On a coordinate plane, a dashed straight line has a negative slope and goes through (0, 2) and (4, 0). Everything below and to the left of the line is shaded. Which point is a solution to the linear inequality y < Negative one-halfx + 2? (2, 3) (2, 1) (3, –2) (–1, 3)

1/2 of a mile.

Step-by-step explanation:

He has already gone 4/8 of a mile (3/8 + 1/8) and he needs to go 8/8 of a mile. 8/8 - 4/8 = 4/8. You can simplify that to 1/2.

Answer:

1/2 a mile.

Step-by-step explanation:

He wants to walk 1 mile.

Distance left = 1 - 3/8 - 1/8

= 8/8 - 3/8 - 1/8

= 8/8 - 4/8

= 4/8

= 1/2 a mile.

Final answer:

The slope of the line passing through the points (9, 10) and (7, 2) is 4.

Explanation:

The slope of a line is a measure of how steep the line is and can be calculated using the formula slope = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are any two different points on the line.

Given two points (9, 10) and (7, 2), we can calculate the slope by subtracting the y-coordinate of the first point from the y-coordinate of the second point, and then dividing that number by the result of subtracting the x-coordinate of the first point from the x-coordinate of the second point.

So, the slope would be calculated as follows:

Slope = (10 - 2) / (9 - 7)

Slope = 8 / 2

Slope = 4

Therefore, the slope of the line passing through the points (9, 10) and (7, 2) is 4. This means there is a rise of 4 on the vertical axis for every increase of 1 on the horizontal axis.

Answer:

[tex]10[/tex]

Step-by-step explanation:

Given that [tex]R,S,T[/tex] are mid points of the sides of the triangle [tex]ABC[/tex]

Perimeter of [tex]\Delta ABC=AB+AC+BC=20[/tex]

In the [tex]\Delta ARS\ and\ \Delta ABC[/tex]

[tex]\frac{AR}{AB}=\frac{1}{2} \ \ (as\ R\ is\ mid\ point\ of\ AB)[/tex]

[tex]\frac{AS}{AC}=\frac{1}{2} \ \ (as\ S\ is\ mid\ point\ of\ AC)[/tex]

[tex]\angle A=\angle A[/tex]

from [tex]SAS[/tex] these two triangles are similar

Hence

[tex]\frac{RS}{BC}=\frac{AR}{AB}=\frac{AS}{AC}=\frac{1}{2}[/tex]

[tex]RS=\frac{BC}{2}[/tex]

Similarly [tex]RT=\frac{AC}{2}\ and\ ST=\frac{AB}{2}[/tex]

[tex]Perimeter\ of \ \Delta RST=RS+ST+RT\\\\=\frac{BC}{2}+\frac{AR}{2}+\frac{AC}{2}   \\\\=\frac{AB+AC+BC}{2}\\\\=\frac{20}{2}\\\\ =10[/tex]

Answer:

The continuously compounded return of Mordice Corporation shares for the period August 1 to August 15 is closest to:______6.90%

Step-by-step explanation:

The question is incomplete. This is the complete version

The weekly closing prices of mordice corporation shares are as follows;

Date. Closing price

Ist August. 112

8 August 160

15 August. 120

Solution

The continuous compounded return of mordice corporation shares can be calculated by taking the natural log change

In(120/112)*100= 6.89% which is closest to 6.90%

Answer:

Step-by-step explanation:

Answer:

  2880

Step-by-step explanation:

Sunnyside has 3 of every 4 books, so has ...

  (3/4)(3840) = 2880 . . . books

Answer:

6554 degres

Step-by-step explanation:

Answer:

The least value of (r+s) is (12+14)=26

Step-by-step explanation:

Well, first let us solve equation of 11(s-1)=13(r-1), which results in 11s-11=13r-13. Hence, 11s+2=13r. It is stated that r and s both are integers and greater than 1.

To make sure that r and s are integers, the least value of s must be equal to 14 (s=14) then the least value of r becomes 12 (r=12).

