The equation of a given circle in general form is x2+ y2 − 8x + 12y + 27 = 0. Write the equation in standard form, (x − h)2 + (y - k)2 = r2, by completing the squares in the equation. Show your work in a table.

Answers

Answer 1
The equation of the circle is [tex] x^{2} + y^{2} +8x+12y+27=0[/tex]

we take x-es and y-s 'close' to each other, and complete the square:

[tex]x^{2}+8x + y^{2} +12y+27=0[/tex]

write the coefficients of the linear terms (the x and y with degree 1) as 2*'something', to see how to complete the square:

[tex]x^{2}+2*4*x + y^{2} +2*6*y+27=0[/tex]

which means that [tex]x^{2}+2*4*x[/tex] needs [tex] 4^{2} [/tex]  

and [tex]y^{2} +2*6*y[/tex] needs [tex] 6^{2} [/tex] to become perfect square trinomials:

[tex](x^{2}+2*4*x + 4^{2})-4^{2} + (y^{2} +2*6*y+ 6^{2})-6^{2} +27=0[/tex]

[tex] (x+4)^{2}+ (y+6)^{2}=16+36-27 [/tex]
[tex] (x+4)^{2}+ (y+6)^{2}=25 [/tex]

[tex](x-(-4))^{2}+ (y-(-6))^{2}= 5^{2} [/tex]


Answer: [tex](x-(-4))^{2}+ (y-(-6))^{2}= 5^{2} [/tex]

Answer 2

Answer:

Step                                                                     Reason

x2 + y2 - 8x + 12y + 27 = 0                                 given

x2 - 8x + y2 + 12y = -27                                      Isolate the constant term

x2 - 8x + 16 + y2 + 12y + 36 = -27 + 16 + 36      Complete the square by adding                              .                                                                           16 and 36 to both sides.

(x2 - 2∙4∙x + 42) + y2 + 12y + 36 = 25                Group and rearrange terms in x.

(x - 4)2 + y2 + 12y + 36 = 25                              (a - b)2 = a2 - 2ab + b2

(x - 4)2 + (y2 + 2∙6∙y + 62) = 25                         Group and rearrange terms in y.

(x - 4)2 + (y + 6)2 = 25                                        (a + b)2 = a2 + 2ab + b2

(x - 4)2 + (y + 6)2 = 52                                        Take the square root to find r = 5.

Step-by-step explanation:

this is the exact answer from plato

hope this helps a little bit :))


Related Questions

Andrew estimated the weight of his dog to be 60 lb. The dog’s actual weight was 68 lb. What was the percent error in Andrew’s estimate? Round your answer to the nearest tenth of a percent. __________ %

Answers

well, the error value is 8, he was off by 8 units... so, if we take 68 to be the 100%, what is 8 in percentage off of it?

[tex]\bf \begin{array}{ccllll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 68&100\\ 8&x \end{array}\implies \cfrac{68}{8}=\cfrac{100}{x}[/tex]

the quadratic formula gives which roots for the equation 2x^2+x-6=0

Answers

2x^2 + x - 6 = 0
a=2, b=1, c=-6
x = -b+_ /(b^2 - 4ac) ÷ 2a
+_ (plus minus) / ( square root)
X = -1 +_ /1^2 - 4(2)(-6) ÷ 2(2)
= -1 +_ /49 ÷ 4
= -1 +_ 7 ÷ 4
= 6/4 or -8/4
= 3/2 or -2

Hope it helped!
Final answer:

The quadratic formula gives two roots for a quadratic equation. The roots of the equation 2x²+x-6=0 are 1.5 and -2.

Explanation:

The quadratic formula gives the roots of a quadratic equation of the form ax²+bx+c=0. For the equation 2x²+x-6=0, the values of a, b, and c are 2, 1, and -6, respectively.

