Calculate the volume in liters of a 0.360 mol/l barium acetate solution that contains 100.g of barium acetate (Ba(C2H3O2)2) . Round your answer to 3 significant digits.

Answers

Answer 1

Answer:

1.08 liters is the volume of 100 g of Ba(CH₃COO)₂

Explanation:

This data is a sort of concentration (Molarity) → 0.360 M [Ba(CH₃COO)₂]

It means that 0.36 moles of solute are contained in 1L of solution.

We should determine the moles of salt, that corresponds to 100 g of solute.

Mass / Molar mass

Ba(CH₃COO)₂ molar mass = 255.3 g/m

100 g / 255.3 g/m = 0.391 moles

So, we can apply a rule of three to calculate the volume of salt.

0.360 moles of solute are contained in 1L of solution

0.391 would be contained in (0.391 .1) / 0.360 = 1.08 liters


Related Questions

The average radius of a molecule of lysozyme, an enzyme in tears, is 1430. pm. What is its radius in centimeters (cm)? (Enter your answer in scientific notation.)

Answers

Answer:

1.43 ×10⁻⁷ cm

Explanation:

Scientific notation is the way to express the large value in short form.

The number in scientific notation have two parts.

The digits (decimal point will place after first digit)

× 10 ( the power which put the decimal point where it should be)

for example the number 6324.4 in scientific notation will be written as = 6.3244 × 10³

Radius of molecule of lysozyme:

1430 pm

In centimeter:

1430/10¹⁰

1.43 ×10⁻⁷ cm

The expanded notation is standard notation of writing the numerical values which is normal way. The numbers are written as they are, without the power of 10 such as, 1430 pm.

Draw the major organic product in the reaction scheme below. Be sure to clearly show stereochemistry (if applicable).

Answers

Answer:

see explanation below

Explanation:

You are missing the reaction scheme, but in picture 1, I found a question very similar to this, and after look into some other pages, I found the same scheme reaction, so I'm gonna work on this one, to show you how to solve it. Hopefully it will be the one you are asking.

According to the reaction scheme, in the first step we have NaNH2/NH3(l). This reactant is used to substract the most acidic hydrogen in the alkine there. In this case, it will substract the hydrogen from the carbon in the triple bond leaving something like this:

R: cyclopentane

R - C ≡ C (-)

Now, in the second step, this new product will experiment a SN2 reaction, and will attack to the CH3 - I forming another alkine as follow:

R - C ≡ C - CH3

Finally in the last step, Na in NH3 are reactants to promvove the hydrogenation of alkines. In this case, it will undergo hydrogenation in the triple bond and will form an alkene:

R - CH = CH - CH3

In picture 2, you have the reaction and mechanism.

Final answer:

This is a question in Organic Chemistry that requires the student to draw the major product of an organic reaction scheme with clear display of stereochemistry if necessary. It entails simplifying larger molecules using line-angle structures and understanding the arrangement of reactants and products in a chemical equation.

Explanation:

The subject of this question is in the discipline of

Chemistry

, specifically the area of

Organic Chemistry

. The task at hand is to draw the major product of an organic reaction scheme while demonstrating clear understanding of stereochemistry, if applicable. In Organic Chemistry, skeletal structures or line-angle structures are often employed to simplify the schematic representation of larger molecules. Here, carbon atoms are delineated by each end of a line or bend in a line. Hydrogen atoms, if attached to a carbon, are typically not drawn while other atoms are represented by their elemental symbols. Also, understanding the importance of the arrangement of reactants and products in a chemical equation is fundamental in reaction

stoichiometry

, which allows us to predict the direction and extent of a reaction. Regarding stereochemistry, it is the study of the three-dimensional structure of molecules. It is important when a molecule features chiral centers (carbon atoms connected to four different groups) because the orientation of these groups in space can lead to different products, known as stereoisomerism.

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If a sample of gas is located 10.2 cm from the injection point and the chart speed is 0.5 cm/min, what is the retention time?

Answers

Answer : The retention time is, 20 min

Explanation :

Retention time : It is defined as the amount of time a compound spends on the column after it has been injected.

Formula of retention time is:

[tex]\text{Retention time}=\frac{\text{Distance from injection point to center of peaks}}{\text{Chart recorded speed}}[/tex]

Given:

Distance from injection point to center of peaks = 10 cm

Chart recorded speed = 0.5 cm/min

Now put all the given values in the above formula, we get:

[tex]\text{Retention time}=\frac{10cm}{0.5cm/min}[/tex]

Retention time = 20 min

Thus, the retention time is, 20 min

Select the substance that has the higher boiling point. Select the substance that has the higher boiling point. a)C3H8 b)CH3Oc)CH3

Answers

The question is incomplete. Here is the full version

Select the substance that has the higher boiling point. Select the substance that has the higher boiling point. a)C3H8 b)CH3OH c)CH3OCH3

Answer:

b)CH3OH

Explanation:

a)C3H8 The dominant intemolecular force here are London dispersion forces.

