Explanation:
Newton's first law of motion states: "an object in motion stays in motion, and an object at rest stays at rest, until acted upon by an unbalanced force."
When you're riding in a vehicle, your body is moving forward. When the vehicle slows or turns, your body's inertia continues to move you forward. The seatbelt is the unbalanced force that pushes you back into your seat. Without it, you would slide off your seat.
Since there is a tendency for motion to continue in accordance to Newtons laws, a passenger that is not wearing a seat belt may be pushed out of the windscreen.
According to Newtons laws of motion, a body will continue in its state of rest or uniform motion unless it is acted upon by an external, unbalanced force. This means that force is the reason why motion starts or uniform motion is changed.
If a car is suddenly applies its brakes, the uniform motion of the car is disturbed and there is a tendency for the motion to continue according to Newtons first law hence the passengers moves forward. This is the reason why wearing a seat belt is important. The seat belt protects the passengers from being pushed out of the windscreen.
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Use the drop-down menus to complete the statements.
The amount of energy a wave carries corresponds to its
is equal to the number of wavelengths that pass a fixed point in a second.
Frequency is typically expressed in
Answer:
1st blank - amplitude
2nd blank - frequency
3rd blank - hertz
The amount of energy a wave carries corresponds to its amplitude. Frequency is equal to the number of wavelengths that pass a fixed point in a second. Frequency is typically expressed in hertz
crane lifts a 1,052 kg car. What force in Newtons must the crane apply to the car to lift it?
Answer:
10520 N
Explanation:
m = 1,052 kg
g = 10 m/s²
F = W = mg
F = 1052 × 10
F = 10520 N
The weight of an object is defined as the force of gravity on the object and may be calculated as the mass times the acceleration of gravity,
w = mg.
Since the weight is a force, its SI unit is the
newton.
For an object in free fall, so that gravity is the only force acting on it, then the expression for weight follows from Newton's second law: F = ma
An advantage of parallel circuits is that A. it is the simplest type of circuit to make. B. electrons can only take one path, so the flow of energy is always known. C. if one part of the circuit is not working, the other parts can still work. D. when one part of the circuit breaks, the whole circuit must be replaced.
Answer:
The answer is c
Explanation:
i can flyat a speed of 200m/s for 20 seconds. how far will i fly in that time
1.
A poorly tuned Yugo can accelerate from rest to a speed of 28 m/s in
20 s.
a) What is the average acceleration of the car?
b) What distance does it travel in this time?
Explanation:
Average acceleration is defined as the rate of change of velocity to the rate of change of period. Change of velocity refers to the difference between final velocity and initial velocity. The unit of acceleration is meter/sec/sec (or) m s^2.
Avg Acceleration=(Final velocity - Initial velocity) /(Final time - Initial time)
a. To find the average acceleration of the car, (initial velocity and initial time is 0, the final velocity is 28 m/s, final time = 20 s)
Avg acceleration of the car = (28 - 0) / (20 - 0)
= 28 / 20 = 1.4 m / s^2.
b. The distance traveled is given by the product of speed and time
Distance traveled = Speed * Time
The Distance traveled by the car = 28 * 20 = 560 m.
By applying basic physics formulas, the car's average acceleration can be determined as 1.4 m/s², and the distance it travels in 20 seconds is 280 meters.
Explanation:To answer this question, you'll need to apply basic physics formulas. Let's go step by step:
a) What is the average acceleration of the car?
Acceleration is defined as the rate of change of velocity per unit of time. The formula is Acceleration = (Final speed - Initial speed) / Time. Here, the initial speed is 0 (because the car is starting from rest), final speed is 28 m/s and time is 20 s.
So, Acceleration = (28 m/s - 0) / 20 s = 1.4 m/s². That's your answer for part a.
b) What distance does it travel in this time?
The distance traveled by the car can be found using the formula of linear motion: Distance = Initial speed x Time + 0.5 x Acceleration x Time². Since the car starts from rest, the initial speed is zero, and this component of the formula will be zero.
So, Distance = 0 + 0.5 x 1.4 m/s² x (20 s)² = 280 m. So, the car travels 280 meters in that time.
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You are at an office party, a holiday party, or a gathering of friends at the home of a neighbor and you are engaged in conversation with a friend in a discussion. More people are talking behind you, but you are not paying attention to their conversation. Suddenly, you hear your name mentioned by one of the individuals engaged in the conversation behind you. You become unable to concentrate on the discussion, because you are too busy trying to hear what the other people are saying about you. You know you were not deliberately eavesdropping on this conversation, but you know that you heard your name. Is it possible that you were unconsciously eavesdropping?