Using the quadratic formula, we can calculate the roots:

x = (-b ± √(b² - 4ac)) / (2a)

Substituting the values of a, b, and c into the formula:

x = (-1 ± √(1² - 4*2*(-6))) / (2*2)

Simplifying the expression:

x = (-1 ± √(1 + 48)) / 4

x = (-1 ± √49) / 4

x = (-1 ± 7) / 4

Therefore, the roots of the equation 2x²+x-6=0 are:

x = (-1 + 7) / 4 = 3/2 = 1.5

x = (-1 - 7) / 4 = -8/4 = -2

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The rounding rule for the correlation coefficient requires three decimal places true or false

Answers

Answer:

Round the value of r to three decimal places.

Step-by-step explanation:

The rounding rule for the correlation coefficient requires three decimal places

this statement is true.

The correlation coefficient in statistics is a parameter which measures the degree of strength of relation between two variables .

Its value lies between -1  to +1 .

The closer the correlation coefficient  will be near to 1 the stronger the correlation will be.

The correlation between two variables can be positive or negative

Correlation coefficients are helpful in determining the  functional relationships among the variables

So higher  magnitude  of correlation coefficients lead to accurate functional relation among variables.

The rounding rule for the correlation coefficient requires three decimal places

this statement is true.

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What are the values of a1 and r of the geometric series?

2 – 2 + 2 – 2 + 2

Answers

First term, a, is 2.  Next term, -2, is the product of 2 and -1 and is -2.  Next term, 2, is the product of -2 and -1.  Thus, the first term, a, is 2 and the common ratio, r, is -1.

Answer:  For the given geometric series, the first term is [tex]a_1=2[/tex] and the common ratio is [tex]r=-1.[/tex]

Step-by-step explanation:  We are given to find the values of [tex]a_1[/tex] and [tex]r[/tex] of the following geometric series:

[tex]2-2+2-2+2-~.~.~..[/tex]

We know that

[tex]a_1[/tex] is the first term and [tex]r[/tex] is the common ratio of the given geometric series.

We can see that the first term of the given geometric series is 2.

So. we must have

[tex]a_1=2.[/tex]

Also, common ratio is found by dividing a term by its preceding term.

Therefore, the common ratio [tex]r[/tex] of the given geometric series is

[tex]r=\dfrac{-2}{2}=\dfrac{2}{-2}=~.~.~.~=-1.[/tex]

Thus, for the given geometric series, the first term is [tex]a_1=2[/tex] and the common ratio is [tex]r=-1.[/tex]

Ohm’s Law states that the electrical current, I in amperes, through a resistor is given by the formula 644-14-04-00-00_files/i0210000.jpg where V is the voltage in volts and R is the resistance in ohms. If the current is 6 amperes and the resistance is 18 ohms, what is the voltage?

Answers

if im am correct its V=I * R sooo    108 = 6 * 18


Your Answer is 108 volts

Answer:

The correct answer is D., or "108 volts".

Complete the pattern ___, ___, ___, 0, 2, 4, 6

Answers

-6, -4, -2, 0, 2, 4, 6. They continue in increments of +2. 

Answer:-6, -4, -2, 0, 2, 4, 6. They continue in increments of +2.

Step-by-step explanation:

A population of flies grows according to the function p(x) = 2(4)x, where x is measured in weeks. A local spider has set up shop and consumes flies according to the function s(x) = 2x + 5. What is the population of flies after two weeks with the introduced spider?

Answers

well, the spider  is "consuming flies", so we'd have to subtract those flies the spider is picking up, that is 2x + 5, x = weeks.

now, after two weeks, x = 2

[tex]\bf P(x)-s(x)\implies 2(4)^2-[2(2)+5]\implies 32-9[/tex]

Answer:

answer is 23

Step-by-step explanation:

Which measure of variability is the most appropriate for this set of values?
13, 42, 104, 36, 28, 6, 17

Answers

Three of the most knowns measure of variability are variance, standard deviation, and interquartile range. Because the given set of values are very far from each other and are also very much scattered, the best measure of variability is the VARIANCE. 

Answer:

in other words that guy said E

Step-by-step explanation:

The law of cosines is a2+b2 - 2abcosC = c^2 find the value of 2abcosC .... A. 40 B. -40 C. 37 D. 20

(The sides are 2,4, and 5; A to B is 2, B to C is 4, and A to C is 5.)