Finally, the least value of (r+s) is (12+14)=26.

Answer: On the 29th day

Step-by-step explanation:

According to this problem, no lilypad dies and the lilypads always reproduce, so we can apply the following reasoning.

On the first day there is only 1 lilypad in the pond. On the second day, the lilypad from the first reproduces, so there are 2 lilypads. On day 3, the 2 lilypads from the second day reproduce, so there are 2×2=4 lilypads. Similarly, on day 4 there are 8 lilypads. Following this pattern, on day 30 there are 2×N lilypads, where N is the number of lilypads on day 29.

The pond is full on the 30th day, when there are 2×N lilypads, so it is half-full when it has N lilypads, that is, on the 29th day. Actually, there are [tex]2^{30} [/tex] lilypads on the 30th, and [tex]2^{29}[/tex] lilypads on the 29th. This can be deduced multiplying succesively by 2.  

Answer:

B = 53°

C = 74°

The correct option for Suppose that we know that a=5cm, b=5cm, and angle A=53o in a certain triangle. According to the Law of Sines D. There is exactly one triangle that meets the criteria.

Given:

a = 5, b = 5,  A = 53°

⇒ a/sin A = b/sin B ⇒ Sin B = Sin A

                               ⇒ B = A (or) 180-A

                               ⇒ B = 53° (or) 127°

B = 53°:

           C = 180-A-B = 0 (not possible)

    ⇒ B = 53°, C = 74° ⇒ C = (Sin C)  (b/sin B) ≅ 6.02 cm

Generally, the law of sines is used to solve the triangle, when we know two angles and one side or two angles and one included side. It means that the law of sines can be used when we have ASA (Angle-Side-Angle) or AAS (Angle-Angle-Side) criteria.

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Answer:

4.93 =< h =< 5.77

a) 90% woman (most of them) are within the height of 4.93 and 5.77 ft

b) not unusual since it is within the range

Note: for this answer, I'll use the following symbols:

=< as less or equal

=> as more or equal

Step-by-step explanation:

The inequality is

Abs[(h-5.35)/0.21)] = < 2

The absolute value sign will causes the value in the abs() bracket to be zero, whether the value is positive or negative

In other word, (h - 5.35)/0.21 could actually be a negative or positive

We consider both possibility

If it's positive: (h - 5.35)/0.21 =< 2

If it's negative: (h - 5.35)/0.21 => -2

Note that if we consider it as negative, the inequality sign change because at negative value, the order of magnitude is inverted to positive values.

Let's consider the positive first:

(h-5.35)/0.21 =< 2

h =< 2*0.21 +5.35

h =< 5.77

And then the negative

(h - 5.35)/0.21 => -2

h => -2*0.21 + 5.35

h => 4.93

From both calculation we can see that the range value of h is

4.93 =< h =< 5.77

a) this means that 90% of woman height is between 4.93 to 5.77 feet

b) 5'99'' = 5.75 ft

The height is within the range found from this calculation. So it's not that unusual.

Answer:

?

Step-by-step explanation:

Answer:

 Roni did not make use of the equation for a proportional relationship.

Step-by-step explanation:

For some constant of proportionality k, y is proportional to x if x and y satisfy the equation ...

  y = kx

Roni knows k=7/25, but she did not use this equation. She added instead of multiplying, so did not end with an equation expressing a proportional relation.

___

  y = (7/25)x

Answer:

47.75 %

Step-by-step explanation:

It is a very well known issue that in Standard Normal Distribution  porcentages of all values fall according to:

μ  +   σ       will contain a 68.3 %

μ   +  2σ    will contain  a  95.5 %

μ  +  3σ      will contain  a  99.7 %

However it is extremely  importan to understand that the quantities above mentioned are distributed simmetrically at both sides of the mean, that is,  the intervals are:

[  μ - 0,5σ ;  μ  + 0,5σ ]

[  μ -   1σ ;  μ  +      1σ ]

[  μ -   1.5σ ;  μ  +   1.5σ ]

So we have to take that fact into account when applying the empirical rule. Then

With   mean    μ  =  47       and  σ = 10   is equal to say

values between    47    and     57    (  μ  +   σ  )  we are talking about the second interval, but just half of it.