             Dipole-dipole forces cancel out because the molecule is symmetric  

b)CH3OH  - The dominant intermolecular force is hydrogen bonding

c)CH3OCH3 - The dominant intemolecular force here are London

                       dispersion forces. Dipole-dipole forces cancel out because

                       the molecule is symmetric

Which situation would violate the octet rule?
3 bonds to boron
3 bonds to and a lone pair on oxygen
5 bonds to carbon
3 bonds to carbon

Answers

Answer:

Explanation:

According to octet rule there should be 8 electrons in the atom's subshell/valence shell. Giving it the same electronic configuration as a noble gas.

among the options:

c) option is correct, as 5 bonds to carbon is violating the octet Rule, 5 bonds means 10 electrons exceeding the noble gas configuration and violets the octet rule.

All the other options are are incorrect, they are following

octet rule. Three bonds of carbon is possible in the case of carbocation.

This alkene can be prepared via Wittig reaction. Draw structural formulas for the aldehyde and the Wittig reagent.

Answers

Final answer:

In a Wittig reaction, the structure of the desired alkene determines the structure of your starting aldehyde and Wittig reagent. The one (aldehyde or ketone) contains the carbonyl group that will form one half of the carbon-carbon double bond in the alkene, and the other (Wittig reagent) provides the rest of the alkene structure.

Explanation:

The

Wittig reaction

is a method used in organic chemistry to create carbon-carbon double bonds (alkenes) from carbonyl compounds (such as aldehydes or ketones) and phosphonium ylides (a compound of a phosphorus cation and an organometallic compound). So, if you have a desired alkene you want to produce, you can actually reverse engineer what ingredients you need for this reaction. The carbon skeleton of the aldehyde and the Wittig reagent are directly related to the resulting alkene. The aldehyde or ketone compound will contain the carbonyl group (C=O) which will form one side of the carbon-carbon double bond in the alkene. The remainder of the alkene structure will be derived from the phosphonium ylide, the Wittig reagent. As an example, if you wanted to prepare 1-hexene, you would use hexanal as your aldehyde and methylenetriphenylphosphorane as your Wittig reagent.

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Final answer:

The Wittig Reaction is used to synthesize alkenes from aldehydes using a reagent known as a Wittig reagent. The Wittig reagent reacts with the aldehyde to create an intermediate molecule that eventually forms the alkene after the expulsion of a leaving group.

Explanation:

The Wittig reaction is a chemical reaction used to synthesize alkenes from aldehydes or ketones using a triphenyl phosphonium ylide, commonly known as a Wittig reagent.

In the most basic form of this reaction, an aldehyde is converted into an alkene through a series of steps. First, the Wittig reagent is prepared from a phosphonium salt, which when deprotonated by a base, forms a ylide or Wittig reagent. This reagent then reacts with the aldehyde in what's known as a [2+2] cycloaddition to form an oxaphosphetane intermediate, which then undergoes a reaction known as a retro-[2+2] cycloaddition to expel triphenylphosphine oxide, resulting in the formation of the alkene.

Without the exact structure of the desired alkene, it is impossible to provide the exact structures for the aldehyde and Wittig reagent, but hopefully, this general explanation of the reaction can assist you in figuring it out for your specific case.

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A sample of nitrogen gas occupies 1.55 L at 27.0°C and 1.00 atm. What will the volume be at −100.0°C and the same pressure?

Answers

Answer:

0.89L ( 2 decimal place)

Explanation:

Using Combined Gas law.

( P₁V₁)/T₁ = (P₂V₂) / T₂

P₁ = 1.00 atm

V₁ = 1.55L

T₁ = 27.0 °C = converting to kelvin ( 27 + 273k) = 300k

P₂ = same as P₁ = 1.00 atm

V₂ = ?