Answers

a² + b² - 2abcosC = c²

Аngle C lies opposite to the side AB, so "c" in the formula it is AB in your triangle

4² + 5² - 2abcosC = 2²
16 + 25 - 2abcosC = 4
41 - 4 = 2abcosC
2abcosC = 37

Given the Law of Cosines, the value of 2abcosC after plugging in the values of a, b, and c is: [tex]\mathbf{2abcosC = 37}[/tex]

Law of Cosines is given as: [tex]a^2+b^2 - 2abcosC = c^2[/tex]

Given also are the sides of a triangle:

a = 4 (side B to C)b = 5 (side A to C)c = 2 (side A to B)

Plug in the values into the Law of Cosines,  [tex]a^2+b^2 - 2abcosC = c^2[/tex] to find [tex]\mathbf{2abcosC}[/tex]

Thus:

[tex]4^2+5^2 - 2abcosC = 2^2\\\\16 + 25 - 2abcosC = 4\\\\41 - 2abcosC = 4[/tex]

Subtract 41 from both sides

[tex]41 - 2abcosC - 41 = 4-41\\\\-2abcosC = -37[/tex]

Divide both sides by -1

[tex]\mathbf{2abcosC = 37}[/tex]

Therefore, given the Law of Cosines, the value of 2abcosC after plugging in the values of a, b, and c is: [tex]\mathbf{2abcosC = 37}[/tex]

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If sin θ = 2 over 7 and tan θ > 0, what is the value of cos θ?

Answers

[tex]\bf sin(\theta)=\cfrac{opposite}{hypotenuse} \qquad cos(\theta)=\cfrac{adjacent}{hypotenuse} \quad % tangent tan(\theta)=\cfrac{opposite}{adjacent}\\\\ -------------------------------\\\\[/tex]

[tex]\bf sin(\theta )=\cfrac{2}{7}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{let's find the adjacent side} \\\\\\ \textit{using the pythagorean theorem}\\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{7^2-2^2}=a\implies \pm\sqrt{45}=a\implies \pm 3\sqrt{5}=a[/tex]

but.... which is it? the + or the -? well, we know that  tan(θ) > 0, is another way to say that the tangent of the angle is positive, now, for the tangent to be positive, since it's opposite/adjacent both opposite and adjacent have to be the same exact sign, now, we know the opposite is +2, so that means the adjacent has to be the same sign, thus is the positive version 3√(5)

thus   [tex]\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\qquad \qquad cos(\theta )=\cfrac{3\sqrt{5}}{7}[/tex]

Which of the following is not one of the three ways to express a ratio A 3/4 B 3:4 C 3 of 4 D 3 to 4

Answers

3 of 4 is the wrong answer

3 of 4 is the incorrect way to express a ratio.

Two standard number cubes are thrown, one after the other. What is the probability that the first cube lands showing a 1 and the second cube lands showing a number that is not 1? Round the answer to the nearest thousandth.

Answers

Let A be the probability that you throw a 1 
Let B be the probability that you don't throw 1

A and B are independent events

P(A)= 1/6  and P(B)= 5/6

Because they are independent you multiply them: 1/6 x 5/6 = 0.138888...

Rounded to the nearest thousandth is 0.139

Answer:

B on edge

Step-by-step explanation:

A deposit of $1,295 at 7% for 180 days what is the interest earned

Answers

Final answer:

To find the simple interest on a deposit of $1,295 at a 7% rate for 180 days, we use the formula I = P × r × t. With 180 days being roughly 0.5 years, the interest earned is approximately $45.33.

Explanation:

Calculating Simple Interest for a Deposit

To calculate the simple interest earned on a deposit, we can use the simple interest formula which is Interest (I) = Principal (P) × Rate (r) × Time (t).