The correct answer is; Yes, you can be unconsciously eavesdropping.
Further Explanation:
When this occurs it is called the “The Cocktail Party Phenomenon.” Your mind can focus on one conversation that is being made and drown out all other speech and things going on around you. This makes your brain have auditory attention on one specific conversation.
The sensory hearing in the person listening to the conversation is subconsciously filtering the conversation into its own stream in the brain. This phenomenon can also detect certain words that are important to the person with a large amount of noise in the background.
This occurs in the left hemisphere of the brain in the superior temporal gyrus region.
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Final answer:
The experience you described is related to the cocktail party effect, a part of selective attention that allows us to focus on a conversation even in a noisy environment, while still unconsciously monitoring other auditory channels, including hearing one's own name.
Explanation:
Cocktail Party Phenomenon and Selective Attention
The situation you described typically relates to the cocktail party effect, which is a well-documented phenomenon in psychology. This effect explains how people can focus on a specific conversation in a noisy environment yet still notice when something salient, like their name, is mentioned elsewhere. It's a part of selective attention, allowing us to concentrate on a single source of input while still unconsciously monitoring other channels. The information overload at events such as parties necessitates this filtering mechanism, where our brains process background conversations without our active awareness. When your name is mentioned, it becomes a significant stimulus that captures your attention, indicating that some unconscious eavesdropping may occur as a byproduct of this natural cognitive process.
As mentioned by Broadbent (1958) and Cherry (1953), selective attention is not a complete exclusion of all background noise; it's a delicate balance that allows for focus while still keeping us connected to our surroundings. This phenomenon shows that even when you're engaged in conversation, you're unconsciously monitoring the environment around you, including the speech of others. Your brain is attending to more than you might realize, as it sifts through various sensory inputs to alert you to anything important—like the mention of your name.
What is the reason why feather falls at a slower rate than a Hammer on Earth not on the moon
A car accelerates uniformly from rest and reaches a speed of 33.5 m/s in 11.9 s. The diameter of a tire is 37.5 cm.
Find the number of revolutions the tire makes during this motion, assuming no slip- ping.
The number of revolutions the tire makes during this motion is 169.265 revolution.
Explanation:
Given:
Car’s initial velocity, u = 0
Car’s final velocity, v = 33.5 m/s
Time required t = 11.9 s
Hence, car’s acceleration ‘a’ can be given by the first equation of motion as
[tex]v=u+(a \times t)[/tex]
[tex]33.5=0+(a \times 11.9)[/tex]
[tex]11.9 \times a=33.5[/tex]
[tex]a=\frac{33.5}{11.9}=2.815 \mathrm{m} / \mathrm{s}^{2}[/tex]
The distance covered by the car during this time is given by the second equation of motion
[tex]s=(u \times t)+\left(\frac{1}{2} \times a \times t^{2}\right)[/tex]
[tex]s=0+\left(0.5 \times 2.815 \times 11.9^{2}\right)[/tex]
[tex]s=0.5 \times 2.815 \times 141.61=199.31 m[/tex]
Now as in each revolution a wheel rolling without slipping covers a distance equal to its periphery ([tex]2 \pi R[/tex]), if the total numbers of revolution of each tire be n, then we have
[tex]s=n \times 2 \pi R[/tex]
Given diameter, d = 37.5 cm = 0.375 m
Radius of the wheel, R = [tex]\frac{d}{2}=\frac{0.375}{2}=0.1875 \mathrm{m}[/tex]
Total numbers of revolution,
[tex]n=\frac{s}{2 \pi R}=\frac{199.31}{2 \times 3.14 \times 0.1875}=\frac{199.31}{1.1775}=169.265 \text { revolution }[/tex]
The car's tires make approximately 917 revolutions during the motion.
Explanation:To find the number of revolutions the tire makes during this motion, we need to first find the distance the car travels. We can use the formula s =[tex]ut + 1/2at^2[/tex]the distance, u is the initial velocity, a is the acceleration, and t is the time. In this case, the initial velocity is 0 m/s, the acceleration is the same as the car's acceleration, and the time is 11.9 s. Plugging in these values, we get:
s = 0(11.9) + 1[tex]/2(33.5)(11.9)^2[/tex]
The distance traveled is equal to the circumference of the tire multiplied by the number of revolutions. The circumference of the tire is equal to π times the diameter. Plugging in the values, we get:
2π(0.375) = 2.35619 m
Let's assume the number of revolutions is N. Therefore, the distance traveled can also be calculated as N times the circumference. Setting up the equation, we have:
N(2.35619) = 2156.29
Solving for N, we get:
N = 2156.29 / 2.35619 = 916.67
Therefore, the tire makes approximately 917 revolutions during this motion.
