an engine has an input temperature of 653 K and an exhaust temperature of 312 K. determine the efficiency of the engine

Answer:

the correct answer is speed, velocity scored incorrectly on my quiz

Explanation:

The formation of bubbles, a change in color, and the formation of a precipitate (1, 3, & 5) are all indicators that a chemical reaction is occurring.

Indicators that a chemical reaction is occurring -

Chemical reactions involve the chemical interaction of two or more chemical substances, resulting in a new substance being formed, and are usually irreversible.

The signs of chemical reactions include gas formation, energy release in the form of light or flame, heat absorption, precipitate formation, and color change.

Thus, Indicators that a chemical reaction is occurring -

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The momentum of the dancer is equal to 151 Kg.m/s.

The momentum of a body can be defined as the function of the mass of the body and its velocity. Momentum (p) can be determined as the kinetic energy of the body and is the multiplication of velocity (v) and mass (m).

The mathematical equation to calculate the momentum of the body is equal to:

p = m×v

The momentum can be described as the conserved quantity and will be zero if the velocity of an object is equal to zero.

Given, the mass of the dancer, m = 60 Kg

The height from the ground, h = 0.32 m

The initial velocity of the dancer, u = 0

v² - u² = 2gh

v² - 0 = 2 × 9.8 ×0.32

v² = 6.272

v = 2.53 m/s

The momentum of the dancer does he reach the ground:

p = 60 × 2.53

p = 151 Kg.m/s

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Answer:

A. The total momentum of the system is conserved.

The value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 Newtons would be 181.81 Newtons.

The friction force prevents any two surfaces of objects from easily sliding over each other or slipping across one another. It depends upon the force applied to the object.

As given in the problem we have to find the  value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newtons,

Friction force =(coefficient of friction)*Normal force

40 = 0.22* Normal force

Normal Force = 40/0.22

                       =181.81 Newtons

Thus, the normal force comes out to be 181.81 Newtons.

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Answer:

Option D

Explanation:

Gravity is a force of attraction by virtue of mass of a body. It is an attractive force. It is due to gravity that the planets and hence, the solar system was formed. Starting from the nebula, the gravity caused the nebula to contract and form start. From rest of the material, the dust and gas were pulled in together due to gravity to form planet. The gravity of the Sun holds the planets in their respective orbits.

Thus, option D is correct.

Answer: Weatherstripping can refer to either the process or the agent that is used to seal small openings around windows, doors, trunk lids and other areas where a tight seal is desired. Essentially weatherstripping is designed to eliminate a flow or draft from an interior space to an exterior space. Because of this property, weatherstripping is often added to window sashes and doors in order to allow for more efficient heating and cooling of the interior space.

So “B” Is the answer of your question.

Explanation:Weatherstripping can take on several different forms. When it comes to dealing with drafts originating from a small open space between the bottom of a door and the floor, the addition of a small rubber strip along the threshold will often be sufficient to seal the area. The weather stripping will effectively block the airflow between inside and outside, while still allowing the door to be opened and closed with ease. Weatherstripping doors may be accomplished when the door is hung, or added at a later time as the house settles.

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Final answer:

The average rate of flow of blood along the radius of an artery is found by integrating the velocity equation v = k(R² - r²) from 0 to R, which results in an average velocity formula of (2/3)kR after integration and simplification.

Explanation:

The question asks to find the average rate of flow of blood along a radius of the artery using the given velocity equation v = k(R² - r²) and integrating between the limits 0 and R. To find the average velocity, we integrate the given equation across the artery's radius and then divide by the radius R to calculate the average.

The integration process involves calculating the integral of k(R² - r²) with respect to r, over the interval from 0 to R, which gives us kR²r - (kr³)/3 evaluated between 0 and R. Substituting the limits and simplifying, the result is (2/3)kR². To find the average velocity, we divide this by R, resulting in an average velocity of (2/3)kR.

The correct answer to the question is 0.3 m/s i.e the speed of the wave is 0.3 m/s.

CALCULATION:

As per the question, the wavelength of the wave is given as [tex]\lambda=\ 3\ m.[/tex]

The frequency of the wave f = 0.1 Hz.

We are asked to calculate the speed [ V ] of the wave .

The relation among speed, frequency and wavelength of a  wave is given as -

                            speed = frequency × wavelength

                           ⇒ V =  f × [tex]\lambda[/tex]

                                   = 3m × 0.1 Hz

                                   = 0.3 m/s.                        [ans]

Hence, the speed of the wave will be 0.3 m/s.

Answer:

option (A)

Explanation:

The amount of matter contained in the matter is called its mass.

Mass is a scalar quantity and it always remains constant.

The SI unit of mass is kg.

Answer:

7055.13 J

Explanation:

Step 1: identify the given parameters

Note: frictional force between the piano and horizontal surface is zero since the plank is frictionless.

Step 2: work done in sliding the piano up the plank = applied force X distance moved by the piano.

The distance moved by the piano is equal to the height above ground when the piano reach top of the plank.

Height of the triangle = 3.49m X sine31.6⁰

Height of the triangle = 1.8287m

Recall, height of the triangle is the height above ground which is equal to the distance moved by the piano

work done in sliding the piano up the plank = applied force X distance moved by the piano.

work done in sliding the piano up the plank = 3858N X 1.8287M

                                                                           = 7055.13 J

As per the question the car has a mass of 12,00 kg.

The engine exerts a force of 600 N.  [ here newton i.e N is the unit of force]

We are asked to calculate the acceleration of the particle .

