The perimeter of a rectangle is 16 inches. The equation that represents the perimeter of the rectangle is 2l + 2w = 16, where l represents the length of the rectangle and w represents the width of the rectangle. Which value is possible for the length of the rectangle?

Option D. $1.50 x 5 = $7.50

For week:

$1.50 x 5

= $7.50

So, the correct answer is D) $1.50 x 5 = $7.50.

The number of bacteria in petri dish A is 30 times greater than the number in petri dish B. This is calculated by dividing 2.4 × 10^11 by 8 × 10^9.

To determine how many times greater the number of bacteria in petri dish A is compared to petri dish B, we need to divide the number of bacteria in petri dish A by the number in petri dish B.

Given:

The calculation is:

2.4 × 10^11 / 8 × 10^9 = 3 × 10^1 = 30

Therefore, the number of bacteria in petri dish A is 30 times greater than in petri dish B.

The probability of the player for final roll is 25%.

Given data:

To find the probability that the final roll is made by player A, we need to consider the possible outcomes of the game. There are two possible scenarios:

Player A rolls a sum of 9 before player B rolls a sum of 6.

Player B rolls a sum of 6 before player A rolls a sum of 9.

Let's calculate the probability for each scenario and determine the probability that the final roll is made by player A.

Scenario 1:

Player A rolls a sum of 9 before player B rolls a sum of 6.

The probability of rolling a sum of 9 with two dice is given by the number of favorable outcomes divided by the total number of possible outcomes.

The number of favorable outcomes for a sum of 9 is 4, as there are four ways to get a sum of 9: (3, 6), (4, 5), (5, 4), and (6, 3).

The total number of possible outcomes when rolling two dice is 36 (6 possible outcomes for each die).

Therefore, the probability of player A rolling a sum of 9 before player B rolls a sum of 6 is 4/36 = 1/9.

Scenario 2:

Player B rolls a sum of 6 before player A rolls a sum of 9.

Similarly, the probability of rolling a sum of 6 with two dice is given by the number of favorable outcomes divided by the total number of possible outcomes.

The number of favorable outcomes for a sum of 6 is 5, as there are five ways to get a sum of 6: (1, 5), (2, 4), (3, 3), (4, 2), and (5, 1).

Therefore, the probability of player B rolling a sum of 6 before player A rolls a sum of 9 is 5/36.

Now, calculate the probability that the final roll is made by player A by adding the probabilities of both scenarios:

Probability that the final roll is made by player A = Probability of Scenario 1 + Probability of Scenario 2

= 1/9 + 5/36

= 4/36 + 5/36

= 9/36

= 1/4

Hence, the probability that the final roll is made by player A is 1/4 or 25%.

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Answer:  D   NOTHING NEEDS TO BE DONE

Step-by-step explanation: and ANY ONE WHO NEEDS THIS ANSWER LOOK IN THE COMMENTS ON THE QUESTION  SO YOU KNOW WHAT IM TALKING ABOUT

Answer:

The absolute value of a real number is the distance from 0 on the number line. The absolute value of a complex number is the distance from the origin in the complex plane. Both are distances, and therefore both are positive values. You need to use the distance formula or the Pythagorean theorem to calculate the absolute value of a complex number.

Step-by-step explanation:

Use the distance formula or the Pythagorean theorem to calculate the absolute value of a complex number.

Every complex number may be represented in the form a + bi, where a and b are real numbers. A complex number is an element of a number system that extends the real numbers with a specific element labeled I sometimes known as the imaginary unit, and satisfies the equation i² = 1.

The absolute value of a real number is the distance from 0 on the number line. The absolute value of a complex number is the distance from the origin in the complex plane.

Both are distances, and therefore both are positive values. You need to use the distance formula or the Pythagorean theorem to calculate the absolute value of a complex number.

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The investor bought 175 shares at $7.00 per share and 225 shares at $1.00 per share.

To solve this problem, you can set up a system of equations. Let x be the number of shares bought at $7.00 per share and y be the number of shares bought at $1.00 per share.

From the information given, we know that:

To solve the system of equations, you can use the substitution method or the elimination method.

Using the elimination method, multiply equation 1 by 7 to make the coefficients of x in both equations equal:

Now, subtract equation 2 from equation 3 to eliminate x:

Substitute the value of y into equation 1 to find x:

Therefore, the investor bought 175 shares at $7.00 per share and 225 shares at $1.00 per share.