T₂ = -100°C = converting to kelvin ( -100 + 273k) = 173k

(1 x 1.55)/300 = (1 x V)/173

1.55/300 = V/173

V / 173 = 0.00516666666

V = 173 x 0.00516666666 = 0.89383333333 ≈ 0.89L ( 2 decimal place)

Answer:

The volume at -100 °C is 0.894 L

Explanation:

Step 1: Data given

The initial volume = 1.55L

The initial temperature = 27.0 °C = 300 K

The pressure is 1.00 atm and stays constant

The temperature lowers to -100 °C = 173 K

Step 2: Calculate the volume

V1 / T1 = V2 / T2

⇒ with V1 = the initial volume = 1.55L

⇒ with T1 = the initial temperature = 300 K

⇒ with V2 = The new volume = TO BE DETERMINED

⇒ with T2 = the final temperature = 173 K

1.55 / 300 = V2 /173

V2 =  0.894 L

The volume at -100 °C is 0.894 L

When NH4NO3­ spontaneously dissolves in water the temperature of the solution decreases. What factors make this a naturally occurring process?

Answers

Explanation:

Once solid ammonium nitrate interacts with water, the molecules of polar water intermingle with these ions and attract individual ions from the structure of the lattice, that actually will break down. E.g;-NH4NO3(s) — NH4+(aq)+ NO3-(aq) To split the ionic bonds that bind the lattice intact takes energy that is drained from the surroundings to cool the solution.

Some heat energy is produced once the ammonium and nitrate ions react with the water molecules (exothermic reaction), however this heat is far below that is needed by the H2O molecules to split the powerful ionic bonds in the solid ammonium nitrate.

Hence, we can say that the dissolution of ammonium nitrate in water is highly endothermic reaction.

What the sample will look like after the temperature is increased from 300 K to 450 KK at constant pressure?

Answers

Answer:

The sample will look expanded and occupy more space.

Explanation:

Since, the pressure is constant here, but the temperature is changed. Therefore, according to Charles' Law Volume is directly proportional to Temperature, provided the pressure is kept constant. Mathematically:

V1/T1 = V2/T2

V1 = (T1/T2)(V2)

V1 = (300 k/450 k)(V2)

V1 = (0.67)V2

The equation indicates that The fina volume of the gas V2 will be greater than the initial volume V1. Thus, sample will look expanded and occupy more space than the previous state.

A hot toluene stream, which has mass flow rate of 8.0 kg/min, is cooled by cooling water in a cocurrent heat exchanger; its temperature drops from 90o C to 60o C after passing through the heat exchanger. The cooling water stream has a mass flow rate of 10 kg/min and an inlet temperature of 20o C. Given that the specific heats of toluene and water are 0.41 and 1.00 kcal/(kg.o C), respectively, determine (a, 3%) the heat duty of the heat exchanger, (b,3%) the temperature of the cooling water leaving the heat exchanger, (c, 3%) the log mean temperature difference (or "driving force") for the heat exchange process, and (d, 3%) the UA value of the heat exchanger. Assume a negligible heat loss to the surroundings.

Answers

Complete Question  

The complete question is shown on the first question

Answer:

a) The duty of the heat exchanger is given as 6.8658 KJ /sec

b) The temperature of the water leaving the exchanger is TOUT = 29.84 ⁰C

c) The log mean difference is given as TZ = 47.317 ⁰ C

d) the UA value is UA = 145.10

Explanation:

The explanation is uploaded on the first and second ,third and fourth image

The molecules of a gas at constant volume are somehow given a lower average kinetic energy.
What two measurable properties of the gas will change and in what direction?

Answers

Answer:

Kinetic energy is proportional to temperature. An increase in the average kinetic energy, decrease the temperature and vice versa. pressure and temperature have a direct relationship between them, if temperature decreases, pressure also decreases and vice versa.

Explanation:

This concept is explained by taking into consideration the gas laws; GayLussac's law of combining volume and charles's law . considering the molecules of a gas at constant volume, there is a direct relationship between the pressure and temperature at constant volume, this is what gay lussac's law entails i.e gases who combine at constant volume they do so in fixed ratio and to the volume of their container.

As for charles's law, there exist a Volume - Temperature relationship at constant pressure, because volume and temperature have a direct relationship, when the average kinetic energy of gas molecules is decreased, this in turn decreases the temperature of the gas molecules.

And when the temperature decreases as a result of decrease in the average kinetic energy, this automatically affect the pressure thereby causing a reduction in the pressure of the gas container.

However, if the average kinetic energy of the gas molecules is increased again, then there will be an increase in the temperature and pressure and vice versa. Kinetic energy and temperature also have a direct relationship.

Final answer:

When the average kinetic energy of a gas at constant volume is decreased, the temperature and pressure of the gas will also decrease due to fewer and less forceful collisions of molecules with the container walls.

Explanation:

If the molecules of a gas at constant volume are given a lower average kinetic energy (KEavg), two measurable properties of the gas that will change are the pressure and temperature of the gas. A decrease in the average kinetic energy of gas molecules, which is directly proportional to the gas's absolute temperature, leads to a lower temperature. As the kinetic energy decreases, molecules move slower, resulting in fewer collisions with the walls of the container. This decrease in collision frequency and force leads to a decrease in gas pressure. The direction of these changes is downward; both temperature and pressure will decrease.