Then the  approximate porcentage of light-bulb replacement requests is

95.5 /2   =  47.75 %

Answer:

The probability of a successful event is the ratio of the number of successful events to the total number of events. In this case, a successful event is selecting a red marble from the box. The total number of events is the total number of marbles in the box:

Red marbles/Total number of marbles

4/12 divide

=1/3

The probability of her selecting a red marble is 1/3

The distribution of the marbles is given as:

Red = 4

Green = 8

The probability of selecting a red marble is:

P(Red) =Red/Total

So, we have:

P(Red) = 4/(4 + 8)

Evaluate

P(Red) = 1/3

Hence, the probability of her selecting a red marble is 1/3

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Answer:

Compatible width of rectangular banquet hall could be 90 feet approximately.

Step-by-step explanation:

Given

Area of a rectangular banquet hall = 7400 square feet

Length of rectangular banquet hall = 82 feet

We need to calculate width of the rectangular banquet hall.

Now Area of rectangle is equal to length times width.

Framing in equation form we get;

[tex]Area\ of \ Rectangle= length \times width[/tex]

Substituting the given values we get;

[tex]82 \times width = 7400\\\\width = \frac{7400}{82} = 90.2439[/tex]

Now by definition of Compatible numbers which state that:

"Compatible numbers are the numbers that are easy to add, subtract, multiply, or divide mentally.  Compatible numbers are close in value to the actual numbers that make estimating the answer and computing problems easier."

Now By Using width as 90 feet and length as 82 feet we get area as 7380 sq ft. which is closet to actual area which is 7400 sq ft.

Hence we can say compatible width could be 90 feet approximately.

Answer:

[tex]z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155[/tex]  

[tex]p_v =2*P(Z<-0.155)=0.877[/tex]  

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given [tex]\alpha=0.05[/tex] we have [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .  

Step-by-step explanation:

1) Data given and notation

n=298 represent the random sample taken

X=29 represent the events claimed

[tex]\hat p=\frac{29}{298}=0.0973[/tex] estimated proportion

[tex]p_o=0.1[/tex] is the value that we want to test

[tex]\alpha=0.05[/tex] represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

[tex]p_v[/tex] represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is 0.1 or no.:  

Null hypothesis:[tex]p=0.1[/tex]  

Alternative hypothesis:[tex]p \neq 0.1[/tex]  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)  

The One-Sample Proportion Test is used to assess whether a population proportion [tex]\hat p[/tex] is significantly different from a hypothesized value [tex]p_o[/tex].

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

[tex]z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155[/tex]  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

[tex]p_v =2*P(Z<-0.155)=0.877[/tex]  

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given [tex]\alpha=0.05[/tex] we have [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .  

We can do the test also in R with the following code:

> prop.test(29,298,p=0.1,alternative = c("two.sided"),conf.level = 1-0.05,correct = FALSE)

Answer:The area of the reduced backyard is 112.5 square feet

Step-by-step explanation:

The initial length of the backyard is 40.5 feet long.

The initial width of the backyard is 25 feet wide.

In order to install a pool, the yard needs to be reduced by a scale of 1/3. This means that the new length of the backyard is would be

40.5 × 1/3 = 40.5/3 feet lonng

The new width of the backyard would be

25 × 1/3 = 25/3 feet wide

The backyard is rectangular in shape. Area of a rectangle is length × width. The area of the reduced backyard becomes

40.5/3 × 25/3 = 1012.5/9 = 112.5 square feet

Answer:

112.5 square feet... edg2020

Answer:

0.784

Step-by-step explanation:

Given that you are  analyzing the allele frequencies for fur color in a population of squirrels where black fur is dominant to red fur.