In this case, a student wants to know the interest earned on a deposit of $1,295 at 7% for 180 days. Since simple interest is usually calculated on an annual basis, we need to adjust the time to reflect a portion of the year. 180 days is equivalent to ½ year (since 180/365 ≈ 0.493). Now we can plug in the values into the formula:

I = P × r × t

I = $1,295 × 0.07 × 0.5



So, the interest earned would be:



I = $1,295 × 0.07 × 0.5I = $45.325

The student will earn approximately $45.33 in interest (rounded to the nearest cent).

Write out the form of the partial fraction decomposition of the function (see example). do not determine the numerical values of the coefficients. (a) x4 + 5 / x5 + 2x3

Answers

[tex]\dfrac{x^4+5}{x^5+2x^3}=\dfrac{x^4+5}{x^3(x^2+2)}=\dfrac ax+\dfrac b{x^2}+\dfrac c{x^3}+\dfrac{dx+e}{x^2+2}[/tex]

The infinite sequence –1, –2, –3, –4, –5, ... can be generated with which explicit formula?

Answers

Answer:

An = (-1)* n

Step-by-step explanation:

    An =  ( -1) * n

    A2   = (-1 ) *  2 = -2

    A3= ( -1 ) * 3 = -3

    A4= ( -1 ) * 4 = -4

    A5= ( -1 ) * 5 = -5

An explicit formula also known as an exact formula is a mathematical formula used to find the nth term in a  series or sequence . hence the explicit formula used to find the nth term of this sequence can be represented as

An = ( -1 ) * n  where n = number of the next term

Answer:

A

Step-by-step explanation:

i got it right

If a new car is valued at $13,200 and 6 years later it is valued at $3000, then what is the average rate of change of its value during those six years?

Answers

I'm not in college so take what I say with a grain of salt but to figure that out first I found the range of 13,200 and 3,000 or basically subtracted 3,000 from 13,200 to get 10,200 so it's value went down 10,200 dollars worth of value in six years, next I divided 10,200 by six because it was six years. To get a rate of change of 1,700 dollars worth of value each year. So the answer is an average rate of 1,700 dollars during those six years or 1.28%

How many minutes does it take an athlete to run a 10.0 kilometer​ race? assume the​ athlete's pace is 6.50 minutes per mile.​ (1 mi​ = 1.609​ km)?

Answers

Final answer:

To find out how many minutes it takes an athlete to run a 10.0 kilometer race using a pace of 6.50 minutes per mile, we can set up a proportion and solve for x. The athlete takes approximately 40.33 minutes to run the race.

Explanation:

To convert the athlete's pace from minutes per mile to minutes per kilometer, we will use the conversion factor 1 mile = 1.609 kilometers. Therefore, the athlete's pace is 6.50 minutes per 1.609 kilometers. To find out how many minutes it takes the athlete to run a 10.0 kilometer race, we can set up a proportion:

6.50 minutes / 1.609 kilometers = x minutes / 10.0 kilometers

Using cross multiplication, we can solve for x:

x = (6.50 minutes × 10.0 kilometers) / 1.609 kilometers

x = 40.33 minutes (rounded to two decimal places)

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Factor 2x^2-128 completely

Answers

2x² - 128

2(x² - 64), but (x² - 64)  = x² - 8² (difference of 2 squares),[a²-b²=(a-b)(a+b)]

2(x² - 64) = 2(x² - 8²) = 2(x-8)(x+8)

Simplify: 4x^2+36/4x•1/5x

Answers

[tex] \frac{4x^2+36}{4x}* \frac{1}{5x} = \frac{4(x^2+9)}{20x^2} = \frac{x^2+9}{5x^2} [/tex]

Answer:

Step-by-step explanation:

The given equation is:

[tex]\frac{4x^2+36}{4x}{\times}\frac{1}{5x}[/tex]

On solving the above equation, we get

=[tex]\frac{4x^2+36}{(4x)(5x)}[/tex]

=[tex]\frac{4(x^2+9)}{(4x)(5x)}[/tex]

=[tex]\frac{x^2+9}{(x)(5x)}[/tex]

=[tex]\frac{x^2+9}{(5x^2)}[/tex]

which is the required simplified form.

