How many license plates can be made using 3 digits and 3 letters of repeated digits and letters are not allowed?statistics?

Answers

Answer 1
[tex]10\cdot9\cdot8\cdot26\cdot25\cdot24=11,232,000[/tex]

Related Questions

What is the future value of $20 a week for 10 years at 6 percent interest? assume the first payment occurs at the end of this week?

Answers

$20/wk x 52wk/yr x 10yr
52 wk x 10yr=520 wks
520x20=10,400x 0.06% interest=624
10,400+624=
$11,024

What is the least common multiple of 2, 10 and 6

Answers

The least common multiple (LCM) of numbers is the smallest number that they all can divide evenly into.

2 = 1 × 2

10 = 1 × 2 × 5

6 = 1 × 2 × 3

Hence, the least common multiple is 1 × 2 = 2.

The least common multiple of 2, 10 and 6 by using the definition of multiple is 30.

The lowest possible number that  can be divisible by all the given numbers is called as  least common multiple (LCM). It is the smallest multiple which is common in all the numbers.

The least common multiple of 2, 10 and 6 can be calculated as:

The multiples of 2 are: 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34.........

The multiples of 10 are: 10,20,30,40,50,60,70.............

The multiples of 6 are: 6,12,18,24,39,36,42,48,54,60,66...........

The lowest common multiple among 2,10,6 is 30.

Thus, the least common multiple of 2, 10 and 6 is 30.

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Children of age 3-6 years require 25% less sleep per day than infants, who need 16hours. How much slee do the 3-6 year olds need?

Answers

infants need 16 hrs.....children of age 3 - 6 require 25% less...

16 - 0.25(16) = 16 - 4 = 12 hrs <=
16 × 0.25 = 4
16 - 4 = 12
So therefore, 3-6 year old aneed 12 hours of sleep.

Or you could solve it this way:
100 - 0.25 = 0.75
16 × 0.75 = 12

Either of the two ways you would get 12

A car rents for $180 per week plus $0.75 per mile. Find the rental cost for a two-week trip of 500 miles for a group of three people.

Answers

Answer:

$735

Step-by-step explanation:

$180/week * 2 weeks = $360 for 2 weeks

$0.75/mile * 500 miles = $375

$360 + $375 = $735 for 2 week trip of 50 miles

simplify 10a + 3b + 7a+ 6b

Answers

Combine numbers with the same variable so 10a + 7a = 17a and 3b + 6b = 9b.  So the full answer is 17a + 9b.
Combine like terms

(10+7)a + (3+6)b

17a + 9b

If each dimension of the rectangular prism is doubled, how will its total surface area change?

mc006-1.jpg

[Not drawn to scale]

The surface area doubles.
The surface area triples.
The surface area increases by a factor of four.
The surface area increases by a factor of eight.

Answers

2(wl+hl+hw) is the surface area of the rectangular prism
If you were to double the dimensions
2(2w2l+2h2l+2h2w)
This simlifies to
8(wl+hl+hw).
The surface area increases by a factor of four.

Answer:

inceases by factor four

Step-by-step explanation:


Let x and y represent two real numbers. Write an algebraic expression to denote the quotient obtained when the product of the two numbers is divided by their sum.

Answers

(xy)/(x+y) hope this helps

An algebraic expression to denote the quotient obtained when the product of the two numbers is divided by their sum is (xy)/(x+y).

What is an expression?

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that let x and y represent two real numbers. The expression to denote the quotient obtained when the product of the two numbers is divided by their sum is written as,

E = (xy)/(x+y).

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Juan will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of
$55
and costs an additional
$0.30
per mile driven. The second plan has no initial fee but costs
$0.80
per mile driven.
For what amount of driving do the two plans cost the same?
What is the cost when the two plans cost the same?

Answers

solve for m, the number of miles 

.09m + 57.98 = .14m + 49.98 
9m + 5798 = 14m + 4998 

How do you work out a percentile rank of a score of 57

Answers

To do that you'll need the mean and standard deviation of all the scores.  Can you provide this info?