As part of your research, you collect the following data:

Total individuals: 1,000

Red fur individuals: 216

So black fur individuals = [tex]1000-216\\=784[/tex]

p2 = proportion of black fur individuals to total individuals

= [tex]\frac{784}{1000} \\=0.784[/tex]

Final answer:

The value of p2 in the population of squirrels is calculated using the homozygous recessive genotype for red fur (q2), which is found to be 0.216. We find q by taking the square root of q2 and then calculate p as 1 - q. The value of p2 is then p squared, resulting in approximately 0.286.

Explanation:

To determine the value of p2 in the population of squirrels for the trait of fur color, we first need to understand that red fur individuals represent the homozygous recessive genotype, which is indicated by q2 in Hardy-Weinberg equations. Since the total number of red fur individuals is given as 216 out of 1,000, we can calculate q2 by dividing the number of red fur individuals by the total number of individuals, which is 216/1000 = 0.216. To find the value of q, we need to take the square root of q2, so q = sqrt(0.216). Then, according to the Hardy-Weinberg principle, we know p + q = 1. Thus, we can calculate p by subtracting q from 1. Finally, to find p2, we just square the value of p.

The calculations are as follows:

Thus, the value of p2 in this population is approximately 0.286.

Answer:

Large box weighs 60 pounds and small box weighs 25 pounds

Step-by-step explanation:

Let x be the weight of large box and y be the weight of small box

The combined weight of a large box and a small box is 85 pounds.

[tex]x+y= 85[/tex]

[tex]y= 85-x[/tex]

The truck is transporting 50 large boxes and 65 small boxes. If the truck is carrying a total of 4625 pounds in boxes

[tex]50x+65y= 4625[/tex]

Solve for x  and y using both equations

[tex]y= 85-x[/tex]

[tex]50x+65(85-x)= 4625[/tex]

[tex]50x+5525-65x= 4625[/tex]

[tex]-15x+5525= 4625[/tex]

[tex]-15x= 4625-5525[/tex]

[tex]-15x=-900[/tex]

Divide both sides by -15

x=60

[tex]y= 85-x=85-60=25[/tex]

Large box weighs 60 pounds and small box weighs 25 pounds

Answer:

i believe  its  B

Step-by-step explanation:

Answer:

The answer is 8,9,10

Step-by-step explanation:

Question is Incomplete,Complete question is given Below.

Ben earns $9 per hour and $6 for each delivery he makes. he wants to earn more than $155 in an 8-hour workday. what is the least number of deliveries he must make to reach his goal?

Answer:

Ben must make at least 14 Deliveries to achieve his goal.

Step-by-step explanation:

Hourly Rate = $9 per hour

Cost of each Delivery = $6

Number of hours to be worked = 8 hours.

Money needs to be earned =$155

we need to find the number of deliveries he must make to reach his goal.

Solution :

Let number of deliveries be 'x'.

Now we can say that Hourly rate multiplied by number of hours of work plus Cost of each delivery multiplied by number of deliveries should be greater than or equal to Money needs to be earned.

Framing in equation form we get;

[tex]9\times8+6x\geq 155[/tex]

Solving the equation we get;

[tex]72+6x\geq 155[/tex]

Subtracting both side by 72 using Subtraction property of Inequality we get;

[tex]72+6x-72\geq 155-72\\\\6x\geq 83[/tex]

Now Dividing both side by 6 using Division Property we get;

[tex]\frac{6x}{6} \geq \frac{83}{6} \\\\x\geq 13.83[/tex]

Hence Ben must make at least 14 Deliveries to achieve his goal.

Answer:

The Company made 6 Bradley hats and 12 Karli hats.

Step-by-step explanation:

Given,

Total Amount of leather = 100 yards

Total number of hats = 19

Solution,

Let the number of Bradley hat be x.

And also let the number of Karli hat be y.

