Total distance cover from Jungle A to B is 60 km
Given that;
Time taken to cover distance = 45 minutes
Speed of trip = 80 km/h
Find:
Total distance cover from Jungle A to B
Computation:
Distance = Speed × Time
Total distance cover from Jungle A to B = Time taken to cover distance × Speed of trip
Total distance cover from Jungle A to B = [45/60] × 80
Total distance cover from Jungle A to B = [0.75] × 80
Total distance cover from Jungle A to B = 60 km
Learn more:
https://brainly.com/question/20330990?referrer=searchResults
Euler's formula, V − E + F = 2, relates the number of vertices V, the number of edges E, and the number of faces F, of a polyhedron. Solve Euler's formula for E.
To solve Euler's formula for the number of edges E, you rearrange the formula to E = V + F - 2. This solution requires the basic operations of adding and subtracting from both sides of the equation.
Euler's formula states that V (vertices) minus E (edges) plus F (faces) equals 2 for any polyhedron without holes. Therefore, to solve for E, we need to rearrange the equation as follows:
Starting with the original formula: V - E + F = 2.
Add E to both sides: V + F = E + 2.
Subtract 2 from both sides to solve for E: E = V + F - 2.
This rearranged formula gives us the number of edges E in terms of the number of vertices V and the number of faces F.
The formula for the number of edges (E) in terms of the number of vertices (V) and faces (F) is E = 2 + V - F.
To solve Euler's formula V − E + F = 2 for E, we need to isolate E on one side of the equation. Here's how we can do that:
Add E to both sides of the equation to move the term containing E to one side:
V − E + F + E = 2 + E
V + F = 2 + E
Subtract V and F from both sides:
V + F - V - F = 2 + E - V - F
0 = 2 + E - V - F
Rearrange the terms:
2 = E - V + F
Finally, isolate E by adding V and subtracting F from both sides:
E = 2 + V - F
Therefore, the formula for the number of edges (E) in terms of the number of vertices (V) and faces (F) is E = 2 + V - F.
What is the atomic number of the atom shown?
Answer: An atom a fundamental piece of matter. ... An atom itself is made up of three tiny kinds of particles called subatomic particles: protons, neutrons, and electrons. The protons and the neutrons make up the center of the atom called the nucleus and the electrons fly around above the nucleus in a small cloud.
Step-by-step explanation:
The ratio of girls to boys in Liza’s classroom is 5 to 4. How many girls are in her classroom if there is a total of 27 students?
Would you classify 256 as a perfect square, perfect cube, both, or neither
Two similar triangles are shown below: Which two sets of angles are corresponding angles? ∠w and ∠v; ∠x and ∠y ∠w and ∠y; ∠x and ∠v ∠w and ∠z; ∠x and ∠v ∠w and ∠z; ∠x and ∠y
The answer is <w and <v; <x and <y. hope that helps
Answer:
<w, <v; <x, <y
Step-by-step explanation:
I just took the test. May I have Brainiest? I still need four to level up... TwT
what statement describes the relationship between ∆ XYZ and ∆ X'Y'Z'?
Use the drop-down menus to describe the key aspects of the function f(x) = –x2 – 2x – 1. The vertex is the . The function is increasing . The function is decreasing . The domain of the function is . The range of the function is
The vertex is (-1,0), range is (-inf,0], increasing on (-inf,-1), decreasing on (1,inf)
The key aspects of the function [tex]f(x) = - x^2 - 2x - 1[/tex] are as follows:
Vertex: The vertex of a quadratic function is the point where the function changes from increasing to decreasing, or vice versa. To find the vertex, we can complete the square or use the vertex formula. In this case, the vertex is (-1,0).
Range: The range of a function is the set of all possible output values. Since the leading coefficient in f(x) is negative, the parabola opens downwards, so the range is all numbers less than or equal to 0, or (-inf,0].
Increasing/Decreasing: A quadratic function is increasing to the left of its vertex and decreasing to the right of its vertex. Therefore, f(x) is increasing on (-inf,-1) and decreasing on (-1,inf).
Domain: The domain of a function is the set of all possible input values. For quadratic functions, the domain is all real numbers, so the domain of f(x) is all real numbers.
Therefore, The vertex is (-1,0), range is (-inf,0], increasing on (-inf,-1), decreasing on (1,inf).
For similar question on Domain
https://brainly.com/question/30096754
#SPJ12
When a fraction cannot be simplified, what must be true about the greatest common factor of the numerator and denominator?
Sixteen is seven plus three times a number. Find the number
Saturn is located at a distance of 9.54 AU from the Sun what is its orbital period
Answer:
C. 29.46 years
Step-by-step explanation:
The other person is correct, thank you.