Under what condition will the change in enthalpy equal the change in internal energy for a given chemical system?

Answers

Explanation:

The change in enthalpy of a system when a chemical reaction occurs is equal to to change in internal energy of the system added to the change in the product of Volume times pressure of the system.

Now, change in enthalpy equal the change in internal energy for a given chemical system when the product of volume time pressure is Zero. That neither the does any work nor any work in done on the system.

Final answer:

The change in enthalpy will equal the change in internal energy for a given chemical system when the process occurs at constant pressure and no work is done other than pressure-volume work. This is due to the first law of thermodynamics.

Explanation:

The change in enthalpy (ΔH) for a given chemical system will equal the change in internal energy (ΔU) under the condition that the process occurs at constant pressure and there is no work being done other than pressure-volume work. In other words, ΔH = ΔU + PΔV, and if PΔV = 0 (no work other than pressure-volume work), then ΔH = ΔU. This is based on the first law of thermodynamics, which states that the total energy of a system is constant unless added or removed by work or heat transfer.  For instance, in a constant pressure chemical reaction in a sealed container, the change in enthalpy would effectively equal the change in internal energy.

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Write a possible full set of quantum numbers for the electron gained when a bromine atom (Br) becomes a bromide ion (Br^−).

Answers

Answer:

The answer is n = 4 , l = 1, m= +1 , ms = -1/2

Explanation:

When br atom gains one electron its atomic number becomes

36 br = 35

electronic config. = [ar] 3d 104s 24p5 br- = 36 = [ar] 3d 104s 24p6

so the electron goes into 4p that means

n = 4 , l = 1, m= +1 , ms = -1/2

Based upon the intermolecular forces present, rank the following substances according to the expected boiling point for the substance.
Rank from highest to lowest boiling point. To rank items as equivalent, overlap them.
HCl, NaCl, N2, H2O

Answers

Final answer:

Boiling points of substances are dependent on the strength of their intermolecular forces. NaCl, with the strongest ionic bonds, has the highest boiling point, followed by H2O with hydrogen bonds, then HCl with dipole-dipole interactions, and finally N2 with the weakest van der Waals forces.

Explanation:

The subject of this question is

intermolecular forces

and their impact on the boiling point of different substances. Boiling points are determined based on the strength of these forces. The stronger the intermolecular forces, the more energy is needed to break them, leading to a higher boiling point.

NaCl

, sodium chloride, has ionic bonds, which are the strongest of the intermolecular forces, so it has the highest boiling point.

H2O

, water, has hydrogen bonds, which are the next strongest, so it comes next.

HCl

, hydrogen chloride, has dipole-dipole interactions, weaker than ionic or hydrogen bonding, hence a lower boiling point than NaCl or H2O. Finally,

N2

, nitrogen, with its weakest van der Waals forces has the lowest boiling point. So the order from highest to lowest boiling point is: NaCl, H2O, HCl, N2.

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What mass (in g) of KIO3 is needed to prepare 50.0 mL of 0.20 M KIO3? b) What volume (in mL) of 0.15 m H2SO4 is needed to prepare 50.0 mL of 0.080 M H2SO4?

Answers

Final answer:

To prepare a 0.20 M KIO3 solution, 2.14 g of KIO3 is required for 50.0 mL. For the 0.080 M H2SO4 solution, 26.7 mL of 0.15 M H2SO4 is needed to dilute to 50.0 mL.

Explanation:

To calculate the mass (in g) of KIO3 needed to prepare 50.0 mL of a 0.20 M solution, use the formula:

mass = molarity × volume × molar mass

We begin by calculating the moles of KIO3 needed:

Moles of KIO3 = Molarity × Volume (in L)

= 0.20 mol/L × 0.0500 L = 0.010 moles of KIO3

The molar mass of KIO3 is K (39.10 g/mol) + I (126.90 g/mol) + 3×O (3× 16.00 g/mol) = 214.00 g/mol.

Now calculate the mass:

Mass of KIO3 = Moles × Molar Mass

= 0.010 moles × 214.00 g/mol = 2.14 g

For the second part, to find the volume (in mL) of 0.15 M H2SO4 needed to prepare 50.0 mL of a 0.080 M solution, we use the dilution formula:

M1V1 = M2V2, where M is molarity and V is volume.