Total number of hats = 19

[tex]\therefore x+y=19\ \ \ \ \ equation\ 1[/tex]

Now, Bradly hats requires 4 yards and Karli hats requires 6 yards of leather.

So framing the above sentence in equation form, we get;

[tex]4x+6y=100\ \ \ \ \ equation\ 2[/tex]

Now, multiplying equation 1 by 4, we get;

[tex]4(x+y)=19\times4\\\\4x+4y=76\ \ \ \ \ equation\ 3[/tex]

Now we subtract equation 3 from equation 2, we get;

[tex](4x+6y)-(4x+6y)=100-76\\\\4x+6y-4x-4y=24\\\\2y=24\\\\y=\frac{24}{2}=12[/tex]

[tex]y=12[/tex]

On substituting the value of y in equation 1, we get the value of x.

[tex]x+y=19\\\\x+12=19\\\\x=19-12=6[/tex]

Hence The Company made 6 Bradley hats and 12 Karli hats.

Answer:

New dimensions of the floor is approximately 301.25 ft by 181.25 ft

Step-by-step explanation:

The question is incomplete. The complete question should be:

Manufacture wants to enlarger it's floor area 1.5 times that of the current facility. The current facility is 260 ft by 140 ft. The manufacture wants to increase each dimension the same amount. Write the dimensions of the new floor.

Given:

Length of floor = 260 ft

Width of floor = 140 ft

The floor area is increased 1.5 times.

To find the new dimensions of the floor.

Solution:

Original area of the floor = [tex]length\times width= 260\times 140=36400\ ft^2[/tex]

New area = [tex]1.5\times Original\ Area = 1.5\times 36,400=54,600\ ft^2[/tex]

Let the length and width be increased by [tex]x[/tex] ft.

Thus, new length = [tex](260+x)\ ft[/tex]

New width = [tex](140+x)\ ft[/tex]

Area of the new floor can be given as:

⇒ [tex]new\ length\times new\ width[/tex]

⇒ [tex](260+x)(140+x)[/tex]

Multiplying using distribution.

⇒ [tex]x^2+260x+140x+36400[/tex]

⇒ [tex]x^2+400x+36400[/tex]

Thus we can equate this with new area to get the equation to find [tex]x[/tex]

[tex]x^2+400x+36400=54600[/tex]

subtracting both sides by 54600.

[tex]x^2+400x+36400-54600=54600-54600[/tex]

[tex]x^2+400x+18200=0[/tex]

Using quadratic formula:

For a quadratic equation [tex]ax^2+bx+c=0[/tex]

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

For the equation [tex]x^2+400x-18200=0[/tex]

[tex]x=\frac{-400\pm\sqrt{(400)^2-4(1)(-18200)}}{2(1)}[/tex]

[tex]x=\frac{-400\pm\sqrt{232800)}}{2}[/tex]

[tex]x=\frac{-400\pm482.49}{2}[/tex]

[tex]x=\frac{-400+482.49}{2} \ and\ x= \frac{-400-482.49}{2}[/tex]

∴ [tex]x\approx 41.25 \ and\ x\approx-441.25[/tex]

Since length is being increased, so we take [tex]x\approx41.25[/tex]

New dimensions are:

New length [tex]\approx 260\ ft + 41.25\ ft =301.25\ ft[/tex]

New width [tex]\approx 140\ ft + 41.25\ ft =181.25\ ft[/tex]

Answer:

  60 m, 61 m

Step-by-step explanation:

If "a" and "b" represent the lengths of the sides adjacent to the right angle, the area is ...

  area = (1/2)ab

Filling in the given information, we can find the other side to be ...

  330 m² = (1/2)(11 m)b

  60 m = b  . . . . . . divide by the coefficient of b

Then the remaining side can be found from the Pythagorean theorem:

  c² = a² + b² = 11²  + 60² = 3721

  c = √3721 = 61 . . . meters

The lengths of the other two sides are 60 m and 61 m.