Saturn's mean distance from the Sun at 9.54 AU gives it an orbital period of about 29.46 Earth years.
The student is asking about the orbital period of Saturn based on its average distance from the Sun, expressed in astronomical units (AU). According to Kepler's third law of planetary motion, there is a relationship between the orbital period of a planet and its average distance from the Sun. For Saturn, its mean distance from the Sun is approximately 9.54 AU, and its orbital period is roughly 29.46 Earth years.
Kepler's third law states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit. This can be expressed mathematically as p² = a³, where p is the orbital period in Earth years and a is the semi-major axis in AU. By checking Saturn's given values for p² (29.46 * 29.46 = 867.9) and a³ (9.54 * 9.54 * 9.54 = 868.3), we can see that Saturn's data approximates the relation of Kepler's third law effectively, confirming that an orbital period of 29.46 years for Saturn's distance from the Sun is consistent.
Write a rule for dividing a positive and negative decimal
I don't get this I need help
Arnold baked a rectangular cake that is 22.5 in. long and 17 in. wide. What is the area of the top of the cake?
A. 38.25 in2
B. 79 in2
C. 382.5 in2
D. 3825 in2
A northbound bus returns to the bus stop every 20 minutes. The southbound bus returns to the bus stop every 25 minutes.How long will it be before both of the buses are at the bus stop at the same time again
Convert 9 over 16 to a decimal.
A. 0.4225
B. 0.5225
C. 0.5625
D. 0.7455
What is the value of v? 45(v−7)=2 Enter your answer in the box.
7 2/45 would be the correct answer
Find the coordinates of quadrilateral V' W' X' Y' after a dilation with the scale factor of 2. Original coordinates: V(6, 2), W(–2, 4), X(–3, –2), Y(3, –5), scale factor of 2
The new coordinates after a dilation with scale factor 2 are: V'(12, 4), W'(-4, 8), X'(-6, -4), Y' (6, -10). The new coordinates are calculated by multiplying both the x and y coordinates of the original points by the scale factor.
Explanation:Dilation is a transformation that alters the size of the figure without changing its shape. It's accomplished by multiplying the original coordinates of the vertices by a specified scale factor.
The original coordinates of quadrilateral VWXY are V(6, 2), W(–2, 4), X(–3, –2), and Y(3, –5). The scale factor given is 2. Let's find the coordinates of each point after dilation.
1. First, we'll start with point V. Its coordinates are (6,2). After dilation with a scale factor of 2, we multiply each coordinate by the scale factor. The new coordinates are (6 × 2, 2 × 2) which gives us (12, 4).
2. The coordinates of point W are (–2, 4). After dilation, we obtain the new coordinates as (–2 × 2, 4 × 2), which gives us (–4, 8).
3. Now we move onto point X. Its coordinates are (–3, –2). After dilation, the new coordinates become (–3 × 2, –2 × 2), which is (–6, –4).
4. Lastly, we have point Y. Its coordinates are (3, –5). After dilation, the new coordinates become (3 × 2, –5 × 2), which gives us (6, –10).
Therefore, the coordinates of the quadrilateral V'W'X'Y' after dilation with the scale factor of 2 are V'(12, 4), W'(–4, 8), X'(–6, –4), and Y'(6, –10).
https://brainly.com/question/34134001
#SPJ3
what are the three consecutive even integers that add up to 156
PLS HALP MEH!!!! A soccer ball is kicked from the ground in an arc defined by the function,h(x) = -2x^2 + 8x. What is the height of the ball after 3 seconds?
Answer:
6 feet
Step-by-step explanation:
A soccer ball is kicked from the ground in an arc defined by the function,
[tex]h(x) = -2x^2 + 8x[/tex]
h(x) is the height of the ball and time is t.
we need to find out the height when t= 3 seconds
Plug in 3 for t
[tex]h(x) = -2x^2 + 8x[/tex]
[tex]h(3) = -2(3)^2 + 8(3)[/tex]
[tex]h(3) =-18+24=6[/tex]
The height of the ball after 3 seconds is 6 feet.
There are 240 students on Misty’s school. This is 5% of the total students in the school district. How many students are there in the school district?
To find the total number of students in the school district, set up a proportion using the given information. Cross multiply to solve for x.
Explanation:To find the total number of students in the school district, we can set up a proportion using the given information. If 240 students represent 5% of the total students, we can write the proportion as:
x/240 = 100/5
Cross multiplying, we get:
x = (240 * 100) / 5
Simplifying, we find:
x = 4800
Therefore, there are 4800 students in the school district.
To find the total number of students in the school district, divide the number of students at Misty's school (240) by the percentage they represent (5%), resulting in a total of 4800 students in the school district.