A 60-kilogram high jumper lands on a mat after her jump. The mat brings her to a stop after 1 second. She
was traveling at 5.0 m/sec when she landed on the mat. Note: The speed of the jumper at the top of her jump.
before she started to fall toward the mat, was 0 m/sec.
a. What is the change in momentum for the jumper?
b. What is the force felt by the jumper upon impact with the mat?
a) Change in momentum: -300 kg m/s
b) Force felt by the jumper: -300 N
Explanation:
a)
The change in momentum of an object is given by
[tex]\Delta p = m(v-u)[/tex]
where
m is the mass of the object
v is the final velocity
u is the initial velocity
For the jumper in this problem, we have
m = 60 kg (mass of the jumper)
v = 0 (final velocity is zero)
u = 5.0 m/s (initial velocity before he hits the mat)
Substituting,
[tex]\Delta p = (60)(0-5.0)=-300 kg m/s[/tex]
Where the negative sign means that the direction of the change in momentum is opposite to the direction of motion.
b)
According to the impulse theorem, the change in momentum of an object is equal to the impulse exerted on it:
[tex]\Delta p = F\Delta t[/tex]
where
F is the force exerted on the object
[tex]\Delta t[/tex] is the time interval
In this problem, we have
[tex]\Delta p = -300 kg m/s[/tex] (change in momentum)
[tex]\Delta t = 1 s[/tex] (duration of the collision)
Solving for F,
[tex]F=\frac{\Delta p}{\Delta t}=\frac{-300}{1}=-300 N[/tex]
Where the negative sign means that the direction of the force is opposite to the direction of motion.
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How much time does it take Mrs. Spencer to travel 240meters at a speed of 80meters per second?
Answer:
3seconds
Explanation:
it will take 3 seconds
The inside surface of the glass inside a vacuum bottle is coated with aluminum to prevent heat loss by ____.
Answer:
radiation
Explanation:
021 (part 1 of 2) 10.0 points
A student sits on a rotating stool holding two
4 kg objects. When his arms are extended
horizontally, the objects are 0.7 m from the
axis of rotation, and he rotates with angular
speed of 0.69 rad/sec. The moment of iner-
tia of the student plus the stool is 4 kg mº
and is assumed to be constant. The student
then pulls the objects horizontally to a radius
0.29 m from the rotation axis.
(D.
T
TZ
Calculate the final angular speed of the
student.
Answer in units of rad/s.
022 (part 2 of 2) 10.0 points
Calculate the change in kinetic energy of the
system.
Answer in units of J.
The problem involves using the principles of conservation of angular momentum and kinetic energy to find the student's final angular speed and the change in kinetic energy of the system when the radius at which weights are held is changed.
Explanation:The problem involves calculating the final angular speed of a student who pulls two objects closer while rotating on a stool and then determining the change in kinetic energy of the system. Using the principle of conservation of angular momentum, we can solve for the student's final angular speed after changing the radius at which the objects are held. The kinetic energy change relies on calculating the initial and final kinetic energies and finding their difference.
Without the complete calculations for this scenario, a precise final angular speed and kinetic energy change cannot be provided here. Typically, you would use the formula for angular momentum (L = Iω) where I is the moment of inertia and ω is the angular speed, and the formula for kinetic energy (KE = 0.5 * I * ω²) to solve these problems.
What impact has the use of optical fibre cables had on the way we receive and communicate information? Discuss both positive AND negative effects.
Due to rising demand for higher bandwidth and faster speed connections, fiber optic transmission is becoming more and more common in the developing world. Optical fiber has had a great impact on the way we receive and transmit signals. They have largely replaced copper wire communications in core networks in the developed world, because of its advantages over electrical transmission. But they brought some difficulties as well.
Following are the advantages and disadvantages of optical fiber:
Advantages
They provide extremely High Bandwidth.Optical fiber is capable of low power loss at long distances.Optical fiber is highly resistant to electromagnetic disturbances. They are virtually error free.The data is transferred through light that is why there is no security risk of data being detected.Optical fiber has lesser weight and size as compared to other cables.Disadvantages
They are made of glass that is why they are very fragile and they have to be handled carefully.They are difficult to install. If you bend them too much, they will break. And fiber cable is highly susceptible to damage during installation or construction activities.Extra optical components have to be added to handle dispersion of light at longer distances.Optical fiber costs a lot more than copper cables. The installation itself is very costly.Keywords: fiber optics, bandwidth, transmission, impact, advantages, disadvantages
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What is an independent variable?