Answer:

  H.  13

Step-by-step explanation:

Make use of the Pythagorean theorem twice. The first time, use it to find TS. The second time, use it to find QR.

  TS² + RT² = RS²

  TS² = RS² -RT² = 64 -48 = 16 . . . . subtract RT², fill in numbers

  TS = 4 . . . . . take the square root

Now, QT = QS -TS = 15 -4 = 11, so ...

  QR² = QT² +RT²

  QR² = 11² +(4√3)² = 121 +48 = 169

  QR = √169 = 13

The length of QR is 13.

Answer:

  D.  D: 0 ≤ b ≤ 10; R: 0 ≤ W(b) ≤ 120

Step-by-step explanation:

The problem statement tells you Owen can build up to 10 birdhouses, and that b represents that number. Then 0 ≤ b ≤ 10 is the domain described by the problem statement.

It also tells you that W(b) = 12b, so filling in values from 0 to 10 gives a range from 0 to 120: 0 ≤ W(b) ≤ 120.

These observations match choice D.

The domain and range for the function W(b) = 12b are D: 0 ≤ b ≤ 10 and R: 0 ≤ W(b) ≤ 120 respectively. The option D is correct.

The function W(b) = 12b represents the total amount of wood needed to build b birdhouses, where each birdhouse requires 12 square feet of wood. Since Owen can build up to 10 birdhouses, the domain of the function (which represents the number of birdhouses Owen can build) is 0 ≤ b ≤ 10.

For the range of the function, which represents the total amount of wood in square feet, if Owen builds no birdhouses (b = 0) he needs no wood (0 square feet), and if he builds the maximum of 10 birdhouses (b = 10), he would need 120 square feet of wood which is calculated as W(10) = 12 * 10. Therefore, the range of his function would be 0 ≤ W(b) ≤ 120. The appropriate domain and range for the function are D: 0 ≤ b ≤ 10 and R: 0 ≤ W(b) ≤ 120, which corresponds to option D.

Answer:

The total number of the games that the eagles played is 12

Step-by-step explanation:

Given:

The eagles soccer team win 40% of the games

Number games won last year = 12

To Find:

Total number of the games that the eagles played = ?

Solution:

Let the total number of games eagles played be X

Then

according to the question,

40% of X = 12

[tex]\frac{40}{100} \times X  = 12[/tex]

[tex]X = 12 \times \frac{100}{40}[/tex]

[tex]X = \frac{1200}{40}[/tex]

X = 30

The Eagles played a total of 30 games last year.

To find the total number of games that the Eagles played last year, we can set up a proportion using the information given. Since the Eagles won 40% of their games, we can say that 40% is equal to 12 games. Let x be the total number of games played. The proportion would be: 40/100 = 12/x. Cross multiplying gives us 40x = 1200. Dividing both sides by 40, we find that x = 30. Therefore, the Eagles played a total of 30 games last year.

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Solving the given system of equations involves rearranging one equation to solve for a variable, substituting this into the other equation to find the value of one variable, and then substituting this value back into the rearranged equation to find the value of the other variable.

To solve a system of equations by substitution, we first solve one of the equations for one variable and then substitute this expression into the other equation. Looking at the two given equations, the second equation, 3.25x - y = -14, is easier to solve for y (because the coefficient before y is -1). So, we'll start with that:

This step-by-step process will give the solution to the system by substitution.

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Answer:

Random

Step-by-step explanation:

The sampling technique used in this scenario is A) cluster sampling.

Cluster sampling is a method where the population is divided into clusters or groups, and a random sample of these clusters is selected for analysis.

In this case, the population consists of 20 statistics classes at the local community college.

Instead of selecting individual students, the clusters (classes) are randomly selected.

Once the clusters are chosen, all the students from each selected class are interviewed.

This approach is different from other sampling techniques because it focuses on sampling groups rather than individuals within the population.

Hence, the most appropriate sampling technique in this scenario is cluster sampling (option A), where the classes were randomly selected as clusters, and all the students within each selected class were interviewed.

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