Thus, the simplified form of the given equation [tex]\frac{4x^2+36}{4x}{\times}\frac{1}{5x}[/tex] is [tex]\frac{x^2+9}{(5x^2)}[/tex].

Let g(x) = x - 3 and h(x) = x2 + 6. What is (h o g)(1)?

Answers

[tex]\bf g(x)=x-3\qquad h(x)=x^2+6 \\\\\\ (h\circ g)(1)\implies h[\ g(1)\ ]\impliedby \textit{now, let's find g(1) first} \\\\\\ g(1)=(1)-3\implies g(1)=\boxed{-2}\qquad thus \\\\\\ h[\ g(1)\ ]\implies h\left( \boxed{ -2}\right)\implies h(-2)=(-2)^2+6 \\\\\\ h(-2)=4+6\implies h(-2)=10\impliedby (h\circ g)(1)[/tex]

which expression is equivalent to (4h^7k^2)^4?

A: 16h^11k^6
B: 16h^28k^8
C; 256h^11k^6
D: 256h^28k^8

Answers

[tex](4h^7k^2)^4 = 4^4 * h^{7*4} * k^{2*4} = 256* h^{28}* k^{8} [/tex]

The answer is D.

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

[tex](4h^7k^2)^4[/tex]

We need to simplify this :

Here we go:

We will apply :

[tex](a^m)^n=a^{mn}[/tex]

[tex](4h^7k^2)^4\\\\=4^4\times (h^7)^4\times (k^2)^4\\\\=256h^{28}k^8[/tex]

Hence, option 'D' is correct.


Which are the roots of the quadratic function f(q) = q2 – 125? Check all that apply. q = 5 q = –5 q = 3 q = –3 q = 25 q = –25

Answers

Answer:

q=5 sqrt 5 and q=-5 sqrt 5

Step-by-step explanation:

got it right on edge :)

Final answer:

The roots of the quadratic function f(q) = q^2 − 125 are q = -5 and q = 5. Other options listed do not satisfy the function. The roots are found by factoring the equation as a difference of squares.

Explanation:

The roots of the quadratic function f(q) = q2 − 125 can be found by solving the equation q2 − 125 = 0. To find the roots, we need to factor the quadratic or use the square root property since the equation is already set to zero.

We can see that this is a difference of squares equation, so it factors to (q + 5)(q - 5) = 0. Setting each factor equal to zero gives us q = -5 and q = 5.

So, the roots of the quadratic function are q = -5 and q = 5. The other options given (q = 3, q = -3, q = 25, q = -25) do not satisfy the equation f(q) = q2 − 125 = 0, hence they are not roots of this function.

Lily is standing at horizontal ground level with the base of the Sears Tower. The angle formed by the ground and the line segment from her position to the top of the building is 15.7°. The Sears Tower is 1450 feet tall. Find Lily's distance from the Sears Tower to the nearest foot.

Answers

This is the concept of trigonometry, the distance of Lily from the tower will be given by:
tan theta=[opposite]/[adjacent]
opposite=1450 ft
adjacent=x ft
theta=15.7
thus;
1450/x=tan15.7
hence;
x=1450/tan15.7
x=5,158.54 ft
x=5,159 (to the nearest foot)

In the figure below, segment AC is congruent to segment AB:

Triangle ABC with a segment joining vertex A to point D on side BC. Side AB is congruent to side AC

Which statement is used to prove that angle ABD is congruent to angle ACD?

Answers

the answer is A. segment AD bisects angle CAB. I just took the exam and I got it right. hope this helps!

Answer: Isosceles  triangle theorem

Step-by-step explanation:

In the given picture, there a triangle whose two sides are equal AB=AC.

Therefore it is an isosceles triangle.

Now, the isosceles theorem says that the angles opposite to the equal sides of a triangle are equal.