The variable that is kept the same in the experiment.
The variable that the scientist change
The result of the experiment.
The data within the experimen
Answer:
variable that scientist change
Explanation:
Formulas (equations): A = 3x and B = 5x + 1
As x increases, does A or B go up faster?
if x=0, then A=?
if x=1 then B=?
Answer:
B goes up faster
if x=0, then A=0
if x=1 then B=6
Explanation:
Formulas Or Equations
We have two different formulas
A = 3x
B = 5x + 1.
They both are equations of lines. The number beside the X (coefficient) is also known as the slope of the line. The greater the slope, the faster the function goes up as X increases. We can clearly see that the equation B has a greater slope, which means it goes up faster than A as X increases
When x=0, A=3(0)=0
When x=1, B=5(1)+1=6
A load of mass 5kg is raised through a height of 2m. (g=10mls)
The gain in gravitational potential energy of the mass = 100 kg m^2 / s^2.
Explanation:
Gravitational potential energy is an energy in which an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the Earth's surface where the gravitational acceleration can be assumed to be constant at about 9.8 m/s2.
The formula for the gravitational potential energy is the product of mass, gravity, and height.
GPE = m *g *h
where m represents mass in kg,
g represents the gravity,
h represents the height.
GPE = 5 * 10 * 2 = 100 kg m^2 / s^2.
What type of mixture is salad dressing?
Answer:
Heterogeneous Mixture
Explanation:
Heterogeneous by definition is when two different substance are mixed together, but they are not evenly distributed. In this case, the salad dressing is a Heterogeneous Mixture, for the dressing does not mix completely evenly throughout the salad.
~
Beth exerts 14 N force to propel a 4.5 kg bowling ball down the lane
Answer:
It will have a certain kinetic energy at the beginning, but it will be lost by resistant work done by friction. Thus, itsmotion wil be uniformly decelerating.
Explanation:
A line on a speed-time graph with a steep slope indicates a greater speed
False: a line on a speed-time graph with a steep slope indicates a greater acceleration
Explanation:
In a speed-time graph, we have:
The time represented on the x-axisThe speed represented on the y-axisThis means that the slope of this graph is
[tex]m=\frac{\Delta y}{\Delta x}=\frac{\Delta v}{\Delta t}[/tex]
where
[tex]\Delta v[/tex] is the change in speed
[tex]\Delta t[/tex] is the change in time
However, acceleration is defined as
[tex]a=\frac{\Delta v}{\Delta t}[/tex]
where [tex]\Delta v[/tex] is the change in velocity. If we consider a motion in a straight line, the change in velocity corresponds to the change in speed: therefore, the slope of a speed-time graph corresponds (for a straight line motion) to the acceleration.
Therefore, the steeper the slope, the greater the acceleration of the body.
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At what speed would one need to fire a lead project tile in order for its temperature to rise from 25°C to 36.9°C upon impact on a stationary object
Answer:
55 m/s
Explanation:
If all kinetic energy is converted to heat:
½ mv² = mCΔT
v = √(2CΔT)
v = √(2 × 128 J/kg/K × (36.9°C − 25°C))
v = 55.2 m/s
Rounded to two significant figures, the speed is 55 m/s.
A clay ball with a mass of 0.50 kg is traveling at 5.7 m/s to the right and hits another clay ball that has a mass of 0.50 kg which is at rest. The two clay balls stick together and move as one. What is the velocity of the two balls?
Answer:
2.9 m/s to the right
Explanation:
Momentum before = momentum after
m₁ u₁ + m₂ u₂ = (m₁ + m₂) v
(0.50 kg) (5.7 m/s) + (0.50 kg) (0 m/s) = (0.50 kg + 0.50 kg) v
v = 2.85 m/s
Rounded to two significant figures, the velocity is 2.9 m/s to the right.
Find the acceleration of a car that can go from rest to 50 km/h in 13 s
The acceleration of the car is 1.067 m/[tex]s^{2}[/tex].
Explanation:
Acceleration is the measure of change in velocity experienced by any object for a given time period. So it is determined as the ratio of difference in the velocity to the time period.
As here the initial velocity is stated as zero, so u = 0. And the final velocity is termed as 50 km/h. Then we have to determine the acceleration in 13 s. So here we have to convert the units as common units. Thus, 50 km/h should be converted to m/s as [tex]\frac{50*1000}{3600}=13.88 m/s[/tex]
So now, the initial velocity u = 0 and final velocity v = 13.88 m/s and the time period is given as t = 13 s.