Let's solve for a.y=2x2+3andgxStep 1: Flip the equation.3adgnx+2x2=yStep 2: Add -2x^2 to both sides.3adgnx+2x2+−2x2=y+−2x23adgnx=−2x2+yStep 3: Divide both sides by 3dgnx.‌3adgnx3dgnx‌=‌−2x2+y3dgnx‌a=‌−2x2+y3dgnx answer :a=‌−2x2+y3dgnx

Answer:

Option A) [tex]1.2(2.5)^{x-1}[/tex]

Step-by-step explanation:

We are given a series:

[tex]1.2, 3, 7.5, 18.75, ...[/tex]

We know that the given series is a geometric series as

[tex]\displaystyle\frac{3}{1.2} = \frac{7.5}{3} = \frac{18.75}{7.5} = 2.5[/tex]

Geometric Series:

The [tex]n^{th}[/tex] term of a geometric series is given by:

[tex]a_n = a(r)^{n-1}[/tex]

[tex]a_1= 1.2\\a_2 = 1.2(2.5)^{2-1} = 3\\a_3 = 1.2(2.5)^{3-1} = 7.5\\a_4 = 1.2(2.5)^{4-1} = 18.75[/tex]

Thus, the general term of the given series can be formulated with the help of [tex]f(x) = 1.2(2.5)^{x-1}[/tex]

Option A) [tex]1.2(2.5)^{x-1}[/tex]

Answer:

Inequality: [tex]\frac{y}{2}>22[/tex]

Solution: [tex]y>44[/tex]

Step-by-step explanation:

We are supposed to write and solve an inequality for the given verbal description.

One half of a number y would be y divided by 2: [tex]\frac{y}{2}[/tex].

Since one half of a number y is more than 22, so we can set an inequality as:

[tex]\frac{y}{2}>22[/tex]

Multiply both sides by 2:

[tex]\frac{y}{2}*2>22*2[/tex]

[tex]y>44[/tex]

Therefore, the solution to our given inequality is any value of y greater than 44.

The inequality representing the verbal expression '8 less than a number n is less than 11' is written as 'n < 19'. This is found by adding 8 to both sides of the inequality 'n - 8 < 11'.

The inequality that represents the verbal expression '8 less than a number n is less than 11' can be translated into a mathematical inequality as follows. First, '8 less than a number n' means you take 8 away from n, which is written as n - 8. Then, this quantity being 'less than 11' is represented by the inequality n - 8 < 11. To find the range of values for n, we solve this inequality.

Step 1: Add 8 to both sides of the inequality to isolate n -
n - 8 + 8 < 11 + 8
Step 2: Simplify -
n < 19

Therefore, the inequality symbol that represents the verbal expression is n < 19.

The inequality that represents the verbal expression '8 less than a number n is less than 11' is 8 < n < 11. The symbol '<' represents 'less than' and since the number n is between 8 and 11, we use the inequality symbol '<' twice.

The inequality that represents the verbal expression '8 less than a number n is less than 11' is 11 > n - 8 > 8.

The inequality that represents the verbal expression '8 less than a number n is less than 11' is 11 > n - 8 > 8. This inequality states that the number n, decreased by 8, is greater than 8 and less than 11.

The transformation that would show triangle PTS is congruent to triangle QTR in quadrilateral PQRS is a reflection over the line segment PR, assuming PQRS is a parallelogram.

The question involves identifying which transformation of triangle PTS would show that it is congruent to triangle QTR in quadrilateral PQRS. Without a diagram, it's difficult to provide a specific answer. However, the properties given refer to the symmetric treatment of the sides of a parallelogram and parallel lines. Based on the axioms provided, if PQRS is a parallelogram, then any reflection over the line connecting opposite corners (diagonals) would make two triangles inside the parallelogram congruent. This is because reflections over a line preserve the size and shape of a geometric figure while flipping it over the line. Since PTS and QTR share point T, reflect triangle PTS over the line containing this shared point, which is the line TR or line segment PR, assuming PQRS is a parallelogram.

The slope of the graph at the point (3,15) is -10. The equation of the tangent line at that point is y = -10x + 45.

To find the slope of the graph, we need to differentiate the equation y=5x/(x-2). Using the quotient rule, the derivative of this equation is (5(x-2) - 5x)/(x-2)². Simplifying this further, we get -10/(x-2)². Now, substitute the x-coordinate of the point (3,15) into the derivative to find the slope at that point. Substituting x=3, we get a slope of -10/1 = -10.

To find the equation of the tangent line at the point (3,15), we use the point-slope form of a line, y - y1 = m(x - x1). Substituting the slope (-10) and the coordinates of the point (3,15) into this equation, we get y - 15 = -10(x - 3). Simplifying further, we get y - 15 = -10x + 30. Rearranging the equation, we get y = -10x + 45. Therefore, the equation of the tangent line to the graph at the point (3,15) is y = -10x + 45.