evaluate √7x(√x-7√7

pls & thanks!

Answer:

Answer:

The height of the rocket after 3 seconds is 63 feet.

Step-by-step explanation:

The path of a model rocket is represented by:

[tex]h(t)=-t^2+20t+12[/tex]

where [tex]h(t)[/tex] represents the height in feet of rocket and [tex]t[/tex] represents time in seconds.

To find the height of the model rocket after 3 seconds from launch.

Solution:

In order to find the  height of the model rocket after 3 seconds from launch, we will plugin [tex]t=3[/tex] in the given function of path of rocket.

Thus, we have

[tex]h(3)=-(3)^2+20(3)+12[/tex]

[tex]h(3)=-9+60+12[/tex]

[tex]h(3)=63[/tex]

Thus, height of the rocket after 3 seconds is 63 feet.

Answer:

see them bellow

Step-by-step explanation:

Answer:

[tex]8b^2+7b-1=(b+1)(8b-1)[/tex]

The missing factor is: [tex](8b-1)[/tex]

Step-by-step explanation:

Given expression:

[tex]8b^2+7b-1=(b+1)(_-)[/tex]

To find the missing factor of the given expression.

Solution:

In order to factor the given term, we will split the middle term into two terms such that the product of the two terms is equal to the product of the first and last term of the expression.

The product of first and last term for the expression is = [tex](8b^2)(-1)=-8b^2[/tex]

The middle term = [tex]7b[/tex] which can be split into  [tex](8b-b)[/tex] as their product = [tex]-8b^2[/tex]

Thus, the expression can be rewritten as:

⇒ [tex]8b^2+8b-b-1[/tex]

We will factor in pairs by taking GCF.

⇒ [tex]8b(b+1)-1(b+1)[/tex]

Factoring the whole expression by taking the common factor.

⇒ [tex](b+1)(8b-1)[/tex]

Thus, the missing factor is: [tex](8b-1)[/tex]

Answer:

y=-3x+14

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-4-26)/(6-(-4))

m=-30/(6+4)

m=-30/10

m=-3

y-y1=m(x-x1)

y-26=-3(x-(-4))

y-26=-3(x+4)

y=-3x-12+26

y=-3x+14

Answer:

B. (-4,5)

Step-by-step explanation:

a function cannot have any repeating x values....it can have repeating y values, just not the x values

so..going by ur answer choices, u can remove (-4,5) and it would be a function. The reason is because u have two sets of points with the same x value...so it is not a function unless u take out either (-4,5) or (-4,3)...because they both have the same x value.

Answer:

They can never be both either increasing or decreasing.

Step-by-step explanation:

If the rate of change i.e. the slope of one linear function is positive, that means the graph of the linear function makes angle which varies between 0° to 90° with respect to the positive direction of the x-axis.

Therefore, the function must be increasing.

Again, if the rate of change i.e. the slope of one linear function is negative, that means the graph of the linear function makes angle which varies between 90° to 180° with respect to the positive direction of the x-axis.

Therefore, the function must be decreasing.

Hence, if the rate of change of one linear function is positive and for another is negative, they can never be both either increasing or decreasing. (Answer)

Answer:

0.072

Step-by-step explanation:

3/4 percent of the number 9.6 is 0.072.

Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".

Given that, 3/4% of 9.6.

Now, 0.75% of 9.6

= 0.0075×9.6

= 0.072

Therefore, 3/4 percent of the number 9.6 is 0.072.

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The solutions for the inequality y > (1/5)x + 3 exist in Quadrants I and II.

The inequality y > (1/5)x + 3 represents a line with a positive slope of 1/5.

The solutions for this inequality exist in the quadrants where y is greater than the value of (1/5)x + 3.

When x is positive and y is positive, the solutions exist in Quadrant I. When x is negative and y is positive, the solutions exist in Quadrant II.

Since the inequality is y > (1/5)x + 3 and not y >= (1/5)x + 3, the solutions do not exist in Quadrant III or IV where y would be negative.