Therefore by isosceles triangle theorem in ΔABC we have

[tex]\angle{B}=\angle{C}[/tex]

Since [tex]\angle{ACD}=\angle{C}[/tex] [Reflexive]

[tex]\angle{ABD}=\angle{B}[/tex] [Reflexive]

Therefore, [tex]\angle{ACD}=\angle{ABD}=[/tex]

The circle will be dilated by a scale factor of 6. What is the value for n if the expression nPI represents the circumference of the circles in inches?

Answers

A dilation by a scale factor of 6 will cause the radius to increase by a factor of 6. So [tex]r_{new} = 6r[/tex]. If we plug this value of r into the formula for the circumference of a circle we get [tex]C = 2\pi r_{new} = 2\pi *6r = 12\pi r[/tex]

So basically N = 12r. You haven't given me any original radius, so I can't give you a constant for N, but if you do have that original radius you can just plug that into 12r.

Based on your comment, N = 12 * 9 = 108 inches

The value of n is 12 .

What is scale factor?

The scale factor is a measure for similar figures, who look the same but have different scales or measures. Suppose, two circle looks similar but they could have varying radii. The scale factor states the scale by which a figure is bigger or smaller than the original figure.

According to the question

The circle will be dilated by a scale factor of 6 .

so,

New radius of the circle R = 6r

As is it dilated by a scale factor of 6

Now ,

The circumference of the new circles = 2πR  

                                                              = 2.6π

                                                              = [tex]12\pi r[/tex]  -------------------- (1)

and given circumference of the new circles = nπ  ---------------------(2)

when we compare both n = 12

Hence, the value of n is 12 .

 

                                                             

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Evaluate the surface integral. ∫∫s (x2 + y2 + z2) ds s is the part of the cylinder x2 + y2 = 16 that lies between the planes z = 0 and z = 5, together with its top and bottom disks.

Answers

Decompose the surface into three components, [tex]\mathbf r_1,\mathbf r_2,\mathbf r_3[/tex], corresponding respectively to the cylindrical region and the top and bottom disks:

[tex]\mathbf r_1(u,v)=\begin{cases}x(u,v)=4\cos u\\y(u,v)=4\sin u\\z(u,v)=v\end{cases}[/tex]
where [tex]0\le u\le2\pi[/tex] and [tex]0\le v\le5[/tex],

[tex]\mathbf r_2(u,v)=\begin{cases}x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=0\end{cases}[/tex]
where [tex]0\le u\le4[/tex] and [tex]0\le v\le2\pi[/tex], and

[tex]\mathbf r_3(u,v)=\begin{cases}x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=5\end{cases}[/tex]
where [tex]0\le u\le4[/tex] and [tex]0\le v\le2\pi[/tex].

For the cylinder, we have

[tex]\dfrac{\partial\mathbf r_1}{\partial u}\times\dfrac{\partial\mathbf r_1}{\partial v}=\langle4\cos u,4\sin u,0\rangle\implies\left\|\dfrac{\partial\mathbf r_1}{\partial u}\times\dfrac{\partial\mathbf r_1}{\partial v}\right\|=4[/tex]

and the integral over this surface is

[tex]\displaystyle\iint_{\text{cyl}}(x^2+y^2+z^2)\,\mathrm dS=4\int_{v=0}^{v=5}\int_{u=0}^{u=2\pi}((4\cos u)^2+(4\sin u)^2+v^2)\,\mathrm du\,\mathrm dv[/tex]
[tex]=\displaystyle320\int_{u=0}^{u=2\pi}\mathrm du+8\pi\int_{v=0}^{v=5}v^2\,\mathrm dv[/tex]
[tex]=640\pi+\dfrac83\pi(125)[/tex]
[tex]=\dfrac{2920\pi}3[/tex]

Bottom disk:

[tex]\dfrac{\partial\mathbf r_2}{\partial u}\times\dfrac{\partial\mathbf r_2}{\partial v}=\langle0,0,u\rangle\implies\left\|\dfrac{\partial\mathbf r_2}{\partial u}\times\dfrac{\partial\mathbf r_2}{\partial v}\right\|=u[/tex]

and the integral over the bottom disk is

[tex]\displaystyle\iint_{z=0}(x^2+y^2+z^2)\,\mathrm dS=\int_{v=0}^{v=2\pi}\int_{u=0}^{u=4}u((u\cos v)^2+(u\sin v)^2)\,\mathrm du\,\mathrm dv[/tex]
[tex]=\displaystyle2\pi\int_{u=0}^{u=4}u^3\,\mathrm du[/tex]
[tex]=128\pi[/tex]

The setup for the integral along the top disk is similar to that for the bottom disk, except that [tex]z=5[/tex]:

[tex]\displaystyle\iint_{z=5}(x^2+y^2+z^2)\,\mathrm dS=\int_{v=0}^{v=2\pi}\int_{u=0}^{u=4}u((u\cos v)^2+(u\sin v)^2+5^2)\,\mathrm du\,\mathrm dv[/tex]
[tex]=\displaystyle2\pi\int_{u=0}^{u=4}(u^3+25u)\,\mathrm du[/tex]
[tex]=528\pi[/tex]

Finally, the value of the integral over the entire surface is the sum of the integrals over the component surfaces:

[tex]\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\frac{2920\pi}3+128\pi+528\pi=\dfrac{4888\pi}3[/tex]
Final answer:

Evaluate the given surface integral by parameterizing the surface and computing the integral on each surface separately. Take the antiderivatives of both dimensions defining the area, from the bounds of the integral for an accurate solution.

Explanation:

The problem you've presented is a surface integral in the field of calculus, specifically relating to multivariable calculus. To solve this, we need to evaluate the integral over the specified parts of the cylinder and the top and bottom disks. We start by parameterizing the surface. Given that our cylinder is x² + y² = 16 between z = 0 and z = 5, we can use cylindrical coordinates with the parameterization: r(θ, z) = <4cos(θ), 4sin(θ), z> for 0 ≤ θ ≤ 2π and 0 ≤ z ≤ 5. With this parameterization, you can derive the equation for the surface integral and solve it.

When working with surface integrals, it's essential to remember that you are totaling up the quantity across the entire surface of an object. In such a situation, we could handle this problem by separating it into three parts: the side of the cylinder, the top disk, and the bottom disk, and compute the integral on each surface separately.

The integral can be solved by taking the antiderivatives of both dimensions defining the area, with the edges of the surface in question being the bounds of the integral. You can apply this approach to all the separate parts of this question.

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Paula has 3 bananas. She wants to divide each of them into sections. How many 's are there in 3 bananas?

Answers

Answer:

B IS 21

Step-by-step explanation:

John has taken out a loan for college. He started paying off the loan with the first payment of $100. Each month he pays, he wants to pay back 1.1 times the amount he payed the month before. Explain to John how to represent his first 20 payments in sequence notation. Then explain how to find the sum of the first 20 payments using complete sentences.

Answers

John's payments are
month 1: $100
month 2: $100*(1.1)
month 3: $100*(1.1)²
month 4: $100*(1.1)³

...

The payments form the geometric sequence 
a, ar, ar², ..., arⁿ
where
a = $100
r = 1.1

The sum of the first n terms is
[tex]S_{n} = \frac{a(1-r^{n})}{1-r} [/tex]

Therefore the sum of the first 20 payments is
S₂₀ = [$100(1 - 1.1²⁰)]/(1 - 1.1)
     = $5727.50

John makes a total of $5727.50 in the first 20 payments.

whats the value of the equation

Answers

13x-2(x+4) = 8x+1 =

13x-2x-8 = 8x+1=

11x-8 = 8x+1

-8 =-3x+1=

-9 = -3x

x = -9/-3 = 3

x = 3

Determine the angular velocity, in radians per second, of 4.3 revolutions in 9 seconds. Round the answer to the nearest tenth.

Answers

[tex]\bf w=\cfrac{4.3rev}{9sec}\cdot \cfrac{2\pi }{rev}\implies w=\cfrac{4.3\cdot 2\pi }{9sec}[/tex]

simplify away.
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