For example:  Supposing that the mean of these scores were 52 and the standard deviation 3.  You'd need to find the "z-score" of 57 in this case.
               57 - 52
It is  z = ------------ , or z = 5/3, or z = 1.67.
                     3

Find the area to the left of z = 1.67.  Multiply that area by 100% to find the percentile rank of the score 57.

Solve the following system of equations.

7x -8y= -19
-2x +5y =0

x=
y=

Answers

answer is as follows:
x= -5
y= -2

Use cylindrical coordinates. find the volume of the solid that is enclosed by the cone z = x2 + y2 and the sphere x2 + y2 + z2 = 72.

Answers

Step 1: The intersection curve is only at the origin.

Step 2: Set up the volume integral over the sphere region.

Step 3:Evaluate the integral to find the volume: [tex]\(V = 216\pi\sqrt{2}\).[/tex]

To find the volume of the solid enclosed by the cone [tex]\(z = x^2 + y^2\)[/tex] and the sphere[tex]\(x^2 + y^2 + z^2 = 72\),[/tex] we'll first find the intersection curve of the cone and the sphere in cylindrical coordinates, then set up the triple integral to find the volume.

Step 1: Finding the intersection curve:

The cone equation in cylindrical coordinates becomes [tex]\(z = r^2\)[/tex] and the sphere equation remains the same as [tex]\(r^2 + z^2 = 72\).[/tex]

To find the intersection, we set these two equations equal to each other:

[tex]\[r^2 = r^2 + z^2\][/tex]

Substitute [tex]\(z = r^2\)[/tex] from the cone equation:

[tex]\[r^2 = r^2 + (r^2)^2\][/tex]

[tex]\[r^2 = r^2 + r^4\][/tex]

[tex]\[r^4 = 0\][/tex]

From this, we see that the only solution is (r = 0), which corresponds to the point at the origin.

Step 2: Setting up the integral for volume:

We'll integrate over the region where the cone lies within the sphere, which is the entire sphere. In cylindrical coordinates, the limits of integration are [tex]\(0 \leq r \leq 6\)[/tex] (since the sphere has radius [tex]\(\sqrt{72} = 6\)) and \(0 \leq \theta \leq 2\pi\).[/tex]

The limits for \(z\) are from the cone to the sphere, so it's from [tex]\(r^2\) to \(\sqrt{72-r^2}\).[/tex]

Thus, the volume integral is:

[tex]\[V = \iiint_{E} r \, dz \, dr \, d\theta\][/tex]

Where (E) is the region enclosed by the cone and the sphere.

Step 3: Evaluate the integral:

[tex]\[V = \int_{0}^{2\pi} \int_{0}^{6} \int_{r^2}^{\sqrt{72-r^2}} r \, dz \, dr \, d\theta\][/tex]

Let's evaluate this integral step by step:

[tex]\[V = \int_{0}^{2\pi} \int_{0}^{6} (r\sqrt{72-r^2} - r^3) \, dr \, d\theta\][/tex]

[tex]\[V = \int_{0}^{2\pi} \left[-\frac{1}{4}(72-r^2)^{3/2} - \frac{1}{4}r^4\right]_{0}^{6} \, d\theta\][/tex]

[tex]\[V = \int_{0}^{2\pi} \left[-\frac{1}{4}(0)^{3/2} - \frac{1}{4}(6^4) - \left(-\frac{1}{4}(72)^{3/2} - \frac{1}{4}(0)^4\right)\right] \, d\theta\][/tex]

[tex]\[V = \int_{0}^{2\pi} \left[\frac{1}{4}(72)^{3/2}\right] \, d\theta\][/tex]

[tex]\[V = \frac{1}{4}(72)^{3/2} \int_{0}^{2\pi} 1 \, d\theta\][/tex]

[tex]\[V = \frac{1}{4}(72)^{3/2} \cdot 2\pi\][/tex]

[tex]\[V = 36\pi \sqrt{72}\][/tex]

[tex]\[V = 36\pi \times 6\sqrt{2}\][/tex]

[tex]\[V = 216\pi\sqrt{2}\][/tex]

So, the volume of the solid enclosed by the cone and the sphere is [tex]\(216\pi\sqrt{2}\).[/tex]

What is the value of x to the nearest tenth?