The initial molarity (M1) is 0.15 M, the final molarity (M2) is 0.080 M, and the final volume (V2) is 50.0 mL. We solve for V1:

V1 = (M2V2) / M1

= (0.080 M × 50.0 mL) / 0.15 M = 26.7 mL

Accordingly, you would need 26.7 mL of the 0.15 M H2SO4.

For the data set: 0.09, 0.10, 0.11, 0.13, 0.09, 0.11, 0.10, 0.07 To obtain information of the precision of the data set the standard deviation would be:

a. 0.018
b. 0.022
c. 0.0166
d. 0.01

Answers

Answer:

Option A is correct (0.018)

S.D≅0.018

Explanation:

Option A is correct (0.018)

General Formula for Standard Deviation is:

[tex]Standard\ Deviation=\sqrt{\frac{\sum_{i=1}^{n}(x_{i}-\bar x)^2}{n-1}}[/tex]

Where:

[tex]x_{i}[/tex] is the data value

[tex]\bar x[/tex] is the mean/average of data

n is the total number of data elements

Calculating [tex]\sum_{i=1}^{n}(x_{i}-\bar x)^2}[/tex]

[tex]\bar x=\frac{0.09+0.10+ 0.11+ 0.13+ 0.09+ 0.11+ 0.10+0.07}{8} \\\bar x=0.1[/tex]

[tex]\sum_{i=1}^{n}(x_{i}-\bar x)^2}=(0.09-0.1)^2+(0.1-0.1)^2+(0.11-0.1)^2+(0.13-0.1)^2+(0.09-0.1)^2+(0.11-0.1)^2+(0.1-0.1)^2+(0.07-0.1)^2\\\sum_{i=1}^{n}(x_{i}-\bar x)^2}=2.2*10^{-3}[/tex]

Calculating n-1:

Total number of terms=8

n-1=8-1=7

Standard Deviation is:

[tex]S.D=\sqrt{\frac{2.2*10^{-3}}{7}}\\S.D=0.0177[/tex]

S.D≅0.018

The pH of a 0.23M solution of acrylic acid HC3H3CO2 is measured to be 2.44. Calculate the acid dissociation constant Ka of acrylic acid. Round your answer to 2 significant digits. Step by step would be helpful...

Answers

Answer:

Kₐ =  5.7 x 10⁻⁵

Explanation:

The equilbrium for this acid is

HC₃H₃CO₂ + H2O    ⇄ H₃O⁺  +   C₃H₃CO₂ ⁻  ,

and the equilibrium constant for acrylic acid is given by the expression:

Kₐ = [ H₃O⁺][ C₃H₃CO₂⁻ ] / [ HC₃H₃CO₂ ]

Since  the pH of the 0.23 M solution is known , we can calculate [ H₃O⁺].

The ][ C₃H₃CO₂⁻ ]  is equal to  [ H₃O⁺] from the above equilibria (1:1)

Finally [ HC₃H₃CO₂ ] is known.

pH = - log  [ H₃O⁺]

taking antilog to both sides of the equation

10^-pH =  [ H₃O⁺]

Substituting

10^-2.44 =  [ H₃O⁺]  = 3.6 x 10⁻³

[ C₃H₃CO₂⁻ ] = 3.6 x 10⁻³

Kₐ = ( 3.6 x 10⁻³ ) /0 .23 = 5.7 x 10⁻⁵

Final answer:

To find the Ka of acrylic acid, we use the measured pH to find [H+], set up an ICE table for the dissociation equilibrium, and solve for Ka, which is approximately 5.8 x 10^{-5} when rounded to two significant digits.

Explanation:

To calculate the acid dissociation constant (Ka) of acrylic acid, we start by using the pH given. The pH is defined as the negative logarithm of the hydrogen ion concentration ([H+]), which can be represented as pH = -log[H+]. From the pH of 2.44, we find the concentration of hydrogen ions:

[H+] = 10^{-pH} = 10^{-2.44} ≈ 3.63 × 10^{-3} M

Given that acrylic acid (HC3H3CO2) is a weak acid and only partially dissociates in a solution, we can represent its dissociation as follows:

HC3H3CO2(aq) ⇌ H+(aq) + C3H3CO2⁻(aq)

The ICE table approach details the initial concentrations, the change in concentrations, and the final concentrations. For acrylic acid, we get:

Initial: [HC3H3CO2] = 0.23 M, [H+] = 0, [C3H3CO2⁻] = 0Change: [HC3H3CO2] decreases by x, [H+] increases by x, [C3H3CO2⁻] increases by xEquilibrium: [HC3H3CO2] = 0.23-x M, [H+] = x , [C3H3CO2⁻] = x

