tim enlarged a picture wit a width of 5.5 inches and a length of 8 inches.

He enlarged the picture by a scale factor of 3.

We have to find the new dimensions of the picture.

Since, New dimension of the picture = Scale factor × dimensions before enlargement

So new width = 3×5.5 = 16.5 inches

new length = 3×8 = 24 inches

Therefore, option b. is the answer.

A lawn mower manufacturer incurs a total of $34,816 in overhead costs and $388 per lawn mower in production costs. How many lawn mowers were manufactured if the average cost of production is $660?

Answers

There are 128 law mowers manufactured. 

I hoped I helped and if you need more you could always ask me :)

-Dawn

Answer:

128 lawn mowers

Step-by-step explanation:

Given,

The overhead cost = $ 34,816,

The cost for one lawn mower = $ 388,

Let x be the number of lawn mowers manufactured,

So, the total cost of x lawn mowers = 34816 + 388x,

Now, if the average cost of x mowers = $ 660,

So, the total cost = 660x

[tex]\implies 660x = 34816 + 388x[/tex]

[tex]660x - 388x = 34816[/tex]

[tex]272x= 34816[/tex]

[tex]\implies x = \frac{34816}{272}=128[/tex]

Hence, 128 lawn mowers were manufactured.

Perform Gauss-Jordan elimination on the augmented matrix shown.
Could someone please help me figure this out.

Answers

Hi! Let me help you!
Basing from the visual you provided, it can be observed that item A, item B, item C, and item D have already undergone "row operations". Therefore, to complete Gauss-Jordan elimination, all we need to do is to transform row echelon A, row  echelon B, row echelon C, and  row echelon D such that each element they have separately become roots of their respective linear equations.

For A:
x = 2; y = (not sure if it is -1 or -7, the visual is too blurry for me to see)

For B:
x = ; y = -1

For C:
x = 0; y = 0

For D:
x = -(26/3); y = -7

I hope this helped you!

17. For the parallelogram find the value of the variables. Show your work.

18. What is the length of the second base of a trapezoid is the length of one base is 24 and the length of the midsegment is 19? Show your work

Answers

24=3y-6 => 30=3y, y=10,

12 = 5x+2 => 10=5x, x =2

Basically parallel sides must have the same length (parallelogram)

Hope it helps!


24=3y-6= 30=5x, y=30
12=5x+2 = 10=5x x=2

If h(x)=6-x, what is the value of (h o h)(10)

Answers

[tex](h \circ h)(x)=6-(6-x)=6-6+x=x\\\\ (h \circ h)(10)=10[/tex]
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