Answers

The value of x is: X = 9.75
x (rounded to the nearest tenth): 9.8

Feel free to ask me more questions; I'm happy to help. (Don't forget Brainliest!)

Find the x and y intercepts of 10x-15y=30

Answers

The x intercept is a point where the graph of the function, intercepts the x-axis.

So the coordinate of that point is (x, 0) , that is, y must be 0 since the point is on the x-axis.

letting  y=0, we find:

10x-15y=30

10x=30

x=3

With the same logic, letting x=0, we find the y-intercept:

10x-15y=30

-15y=30

y=-2


Answer: 

x- intercept : 3      [point (3, 0)]
y- intercept : -2      [point (0, -2)]

Harry rolls a number cube what is the probability that he will roll an even number or a number greater than four

Answers

P(E OR >4)=P(E)+P(>4)

P(E OR >4)=(3/6)+(2/6)

P(E OR >4)=5/6

in the problem 10-4=6, whats the correct term for the number 4

Answers

Subtraction is a mathematical operation signified by the minus sign ( - ).
In this example : 10 - 4 = 6 ( or "ten minus four equals six" ).
Terms are:
Minuend  -  Subtrahend  = Difference.
Answer:
The correct term for the number 4 is Subtrahend.

you need 2 3/4 wheelbarrows of sand to make 8 wheelbarrows of concrete. how much sand will you need to make 248 cubic feet of concrete

A. 84 cubic feet
B. 85 1/4 cubic feet
C. 682 cubic feet
D. Not enough info

Answers

8 ÷ (2 3/4) = 32/11

248 ÷ (32/11) = B. 85 1/4 cubic feet

Answer:

Option B.

Step-by-step explanation:

We need [tex]2\frac{3}{4}[/tex] wheelbarrows of sand for 8 wheelbarrows of concrete.

That means ratio between sand and concrete is [tex]2\frac{3}{4}:8[/tex]

Or [tex]\frac{11}{4}:8[/tex]

Now we have to calculate the amount of sand to make 248 cubic feet of concrete.

If the amount of sand required is x cubic feet then the ratio of sand and concrete will be x : 248.

Since both the ratios should be same therefore,

[tex]\frac{x}{248}=\frac{\frac{11}{4} }{8}[/tex]

[tex]\frac{x}{248}=\frac{11}{32}[/tex]

x = [tex]\frac{11\times 248}{32}[/tex]

x = [tex]\frac{2728}{32}[/tex]

x = [tex]\frac{341}{4}[/tex]

  = [tex]85\frac{1}{4}[/tex] cubic feet

Option B will be the answer.

EASY 5 POINTS!!! This box has the same length, width, and height as the 2 basketballs. Which expression gives the volume of the empty space encircling the basketballs inside the box?

Answers

This one is easier to work out by elimination than by actual math:

1. We know it's a difference, therefore we need to subtract the volume of the balls from the volume of the box. B is wrong.

2. The box is 3dimensional so we must have 3 linear measurements multiplied together in it's volume calculation. D is wrong.

3. The sphere volume formula uses radius cubed (not diameter). C is wrong

A is the only one left and must be correct. 

To check:
Volume of the box: [tex] V=lwh = 48 \times 24 \times 24 = 48 \times 24^{2}[/tex]

Volume of two balls: [tex] V = 2(\frac{4}{3} \pi r^{3}) = 2(\frac{4}{3} \pi \times 12^{3})[/tex]

Total volume = box - balls: [tex]V_{total}=48 \times 24^{2} - 2(\frac{4}{3} \pi \times 12^{3})[/tex]

This matches A, just as we thought. 

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An artisan is creating a circular street mural for an art festival. The mural is going to be 50 feet wide. One sector of the mural spans 38 degrees. What is the area of the sector to the nearest square foot?

Answers

check the picture below.