Since the pH corresponds to the hydrogen ion concentration at equilibrium, we also know that x (the increase in [H+]) is equal to 3.63 × 10^{-3} M. Now we can calculate the Ka using the equilibrium expressions:

Ka = \frac{[H+][C3H3CO2⁻]}{[HC3H3CO2]}

Assuming x is small compared to the initial concentration, we can simplify [HC3H3CO2] to be approximately equal to 0.23 M:

Ka ≈ \frac{(3.63 × 10^{-3})^2}{0.23}

Thus, Ka ≈ 5.76 × 10^{-5}. Rounded to two significant digits, Ka ≈ 5.8 × 10^{-5}.

water has a heat of vaporization and boils at 100. what is the boiling point of water at the top of mount everest where the atmospheric pressure is only 34 as stong as the pressure at sea level

Answers

Answer: 71°C

Explanation: Liquids tends to boil when their vapour pressure equals atmospheric pressure. As we go higher, the atmospheric pressure reduces. Since Everest is at high altitude, water will boils at a much lower value.

From the list of the instructions and tips below, select the statement that would NOT lead to a successful recrystallization O Dry the crystals by pulling air through after vacuum filtration (to help them dry). O Keep the crystals open to the air for quite a while during the drying step. O Precipitate the crystals as fast as possible. O Rinse the crystals on the filter with a small amount of the ice-cold solvent. O Use a very small amount of ice-cold solvent and a spatula to remove any crystals left in the flas

Answers

Answer:

C. Precipitate the crystals as fast as possible

Explanation:

C. Precipitate the crystals as fast as possible

Precipitation if done fast , can lead to the formation of impure crystals , as impurities also get stuck inside the crystals. So it must be done slowly to obtain the pure crystals . Slower the crystals form , purer they are .

All the other options can lead to a successful recrystallization.  

Final answer:

The statement 'Precipitate the crystals as fast as possible' is incorrect for successful recrystallization since it contradicts the ideal slow cooling process required for forming pure crystals.

Explanation:

The statement that would NOT lead to a successful recrystallization is "Precipitate the crystals as fast as possible." This practice is contrary to the ideal method of recrystallization where slow cooling of the solution is necessary to form pure crystals. Rapid precipitation can trap impurities within the crystal lattice and lead to the formation of small, impure crystals. The other statements regarding drying the crystals, keeping them open to air, rinsing with cold solvent, and using a small amount of ice-cold solvent to remove remaining crystals from the flask are in line with successful recrystallization techniques.

The critical temperature at which steel trusses can fail from exposure to heat alone without any flames is

Answers

Answer: 1000°F

Explanation:

As heat starts to attack the steel trusses, the steel will fail without flame at 1000°F

The weight of H2SO4 (molecular weight 98.1) in 50.0 milliliters of a 6.00-molar solution is....

Answers

Answer:

The solution has 29.43 g of H2SO4

Explanation:

A.molar solution is in molarity concentration. It means moles of solute in 1L of solution.

This solution which is 6 M has 6 moles of sulfuric in 1L of water.

Let's determine moles of solute qith a formula:

Volume (L) . molarity = mol

0.050 L . 6 mol/L = 0.3 mol

Now we can convert the moles to mass (mol . molar mass)

0.3 mol . 98.1 g/mol = 29.43 g

A 50.0 milliliters of a 6.00-molar solution of H₂SO₄ contains 29.43 grams of the acid. This is calculated by determining the number of moles and then converting to mass using the molecular weight.

Calculating the Weight of H₂SO₄  in a 50.0 mL of a 6.00 M Solution:

To determine the weight of H₂SO₄  in a 50.0 mL solution with a molarity (M) of 6.00, follow these steps:

Calculate the number of moles of H₂SO₄ . Use the formula:
/math/ Moles = Molarity × Volume (in liters)
Here, M = 6.00 M and V = 50.0 mL = 0.050 L.
Moles of H2SO4 = 6.00 M × 0.050 L = 0.300 moles.Calculate the mass using the molecular weight of H₂SO₄  (98.1 g/mol).
Mass = Moles × Molecular Weight.
Mass = 0.300 moles × 98.1 g/mol = 29.43 grams.

Therefore, the weight of H₂SO₄ in 50.0 milliliters of a 6.00-molar solution is 29.43 grams.

The recommended daily allowance (RDA) of the trace metal magnesium is 410 mg/daymg/day for males. Express this quantity in μg/dayμg/day

Answers

Answer:

[tex]410mg/day *\frac{1000 ug}{1 mg}[/tex]

Recommended daily Amount (RDA) of magnesium is  410,000 μg/day.