[tex]Acceleration = \frac{v-u}{t}=\frac{13.88-0}{13}=1.067 m/s^{2}[/tex]
So the acceleration of the car is 1.067 m/[tex]s^{2}[/tex].
Which kind of intelligence involves is the ability to hear pitch, tone, and rhythm?
Answer:
musical intelligence
Explanation:
The charged parts of the atom are the
Answer:
Proton and electron
Explanation:
An atom can be broken down into three constituents parts – protons, neutron, and electrons. Each of these parts has an associated charge, with protons carrying a positive charge, electrons having a negative charge, and neutrons possessing no net charge
For calculating work, the force and the distance must be in the same ____________.
For calculating work, the force and the distance must be in the same direction
Explanation:
The work done by a force on an object is given by the equation
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
The equation can be rewritten as
[tex]W=(F cos \theta) d[/tex]
where [tex]F cos \theta[/tex] is the component of the force parallel to the displacement of the object. This means that when calculating the work, only the component of the force parallel to the motion of the object contributes to the work: in this sense, we can say then for work to be different from zero, the force must have a component in the same direction as the motion of the object.
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Answer:
Direction
Explanation:
An eosinophil is a white blood cell involved in controlling infections. The white blood cell is a part of the ^____________ system, while the red blood cells are part of the ____________ system.
A immune, circulatory
B circulatory, respiratory
C immune, respiratory
D circulatory, immune
Answer:
A
Explanation: This isn't Physics, but there's your answer.
What is the change in internal energy if 30 J of thermal energy is released
from a system, and the system does 40 J of work on the surroundings? Use A
U= Q-W.
Answer:
ΔU = -70 J
Explanation:
ΔU = Q − W
where ΔU is the change in internal energy,
Q is the heat absorbed by the system,
and W is the work done by the system (on the surroundings).
30 J of thermal energy is released, so Q = -30 J.
40 J of work is done by the system, so W = 40 J.
Therefore, the change in internal energy is:
ΔU = -30 J − 40 J
ΔU = -70 J
Final answer:
The change in internal energy of the system is calculated using the formula
ΔU = Q - W. With 30 J of thermal energy released and 40 J of work done by the system, the internal energy decreases by 70 J.
Explanation:
Change in Internal Energy Calculation
To calculate the change in internal energy (ΔU) of a system, the first law of thermodynamics is often used, which is expressed as ΔU = Q - W, where Q is the heat added to the system, and W is the work done by the system on its surroundings. In this scenario, Q is a negative value since 30 J of thermal energy is released (or removed) from the system, which makes Q = -30 J. The system does 40 J of work on the surroundings; hence, W is also 40 J.
The change in internal energy is therefore calculated as follows:
ΔU = Q - W
ΔU = (-30 J) - (40 J)
ΔU = -30 J - 40 J
ΔU = -70 J
Thus, the change in internal energy of the system is -70 J, indicating that the internal energy of the system has decreased by 70 joules.
A 3.50 kg block of lead at 14.4°C comes in contact with a block of copper at 88.4°C. They come to equilibrium at 55.9°C. What was the mass of the copper block? (Unit=kg)
Answer:
1.48 kg
Explanation:
The conservation of energy states that energy cannot be created or destroyed but can be converted from one form to another. Hence, in this case, energy lost by the copper should equal to the energy gained by the lead. Hence,
Energy Lost by Copper = Energy Gained by Lead
mcT = mcT (Bolded is for copper, italicised is for lead)
m(387)(88.4 - 55.9) = (3.50)(128)(55.9 - 14.4)
12577.5m = 18592
m = 1.48 kg (3 sf)
(Note: Thermal energy can be calculated using Q = mcT where m is the mass, c is the specific heat capacity and T is the change in temperature)
Answer:
1.48 kg
Explanation:
What is the IMA of a lever whose resistance arm is 7cm long if the effort arm is 0.7m long and the load is 8.5N?
The IMA of the lever is 10
Explanation:
The IMA (Ideal Mechanical Advantage) of a simple machine is given by:
[tex]IMA=\frac{d_e}{d_r}[/tex]
where
[tex]d_r[/tex] is the length of the resistance arm
[tex]d_e[/tex] is the length of the effort arm
For the lever in this problem, we have:
[tex]d_r = 7 cm = 0.07 m[/tex] is the length of the resistance arm
[tex]d_e = 0.7 m[/tex] is the length of the effort arm
Substituting into the equation, we find the IMA of the lever:
[tex]IMA=\frac{0.7}{0.07}=10[/tex]
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A picture hanging on a wall has what energy.