How many times greater is 700 than 70

Answers

Answer:

10 times greater

Step-by-step explanation:

700÷70=10

A ball of radius 0.200 m rolls with a constant linear speed of 3.00 m/s along a horizontal table. the ball rolls off the edge and falls a vertical distance of 2.08 m before hitting the floor. what is the angular displacement of the ball while the ball is in the air

Answers

The angular displacement of the ball while it's in the air is 9.77 radians.

Here's how we can find it:

Time in the air: First, we need to find the time the ball spends in the air. We can use the following kinematic equation for vertical motion:

h = 1/2 * g * t^2

where:

h is the vertical distance (2.08 m)

g is the acceleration due to gravity (9.81 m/s²)

t is the time in the air

Solving for t, we get:

t = sqrt(2 * h / g) = sqrt(2 * 2.08 m / 9.81 m/s²) ≈ 1.43 s

Angular velocity: The angular velocity (ω) of the ball is related to its linear velocity (v) and radius (r) by the following equation:

ω = v / r

where:

v is the linear velocity (3.00 m/s)

r is the radius (0.200 m)

Plugging in the values, we get:

ω = 3.00 m/s / 0.200 m = 15 rad/s

Angular displacement: Finally, the angular displacement (θ) of the ball is the product of its angular velocity (ω) and the time (t) it spends in the air:

θ = ω * t = 15 rad/s * 1.43 s ≈ 21.45 rad ≈ 9.77 rad (rounded to three significant figures)

Therefore, the angular displacement of the ball while in the air is approximately 9.77 radians.

A photograph has a length that is 6 inches longer than its width, x. So its area is given by the expression x(x+6) square inches. If the area of the photograph is 112 square inches, what is the width of the photograph?

Answers

112 = x(x + 6)
112 = x^2 + 6x
x^2 + 6x - 112 = 0
(x - 8)(x + 14) = 0

x - 8 = 0
x = 8

x + 14 = 0
x = -14....not this one because it is negative

x = 8 <===width = 8 inches

L = x + 6
L = 8 + 6
L = 14 ....length = 14

The width of the photograph is 8 inches

let

width of the photograph = x

length of the photograph = 6 + x

Area  = x(6 + x)

112 =  x(6 + x)

112 = 6x + x²

x² + 6x - 112 = 0

x² - 8x + 14x - 112 = 0

x(x - 8) + 14(x - 8) = 0

(x + 14)(x - 8)

x = -14 or 8

x = 8

x cannot be negative so we use only 8.

width of the photograph = 8 inches

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A new car dealer offered to sell her demonstrator model for 90% of the retail price. If the sale price was $9,750, what was the retail price?

Answers

90% = 9,750

9750/90 = 1%

1% = 108.3

100% = 10,833.3

original retail price = $10,833.30

A regular octagon has side length 10.9 in. The perimeter of the octagon is 87.2 in and the area is 392.4 in2. A second octagon has side lengths equal to 16.35 in. Find the area of the second octagon.

Answers

To solve this problem, let us first calculate for the Perimeter of the other octagon. The formula for Perimeter is:

Perimeter = n * l

Where n is the number of sides (8) and l is the length of one side. Let us say that first octagon is 1 and the second octagon is 2 so that:

Perimeter 2 = 8 * 16.35 in = 130.8 inch

We know that Area is directly proportional to the square of Perimeter for a regular polygon:

Area = k * Perimeter^2

Where k is the constant of proportionality. Therefore we can equate 1 and 2 since k is constant:

Area 1 / Perimeter 1^2 = Area 2 / Perimeter 2^2

Substituting the known values:

392.4 inches^2 / (87.2 inch)^2 = Area 2 / (130.8 inch)^2

Area 2 = 882.9 inches^2

 

Therefore the area of the larger octagon is about 882.9 square inches.