Therefore, the solutions for the inequality y > (1/5)x + 3 exist in Quadrants I and II.

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Answer:

y-2=2(x-9)

Step-by-step explanation:

Perpendicular means negative reciprocal of the slope.

y-y1=m(x-x1)

y-2=2(x-9)

Answer:

4.5

Step-by-step explanation:

To find the instantaneous rate of chance, take the derivative:

[tex]f(x) = {x}^{2} - \frac{2}{x} - 1 \\ \frac{d}{dx} f(x) = 2x + \frac{2}{ {x}^{2} } [/tex]

Remember to use power rule:

[tex] \frac{d}{dx} {x}^{a} = a {x}^{a - 1} [/tex]

To differentiate -2/x, think of it as:

[tex] - 2 {x}^{ - 1} [/tex]

Then, substitute 2 for x:

[tex]2(2) + \frac{2}{ {2}^{2} } \\ 4 + \frac{2}{4} = 4.5[/tex]

Answer:

2

Step-by-step explanation:

Assuming the function is:

f(x) = (x² − 2) / (x − 1)

Use quotient rule to find the derivative.

f'(x) = [ (x − 1) (2x) − (x² − 2) (1) ] / (x − 1)²

f'(x) = (2x² − 2x − x² + 2) / (x − 1)²

f'(x) = (x² − 2x + 2) / (x − 1)²

Evaluate at x=2.

f'(2) = (2² − 2(2) + 2) / (2 − 1)²

f'(2) = (4 − 4 + 2) / 1

f'(2) = 2

Answer:

it is 4,000

Step-by-step explanation:

since you are rounding it to the nearest thousand, you loo at the 4, and the 2, the 2 is blow five, so it doesn't change the thousands place, but everything else becomes a 0

Answer: 4,000

Explanation: To round 4,279 to the nearest thousand, we first locate the digit in the rounding place which in this case is the 4 in the thousands place.

Next, we look at the digit to the right of the 4 which is 2. The rules of rounding tell us that if the digit to the right of the rounding place is less than 5, we round down and if the digit to the right of the rounding place is greater than or equal to 5, we round up.

In this problem, the digit to the right of the rounding place is less than 5 so we round down. This means that the 4 in the rounding place stays the same and all digits to the right of the 4 become zero.

Therefore, 4,279 rounded to the nearest thousand is 4,000.

Answer:

16 cm

Step-by-step explanation:

Let the width be x

The length will be 3 x since the length is three times the width

Perimeter=2(l+w) where l is length and w is width

By substituting 128 cm for perimeter, x for w and 3 x for l then

128=2(3x+x)

128=8x

[tex]x=\frac {128}{8}=16[/tex]

Therefore, the width is 16 cm, the width is 16*3=48 cm

The correct answer is:

The greatest possible width for the rectangle, with length three times, is 16 cm, ensuring the perimeter doesn't exceed 128 cm.

Let's denote:

- Width of the rectangle as [tex]\( w \)[/tex] cm

- Length of the rectangle as [tex]\( 3w \)[/tex] cm (since it is three times the width)

The perimeter of a rectangle is given by:

[tex]\[ \text{Perimeter} = 2 \times (\text{Length} + \text{Width}) \][/tex]

Given the perimeter is at most 128 cm, we can write:

[tex]\[ 2 \times (3w + w) \leq 128 \][/tex]

Now, let's solve for [tex]\( w \)[/tex]:

[tex]\[ 2 \times (3w + w) \leq 128 \]\[ 2 \times 4w \leq 128 \]\[ 8w \leq 128 \]\[ w \leq \frac{128}{8} \]\[ w \leq 16 \][/tex]

So, the width of the rectangle must be less than or equal to 16 cm. Therefore, the greatest possible value for the width is 16 cm.