Explanation:If Misty's school has 240 students, which represents 5% of the total students in the school district, we can calculate the total number of students in the school district using percentages and equivalent fractions. We can set up an equation where 240 students is 5% of the total number of students (let's call this total x).
The equation is 240 = 0.05 * x. To find x, divide 240 by 0.05, which gives us x = 240 / 0.05. This calculation yields x = 4800. Therefore, there are 4800 students in the school district.
- 4 3/4 is greater than, equal to or less than -4.7 and then name a number between them
Solve. 6(x+20)=168
A) x=4 2/3 B) x=8
C) x=24 2/3 D) x=28
Sunni drives total of sixty-four and half mile to work and back each day Monday through friday.Her car gets 21.5miles per gallon.if has cost $2.85 per gallon ,how much does it cost Sunni to drive and from work each week?
Which term correctly labels the blank in the graphic organizer above? A. square B. quadrilateral C. pentagon D. triangle
The term that correctly labels the blank in the graphic organizer depends on the specifics of the organizer itself. It could either be a square, quadrilateral, pentagon, or triangle.
Explanation:
Without seeing the graphic organizer, it is difficult to provide a specific answer. However, each option represents a different type of bidimensional figure in mathematics. A square is a specific type of quadrilateral with all sides equal and all angles being 90 degrees. A quadrilateral is a polygon with 4 sides, which can be of different lengths and angles. A pentagon is a polygon with 5 sides. A triangle is a polygon with 3 sides. Depending on what the graphic organizer is showing, any one of these could be the correct answer.
Learn more about Bidimensional Figure here:https://brainly.com/question/36765954
#SPJ6
Answer:B Quadrilateral
Step-by-step explanation:
Answer:B Quadrilateral
Step-by-step explanation:
When a figure is rotated, its angle measures (remains the same OR may change), and its orientation (remain the same OR may change).
please help me solve if it remains the same or may change
The greatest common factor of 60w^5 y^3 and 78wy^2 is _____.
2wy^2
6wy^2
6w^5y^3
13w^5y^3
will mark best answer!
Answer: The required greatest common factor of the given expressions is [tex]6wy^2.[/tex]
Step-by-step explanation: We are given to find the greatest common factor of the following two expressions :
[tex]E_1=60w^5y^3,\\\\E_2=78wy^2.[/tex]
The factorization of the given expressions can be written as :
[tex]E_1=2^2\times3\times5\times w^5\times y^3,\\\\E_2=2\times3\times13\times w\times y^2.[/tex]
Therefore, the greatest common factor of the given expressions is
[tex]GCD(E_1,E_2)=2\times3\times w\times y^2=6wy^2.[/tex]
Thus, the required greatest common factor of the given expressions is [tex]6wy^2.[/tex]
team won 4/5 of games Lily scored points in 2/3 of the games won what fraction of her team's winning games did LILY score point?
There are values of t so that sin t = 5/4. True or false.
Answer: The given statement is FALSE.
Step-by-step explanation: We are given to check whether the following statement is TRUE of FALSE :
"There are values of t so that [tex]\sin t=\dfrac{5}{4}.[/tex]"
We know that the range of sine function is the close interval [-1, 1].
That is,
the value of sine of any angle cannot be less than -1 and greater than 1.
According to the given information, we have
[tex]\sin t=\dfrac{5}{4}=1.25>1.[/tex]
So, no such values of t exists for which [tex]\sin t=\dfrac{5}{4}.[/tex]
Hence, the given statement is FALSE.
PQ and RS are two lines that intersect at point T, as shown below:
Two lines PQ and RS intersect at point T. Angles PTR and STQ are shown congruent.
Which statement is used to prove that angle PTR is always equal to angle STQ?
a. Lines PQ and RS do not have a fixed length.
b. Angle PTR and angle PTS are supplementary angles.
c. Lines PQ and RS intersect at an angle less than a right angle.
d. Angle PTR and angle PTS are complementary angles.
Manoj rappelled 30 ft down from the top of a canyon. He then rappelled an additional 10 ft down the canyon.
What must he do to return to the top of the canyon?
Answer:
To return to the top of the canyon he rappelled 40 ft above .
Step-by-step explanation:
Given : Manoj rappelled 30 ft down from the top of a canyon. He then rappelled an additional 10 ft down the canyon.
To find : What must he do to return to the top of the canyon.
Solution : We have given
Manoj rappelled down from the top of a canyon = 30 ft.
Again he rappelled an additional down the canyon = 10ft.
So, total distance he covered = 30 ft + 10 ft = 40 ft .
Now , He is 40 ft down from the top of the canyon .
To return to the top of the canyon he rappelled 40 ft above .
Therefore, To return to the top of the canyon he rappelled 40 ft above .