Use cylindrical coordinates. find the volume of the solid that lies between the paraboloid z = x2 + y2 and the sphere x2 + y2 + z2 = 2

Answers

[tex]\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}[/tex]

Let [tex]R[/tex] be the region bounded by the two surfaces. Then the volume of the region is given by

[tex]\displaystyle\iiint_R\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{\zeta=r^2}^{\zeta=\sqrt{2-r^2}}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta[/tex]
[tex]=\displaystyle2\pi\int_{r=0}^{r=1}r(\sqrt{2-r^2}-r^2)\,\mathrm dr[/tex]
[tex]=\displaystyle2\pi\int_0^1(r\sqrt{2-r^2}-r^3)\,\mathrm dr[/tex]
[tex]=\dfrac{(8\sqrt2-7)\pi}6[/tex]
Final answer:

To find the volume of the solid that lies between the paraboloid z = x^2 + y^2 and the sphere x^2 + y^2 + z^2 = 2 using cylindrical coordinates, set up the integral for the volume by rewriting the sphere equation in cylindrical coordinates, determining the limits for r and z, and evaluating the integral.

Explanation:

To find the volume of the solid that lies between the paraboloid z = x^2 + y^2 and the sphere x^2 + y^2 + z^2 = 2

We can rewrite the sphere equation in cylindrical coordinates as r^2 + z^2 = 2. The limits for r are from 0 to √(2-z^2), and for z, they are from 0 to √(2-r^2).

The volume can be found by integrating the constant 1 over the limits of r and z: V = ∭1 dz dr dθ. Evaluate this integral to find the volume of the solid.

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The quotient of 8.4x10^9 and a number n results in 5.6 x 10^27 What is the value of n?

Answers

8.4x10^9/n=5.6 x 10^27
so 8.4x10^9/5.6 x 10^27=n
n=1.5x10^-18

Answer:

[tex]1.5\times 10^{-18}[/tex]

Step-by-step explanation:

We have been given that the quotient of [tex]8.4\times 10^9[/tex] and a number n results in [tex]5.6\times 10^{27}[/tex]

To find the value of n we will write our given information in an equation as:

[tex]\frac{8.4\times 10^9}{n}=5.6\times 10^{27}[/tex]

[tex]\frac{8.4\times 10^9}{5.6\times 10^{27}}=n[/tex]

Using quotient rule of exponents [tex]\frac{a^m}{a^n}=a^{m-n}[/tex] we will get,

[tex]\frac{8.4\times 10^{9-27}}{5.6}=n[/tex]

[tex]\frac{8.4\times 10^{-18}}{5.6}=n[/tex]

[tex]1.5\times 10^{-18}=n[/tex]

Therefore, the value of n is [tex]1.5\times 10^{-18}[/tex].

What is the slope of a line that is perpendicular to the line whose equation is 0.5x−5y=9

Answers

First find the slope of the line given by changing it into slope intercept form.
0.5x-5y=9
-5y=-0.5x+9
y=0.1x-9/5
The slope is 0.1
To find a perpendicular slope, find the negative reciprocal.
The reciprocal of 0.1 is 10
The negative of 10 is -10
Final answer: -10
Final answer:

To find the slope of a line perpendicular to the line defined by the equation 0.5x−5y=9, first convert the equation into slope-intercept form to determine the slope of the original line. The slope of the line perpendicular to this is its negative reciprocal. For this specific problem, the slope of the line perpendicular to the given line is -10.

Explanation:

Firstly, rearrange the given equation, 0.5x−5y=9, into the slope-intercept format, i.e. y=mx+b. Here, 'm' is the slope of the line. To illustrate this rearrangement: 5y = 0.5x - 9, then divide through by 5 to get y = 0.1x - 1.8. Thus, the slope of the given line is 0.1.

Lines that are perpendicular to each other have slopes that are negative reciprocals of each other. In this case, the slope of the given line is 0.1, so the negative reciprocal (which represents the slope of the line perpendicular to this line) is -1/0.1, which equals -10. This is the slope of the line perpendicular to the given line.

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What is the probability that a randomly selected person will have a birthday in march? assume that this person was not born in a leap year. express your answer as a simplified fraction or a decimal rounded to four decimal places?

Answers

there are 31 days in August

 365 days in a year

31/365 = 0.0849 probability

Answer:

0.0849

Step-by-step explanation:

Let's consider the event: a birthday takes place in March. The probability (P) of such event is:

[tex]P = \frac{favorable\ cases }{possible\ cases}[/tex]

The favorable cases are 31 because March has 31 days.

The possible cases are 365 because there are 365 days in a year.