Step-by-step explanation:

Wooden Cars = 2 × Wooden Trains

Ratio is

2 : 1

In total there are 3 parts

228 ÷ 3 = 76 (1 part)

Wooden Cars = 2 × 76 = 152

Wooden Trains = 1 × 76 = 76

To find the number of wooden trains made, we can set up an equation and solve for 'x'.

To solve this problem, let's represent the number of wooden trains as 'x'.

According to the given information, there are twice as many wooden cars as wooden trains. So, the number of wooden cars can be represented as '2x'.

We are also given that the total number of wooden vehicles made is 228.

Therefore, the equation that represents the given information is: x + 2x = 228

Simplifying the equation, we get: 3x = 228

Dividing both sides by 3, we find that x = 228/3 = 76

So, they made 76 wooden trains.

Answer:

Step-by-step explanation:

he uses 3/4 cup of butter in each batch...and he made 2 1/2 batches..

so he used :

2 1/2 * 3/4 =

5/2 * 3/4 =

15/8 =

1 7/8 cups of butter <====

A 5/3x3/4=1 7/8 because 15/8 is 5/3 x 3/4 = 1 7/8

Answer:

There was a 15 among the 7 numbers. That is the number you removed.

Step-by-step explanation:

x/7 = 9                       (1)

(x -  y)/6 = 8               (2)

Multiply 1 by 7

x/7 * 7 = 9*7

x = 63

Put 63 for x into equation 2

(63 - y)/6 = 8         Multiply by 6

6*(63-y)/6 =8*6

63 - y = 48            Add y to both sides

63-y+y = 48+y

63 = 48 + y           Subtract 48 from both sides

63-48=48-48+y

y = 15

Final answer:

The number removed from the list to change the average from 9 to 8 is 15, calculated by finding the difference between the total sum of the original and remaining lists.

Explanation:

To find the number that was taken away from a list when the average changes, you can first calculate the total sum of the original list, then the sum of the list after the number is removed.

Initially, the average of the 7 numbers is 9. To find the total sum of all 7 numbers, you multiply the average by the number of values.

Total sum of original list = 7 (number of values) × 9 (original average) = 63

After removing one of the numbers, the average of the 6 remaining numbers is 8.

Total sum of the remaining list = 6 (remaining values) × 8 (new average) = 48

The number that was removed can be found by subtracting the sum of the remaining list from the sum of the original list.

Number removed = Total sum of original list - Total sum of the remaining list = 63 - 48 = 15

Therefore, the number that was taken away from the list is 15.

Answer:

Julie made $3 /hour more than Loren

Step-by-step explanation:

Loren makes 18 /2 = 9 ($9 / hour constant ratio)

Julie: 36 /3 = 12 ($12 / hour)

Julie - Loren = 12 -9 = 3

? in Loren's : 126, 144

? in Julie's : 72, 252

The value of x when y = 9 is x = 2 or x = -2

Solution:

Given that value of y varies inversely as the square of x, and y=4, when x=3.

Therefore the initial statement is:

[tex]y \propto \frac{1}{x^{2}}[/tex]

To convert to an equation, multiply by k, the constant  of variation

[tex]y = k \times \frac{1}{x^2}[/tex]

[tex]y = \frac{k}{x^2}[/tex]  --- eqn 1

Given that,

y = 4 when x = 3

Now find value of k

[tex]4 = \frac{k}{3^2}\\\\4 \times 9 = k\\\\k = 36[/tex]

Find the value of x when y = 9

x = ?

y = 9

From eqn 1,

[tex]9 = \frac{k}{x^2}\\\\9 = \frac{36}{x^2}\\\\x^2 = 4\\\\x = \pm 2[/tex]

Thus value of x is found

Final answer:

To find the value of x when y=9 for a scenario where y varies inversely as the square of x, and given y=4 when x=3, we first determine the constant of variation and then solve for x, resulting in x=2.