Explanation:

There are 1000μg in 1 mg and 1000 mg in 1g

1 mg=1000μg

The Recommended daily Amount (RDA) is 410 mg/day of magnesium. Converting 410 mg/day into μg/day

[tex]410mg/day *\frac{1000 ug}{1 mg}[/tex]

It will become 410,000 μg/day

So Recommended daily Amount (RDA) of magnesium is  410,000 μg/day.

A balance measures mass to 0.001 g. If you determine the mass of an object that weighs about 30 g, would you record the mass as 30 g, 32 g, 32.1 g, or 32.075 g? Explain your choice by writ­ing one or two complete sentences that describe your thinking.

Answers

Answer:

The mass is recorded as 32.075 g

Explanation:

"The first digit of uncertainty is taken as the last significant digit", this is the rule for significant figures in the analysis. The balance measures the mass up to three decimal places, so it makes the most sense to note the  whole figure.

Answer:

30g

Explanation:

The true mass of the recorded will be 30g ±0.001g. This figure means that the actual mass recorded lies somewhere between either 29.999g or 30.001g. Both figures could be rounded to two significant figures giving 30g.

Hence the answer written is correct to two significant figures considering the uncertainty in the measurement of the mass.

For the isopropyl alcohol solution, what types of intermolecular forces would be experienced by the FD and; C Red 40, Blue 1 and Yellow 5 and the solution

Answers

Answer:

Hi

Isopropyl alcohol is a colorless, flammable liquid with an intense smell and miscible with water. It is an isomer of 1-propanol. It is obtained by means of a hydration reaction with propylene. It is also produced by hydrogenation of acetone. There are two main ways for the process of hydrating propylene: indirect hydration by sulfuric acid and direct hydration. The type of bond that presents hydrogen bonds and dipole-dipole forces.

Explanation:

Identify the element below and give the symbols of the other elements in its group. [Ar]4s23d104p4

Answers

Answer: The element having given electronic configuration is Selenium

Explanation:

Electronic configuration is defined as the representation of electrons around the nucleus of an atom.

Number of electrons in an atom is determined by the atomic number of that atom.

We are given:

An electronic configuration of element: [tex][Ar]4s^23d^{10}4p^4[/tex]

The number of electrons in the given element = 18 + 2 + 10 + 4 = 34

The element having atomic number '34' is Selenium

Hence, the element having given electronic configuration is Selenium

For a hydrogen atom, which electronic transition would result in the emission of a photon with the highest energy?
A.4p-->2s
B.2s-->3p
C.5f-->3d
D.3p-->6d

Answers

Answer: A

Explanation:

Considering the order of filling electrons into orbitals, movement from a higher to a lower energy level results in the emission of a photon with energy equal to the energy difference between the two energy levels. However, the energies of different orbitals are close together for high values of n (principal quantum number). Their relative energies may change significantly when they form ions. This implies that energy levels are better separated and have high differences in energy for low values of n. Hence the answer. This means that photons transiting between these Lowe n levels will posses higher photon energy due to larger energy difference between levels.

Final answer:

The electronic transition resulting in the emission of a photon with the highest energy is the one with the largest energy difference between the initial and final energy levels.

Explanation:

The electronic transition that results in the emission of a photon with the highest energy is the one involving the transition from a higher energy level to a lower energy level. This means that the transition with the largest energy difference between the initial and final energy levels will emit a photon with the highest energy. In this case, the correct option would be Option D. 3p-->6d as it involves a larger energy difference compared to the other options.

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Student mixed 25.0 mL of 0.100 M glucose, 15.0 mL of 0.500 M NaCl and 450. mL water. What are concentrations in his solution?

Answers

The question is incomplete, here is the complete question:

Student mixed 25.0 mL of 0.100 M glucose, 15.0 mL of 0.500 M NaCl and 450. mL water. What are concentrations in his solution?

A. 5.10 mM glucose, 15.3 mM NaCl

B. 5.56 mM glucose, 16.7 mM NaCl

C. 0.556 mM glucose, 0.167 mM NaCl

D. 0.222 mM glucose, 1.11 mM NaCl

E. 0.556 mM glucose, 0.0667 mM NaCl

Answer: The concentration of glucose and NaCl in the solution is 5.10 mM and 15.3 mM respectively.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}[/tex]    .....(1)

For glucose:

Molarity of glucose solution = 0.100 M

Volume of solution = 25.0 mL

Putting values in equation 1, we get:

[tex]0.100M=\frac{\text{Moles of glucose}\times 1000}{25.0}\\\\\text{Moles of glucose}=\frac{(0.100\times 25.0)}{1000}=0.0025mol[/tex]

For NaCl:

Molarity of NaCl solution = 0.500 M

Volume of solution = 15.0 mL

Putting values in equation 1, we get:

[tex]0.500M=\frac{\text{Moles of NaCl}\times 1000}{15.0}\\\\\text{Moles of NaCl}=\frac{(0.500\times 15.0)}{1000}=0.0075mol[/tex]

Total volume of solution = 25.0 + 15.0 + 450. = 490. mL

Now, calculating the concentration of glucose and NaCl in the solution by using equation 1:

Using conversion factor:  1 M = 1000 mM

For glucose:

Moles of glucose = 0.0025 moles

Volume of solution = 490. mL

Putting values in equation 1, we get:

[tex]\text{Concentration of glucose}=\frac{0.0025\times 1000}{490}\\\\\text{Concentration of glucose}=0.0051M=5.10mM[/tex]

For NaCl:

Moles of NaCl = 0.0075 moles

Volume of solution = 490. mL

Putting values in equation 1, we get:

[tex]\text{Concentration of NaCl}=\frac{0.0075\times 1000}{490}\\\\\text{Concentration of NaCl}=0.0153M=15.3mM[/tex]

Hence, the concentration of glucose and NaCl in the solution is 5.10 mM and 15.3 mM respectively.

Nitrogen and hydrogen combine to form ammonia in the Haber process. Calculate (in kJ) the standard enthalpy change ∆H° for the reaction written below, using the bond energies given. N2( g) + 3H2( g) → 2NH3( g)

Answers

Answer:

∆H° rxn = - 93 kJ

Explanation:

Recall that a change in standard in enthalpy, ∆H°, can be calculated from the inventory of the energies, H, of the bonds  broken minus bonds formed (H according to Hess Law.

We need to find in an appropiate reference table the bond energies for all the species in the reactions and then compute the result.

              N₂ (g)   +            3H₂ (g)   ⇒                          2NH₃ (g)

1 N≡N = 1(945 kJ/mol)     3 H-H = 3 (432 kJ/mol)       6 N-H = 6 ( 389 kJ/mol)

∆H° rxn = ∑  H bonds broken  - ∑ H bonds formed

∆H° rxn = [ 1(945 kJ)   + 3 (432 kJ) ] - [ 6 (389 k J]

∆H° rxn = 2,241 kJ -2334 kJ = -93 kJ

be careful when reading values from the reference table since you will find listed N-N bond energy (single bond), but we have instead a triple bond,  N≡N,  we have to use this one .

Below is the Lewis structure of the hydrogen peroxide (H202) molecule. H: O:O:H Count the number of bonding pairs and the number of lone pairs around the right oxygen atom. bonding pairs:

Answers

Idek what would be the point

The two bonding pairs and two lone pairs on each oxygen atom in the Lewis structure of hydrogen peroxide (H₂O₂) molecule.

What is the lewis electron dot diagram?

A lewis structure can be used to represent the number of chemical bonds, the bonding atoms, and the lone pairs reaming on the atoms in a given molecule.

Lines are used to showing the bonds between atoms that are bonded to one another and lone pairs are depicted as dot pairs and are placed next to the respective atoms. As the valence electrons of each oxygen atom are equal to six from the electronic configuration of the oxygen atom.

From the lewis structure of hydrogen peroxide, we can see that each oxygen atom form one bond with a hydrogen atom and another bond with an oxygen atom. The two lone pairs are still present on each oxygen atom in the molecule.

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Ethyl alcohol, also known as ethanol, has a density of 0.79 g/mL. What is the volume, in quarts, of 2.60 kg of this alcohol?

Answers

Answer: 3.49quarts

Explanation:

Mass = 2.6kg = 2600g

Density = 0.79 g/mL

Volume =?

Density = Mass / volume

Volume = Mass / Density

Volume = 2600 / 0.79

Vol = 3291.14mL = 3291.14x0.00106

Volume = 3.49quarts

Final answer:

The volume of 2.60 kg of ethyl alcohol is approximately 3.47 quarts.

Explanation:

To find the volume of 2.60 kg of ethyl alcohol, you need to convert the mass to grams and then use the formula: density = mass/volume. Rearranging the formula to solve for volume gives us: volume = mass/density. First, convert the mass from kg to g by multiplying it by 1000 (1 kg = 1000 g).

Next, plug the values into the formula: volume = 2600 g / 0.79 g/mL. Finally, divide the mass by the density to find the volume: volume = 3291.14 mL. To convert mL to quarts, divide the volume by 946.35 (1 quart = 946.35 mL): volume in quarts = 3291.14 mL / 946.35 = 3.47 quarts.

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