The probability of a birthday being in March is:

[tex]P=\frac{31}{365} =0.0849[/tex]

March 21, the 80th day of the year, is the spring equinox. find the number of hours of daylight in fairbanks on this day

Answers

According to a daylight calculator for Fairbanks, AK, sun rises at 07:40 and sun sets at 20:12, giving 12 hours and 32 minutes of daylight.

Note that it is not a mistake that daylight is not exactly 12 hours on that day due to refraction of the sun's rays at sunrise and sunset.

At Fairbanks, near equality to 12 hours occurs on March 16 with sunrise at 07:58 and sunset at 19:57.

Let x be a random variable giving the number of aces in a random draw of 4 cards from an ordinary deck of 52 cards. construct a table showing the probability distribution of x

Answers

[tex]\mathbb P(X=x)=\begin{cases}\dfrac{\binom{48}4\binom40}{\binom{52}4}\approx0.7187&\text{for }x=0\\\\\dfrac{\binom{48}3\binom41}{\binom{52}4}\approx0.2556&\text{for }x=1\\\\\dfrac{\binom{48}2\binom42}{\binom{52}4}\approx0.0250&\text{for }x=2\\\\\dfrac{\binom{48}1\binom43}{\binom{52}4}\approx0.0007&\text{for }x=3\\\\\dfrac{\binom{48}0\binom44}{\binom{52}4}\approx0.0000037&\text{for }x=4\\\\0&\text{otherwise}\end{cases}[/tex]
Final answer:

The provided table outlines the probability distribution for drawing varying numbers of aces in a random draw of 4 cards from a standard 52-card deck, using combinatorial probability calculations.

Explanation:

To answer your question, we need to consider the different possibilities for pulling aces in a draw of four cards. There are 4 aces in a standard deck of 52 cards, and here's a table showing the probability distribution for each outcome:

x = 0 - this represents no aces drawn. The number of ways to choose no aces from 4 aces and 4 non-aces from 48 non-aces is (4 choose 0)*(48 choose 4). So the probability P(X=0) = (comb(4, 0)*comb(48, 4))/comb(52,4)x = 1 - one ace is drawn. The probability P(X=1) = (comb(4, 1)*comb(48, 3))/comb(52,4).x = 2 - two aces are drawn. The probability P(X=2) = (comb(4, 2)*comb(48, 2))/comb(52,4).x = 3 - three aces are drawn. The probability P(X=3) = (comb(4, 3)*comb(48, 1))/comb(52,4).x = 4 - all four aces are drawn, and the probability P(X=4) = (comb(4, 4)*comb(48, 0))/comb(52,4).

Please note that 'comb(a, b)' in this case represents 'a choose b', which is a way to compute combinations in probability.

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A team of 10 players is to be selected from a class of 6 girls and 7 boys. Match each scenario to its probability. You have to drag the sentences to match probabilities.


Possible probabilities are:
0.07
0.12
0.44
0.49


Options for answers are:
The probability that a randomly chosen team includes all 6 girls in the class.
The probability that a randomly chosen team has 3 girls and 7 boys.
The probability that a randomly chosen team has either 4 or 6 boys.
The probability that a randomly chosen team has 5 girls and 5 boys.

Answers

Answer:

 0.07 -The probability that a randomly chosen team has 3 girls and 7 boys.

0.12 -The probability that a randomly chosen team includes all 6 girls in the class.

0.44 -The probability that a randomly chosen team has 5 girls and 5 boys.

0.49-The probability that a randomly chosen team has either 4 or 6 boys.

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When a team of 10 players is to be selected from a class of 6 girls and 7 boys the probability of each scenario occurring is:

0.07 = The probability that a randomly chosen team has 3 girls and 7 boys.

0.12 = The probability that a randomly chosen team includes all 6 girls in the class.

0.44 = The probability that a randomly chosen team has 5 girls and 5 boys.

0.49 = The probability that a randomly chosen team has either 4 or 6 boys.

What is probability?

In simple words, it refers to a numerical guess of how likely an event is to occur. Hence, when it comes to probability we believe there is no guarantee the event would occur.

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