Explanation:

The student's question concerns an inverse variation where the value of y varies inversely as the square of x, with an initial condition that when x=3, y=4. To find the value of x when y=9, we recall that an inverse variation can be expressed as y = k/x², where k is a constant. Using the given condition, we can solve for k: 4 = k/3², leading to k = 36. To find x when y=9, we set up the equation 9 = 36/x² and solve for x, yielding x = 2.

Answer:

10 rectangles can fit in the square that has one side 10 cm long.

Step-by-step explanation:

Given:

Rectangle 5 cm multiply 2 cm .

Square that has one side 10cm long.

Now, to find the number of rectangle that can fits in the square.

So, for getting the number of rectangle we need to get the area first:

Area of rectangle as given 5 cm multiply 2 cm :

[tex]5\ cm\times 2\ cm=10\ cm^2[/tex]

Then the area of square as given side is 10 cm:

Area of square = (side)²

[tex]Area\ of\ square=10^2[/tex]

[tex]Area\ of\ square=100\ cm^2[/tex]

Now, for getting the number of rectangle we divide the area of square by area of rectangle:

Number of rectangle = Area of square ÷ Area of rectangle

[tex]Number\ of\ rectangle=100\ cm^2\div 10\ cm^2[/tex]

[tex]Number\ of\ rectangle=10.[/tex]

Therefore, 10 rectangles can fit in the square that has one side 10 cm long.

Answer:

4875

Step-by-step explanation:

100%-84%=16%

16%x=780

x=4875

Answer:

14

Step-by-step explanation:

Squaring a number (a+b) for example is a^2+2ab+b^2. So you square root x^2 and 49, you get x and seven respectively. you multiply them together and on top of that multiply the product by 2. so 7x*2 is 14x and ye

Answer: 1,602 Crayons with old labels that the company has in stock

Step-by-step explanation:

The total is 2,776 and 1,174 of the total have new labels so you would have to subtract 1,174 from 2,776. Your welcome

Answer:

The total cost to make 3 widgets is $64.

Step-by-step explanation:

As cost is give by quadratic function such as [tex]c(x) = ax^2 + bx + d[/tex]

As it costs $29 to produce 2 widgets. So,

[tex]c(2) = a(2)^2 + b(2) + d[/tex]

[tex]29= 4a+2b+d ....[A][/tex]

As it costs $115 to produce 4 widgets. So,

[tex]c(4) = a(4)^2 + b(4) + d[/tex]

[tex]115= 16a+4b+d ....[B][/tex]

As it costs $757 to produce 10 widgets. So,

[tex]c(10) = a(10)^2 + b(10) + d[/tex]

[tex]757= 100a+10b+d ....[C][/tex]

In order to find the values of a, b, c and d, we have to equations [A], [B] and [C]

Subtracting Equation [A] from [B] and [B] from [C]

 12a + 2b = 86  ........[D]

 84a + 6b = 642  ........[E]

Multiplying Equation [D] by 3 and subtracting from [E]

84a + 6b + 3(12a + 2b) = 642 - 86

48a = 384

a = 8

Putting value of a = 8 in equation [D]

12(8) + 2b = 86

96 + 2b = 86

2b = -10

b = -5

Substituting the value of a = 8 and b = -5 in Equation [A].

29= 4a+2b+d

29 = 4(8) + 2(-5) + d

29 = 32 - 10 + d

d = 29 + 10 - 32

d = 7

The required form of equation can be obtained by substituting a = 8, b = -5 and d = 7 in the cost equation. So,

[tex]c(x) = 8x^2 - 5x + 7[/tex] is the required form of equation.

Therefore, the total cost to make 3 widgets will be:

Putting x = 3 in [tex]c(x) = 8x^2 - 5x + 7[/tex]

[tex]c(3) = 8(3)^2 - 5(3) + 7[/tex]

[tex]c(3) = 72 - 15 + 7[/tex]

[tex]c(3) = 64[/tex]

Hence, the total cost to make 3 widgets is $64.

Keywords: quadratic equation, cost

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Answer:[tex]30 i -473 j -3 k[/tex]

Step-by-step explanation:

We are given two velocity vectors with its three components in unit notation:

Airplane's velocity:

[tex]\vec{p}=30i-492j+42k[/tex]

Crosswind velocity:

[tex]\vec{t}=0i+19j-45k[/tex]

Now, if we want to know the velocity of the airplane when it is affected by the wind, we have to add these two velocity vectors:

[tex]\vec{p} + \vec{t}=(30i-492j+42k) + (0i+19j-45k)[/tex]

Adding both vectors:

[tex]\vec{p} + \vec{t}=30i-473j-3k[/tex]

Answer:

D edge

Step-by-step explanation:

The equation that represents the relationship between the remaining balance on Renata's gift card and the number of songs purchased is y = 20 - 1.25x, where x represents the number of songs purchased.

The equation that represents the relationship between the remaining balance on Renata's gift card and the number of songs purchased is y = 20 - 1.25x.

Here's how we get to this equation:

For example, if Renata purchased 16 songs, the equation becomes y = 20 - 1.25(16) = 20 - 20 = 0, which matches the given information that the gift card has a remaining balance of $0 after 16 songs are purchased.

Problem 1

--------------

Work Shown:

For any convex polygon, the sum of the exterior angles is always 360 degrees

Add up all the angles shown, set the sum equal to 360, then solve for v.

9v+(19v-21)+45+(v+48)+7v = 360

36v+72 = 360

36v+72-72 = 360-72

36v = 288

36v/36 = 288/36

v = 8

===============================================

Problem 2

--------------

Explanation:

Segment WU is not an altitude because we have no angle markers to show if WU is perpendicular to VT.

Segment WU is not a median since we dont know if TU = UV or not.

Segment WU is not an angle bisector. If it were an angle bisector, then the two angles marked (33 and 40) should be equal angles. In other words, an angle bisector cuts an angle into two equal halves.

Answer:

um whats the question

Step-by-step explanation:

Answer:

your answer is option A

Answer:

A is the correct answer... ten hundreths thousandths

βrainliest pleaseeeeeeeeeeeee

Solution: [tex]\frac{12}{13}[/tex]. The cosine of an acute angle of a right triangle is the adjacent side divided by the hypotenuse.

Answer:

3: 6,9,12,15,18,21 and 24.

7: 14,21,28,35,42,49 and 56.

5: 10,15,20,25,30,35 and 40.

9: 18,27,36,45,54,63 and 72

4: 8,12,16,20,24,28 and 32.

Step-by-step explanation:

Given are the number at the beginning of each strings.

We need to write multiples of number on first light of string on rest of lights on the string.

3: [tex]3\times 1= 3 (given)[/tex]

[tex]3\times 2= 6\\3\times 3= 9\\3\times 4= 12\\3\times 5= 15\\3\times 6= 18\\3\times 7= 21\\3\times 8= 24[/tex]

7: [tex]7\times 1= 7 (given)[/tex]

[tex]7\times 2= 14\\7\times 3= 21\\7\times 4= 28\\7\times 5= 35\\7\times 6= 42\\7\times 7= 49\\7\times 8= 56[/tex]

5: [tex]5\times 1= 5 (given)[/tex]

[tex]5\times 2= 10\\5\times 3= 15\\5\times 4= 20\\5\times 5= 25\\5\times 6= 30\\5\times 7= 35\\5\times 8= 40[/tex]

9: [tex]9\times 1= 9 (given)[/tex]

[tex]9\times 2= 18\\9\times 3= 27\\9\times 4= 36\\9\times 5= 45\\9\times 6= 54\\9\times 7= 63\\9\times 8= 72[/tex]

4: [tex]4\times 1= 4 (given)[/tex]

[tex]4\times 2= 8\\4\times 3= 12\\4\times 4= 16\\4\times 5= 20\\4\times 6= 24\\4\times 7= 28\\4\times 8= 32[/tex]