From Newton's second law of motion we know that force acting on a particle is mass times the acceleration of the particle . Mathematically it can be written as-

                                   F = ma             [Here F is the applied force,m is the mass which is constant here and ' a' is the acceleration]

Here m =1200 kg

        F = 600 N

Hence the acceleration produced due to the force exerted by the engine on car is-                                        

                                     [tex]a =\frac{F}{m}[/tex]

                                           [tex]=\frac{600 N}{1200 kg}[/tex]

                                             [tex]=0.5 m/s^2[/tex]      [ans]  

The cyclist's displacement from the starting position after 64 seconds is 256 meters. Their position from point A after that time is 509 meters.

If a cyclist maintains a constant velocity of 4 m/s headed away from point A, their displacement after any given time can be calculated using the formula Δx = vt, where Δx is the displacement, v is the velocity, and t is the time. For a time of 64 seconds, the displacement would be Δx = (4 m/s) × (64 s) = 256 meters.

Since the cyclist starts 253 meters away from point A, the new position (total distance from point A) after 64 seconds can be found by adding the initial distance to the displacement. This gives us a total distance = 253 m + 256 m = 509 meters from point A.

According to Newton's first law of motion, an object at rest will remain at rest and an object in motion will continue moving at a constant velocity unless acted upon by an external force. To make an object slow down, an external force in the opposite direction of its motion, such as friction, is required.

According to Newton's first law of motion, an object will continue moving at a constant velocity unless acted upon by an external force. To make an object slow down, an external force in the opposite direction of its motion is required. This force is called friction. Friction can be caused by various factors, such as air resistance or contact with a surface.

B.) Any physical laws are the same for the entire universe.

The speed of the tire at the top of the next hill, which is 8.59 m high, is approximately 15.12 m/s.

a) Variables:

  - [tex]\( h_1 \)[/tex] = Initial height of the hill (22.4 m)

  - [tex]\( h_2 \)[/tex] = Height of the next hill (8.59 m)

  - [tex]\( v_{i1} \)[/tex] = Initial speed of the tire (2.10 m/s)

  -[tex]\( v_{f1} \)[/tex] = Final speed at the top of the first hill

  - [tex]\( v_{f2} \)[/tex] = Final speed at the top of the next hill

  - g = Acceleration due to gravity (-9.8 m/s²)

b) Equation for the first hill:

[tex]\[ v_{f1}^2 = v_{i1}^2 + 2gh_1 \][/tex]

c) Calculate [tex]\( v_{f1} \)[/tex]:

[tex]\[ v_{f1}^2 = (2.10 \, \text{m/s})^2 + 2(-9.8 \, \text{m/s}^2)(22.4 \, \text{m}) \][/tex]

[tex]\[ v_{f1} \approx 16.83 \, \text{m/s} \][/tex]

d) Equation for the next hill:

[tex]\[ v_{f2}^2 = v_{f1}^2 + 2gh_2 \][/tex]

e) Solve for [tex]\( v_{f2} \)[/tex]:

[tex]\[ v_{f2}^2 = (16.83 \, \text{m/s})^2 + 2(-9.8 \, \text{m/s}^2)(8.59 \, \text{m}) \][/tex]

[tex]\[ v_{f2} \approx 15.12 \, \text{m/s} \][/tex]

The speed of the tire at the top of the next hill, which is 8.59 m high, is approximately 15.12 m/s.

Final answer:

The speed of the tire at the top of the next hill is 21.2 m/s.

Explanation:

To find the speed of the tire at the top of the next hill, we can use the principle of conservation of energy.

According to the principle of conservation of energy, the initial potential energy of the tire at the top of the first hill is equal to the final potential energy of the tire at the top of the next hill.

Therefore, we have:

mgh = 1/2 × mv²

Where m is the mass of the tire, g is the acceleration due to gravity, h is the height difference between the two hills, and v is the final velocity of the tire at the top of the next hill.

Plugging in the values, we get:

10.5 × 9.8 × 22.4 = 1/2 × 10.5 × v²

Solving for v, we find:

v = sqrt((2 × 10.5 × 9.8 × 22.4) / 10.5)

v = 21.2 m/s

Final answer:

The plane ends up flying northeast. To find its speed relative to the ground, use vector addition to calculate the resultant velocity as 694 km/hr.

Explanation:

Direction: The plane ends up flying northeast.

Speed Relative to the Ground: To find the speed relative to the ground, we need to calculate the resultant velocity. The plane's velocity relative to the air is northeast at an angle, while the wind blows from the west. Using vector addition, we determine the speed relative to the ground to be 694 km/hr.

Vector Addition: Vector addition is essential to determine the resultant velocity of the plane with respect to the ground, taking into account both the airspeed and the wind speed.

Shearing

The stress force that causes a mass of rock to pull or twist in opposite directions is called shearing.

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Answer:

16m

Explanation:

To find a vector w with the same direction of u but twice as long as v, we can use unit vectors. The magnitude of u is √20 and the magnitude of v is √5. The unit vector parallel to u is (0, 2/√5, 1/√5) and the unit vector parallel to v is (2/√5, 1/√5, 0). Multiplying the unit vector parallel to u by 2 times the magnitude of v gives us the vector w = (4/√5, 2/√5, 0).

To find a vector w with the same direction as u but twice as long as v (u = {0 4 2} v = {2 1 0}), we can use the concept of unit vectors. First, let's calculate the magnitudes of vectors u and v. The magnitude of u is √(0^2 + 4^2 + 2^2) = √20. The magnitude of v is √(2^2 + 1^2 + 0^2) = √5.

To find a unit vector parallel to u and v, we divide each vector by its magnitude. The unit vector parallel to u is (0/√20, 4/√20, 2/√20) = (0, 2/√5, 1/√5). The unit vector parallel to v is (2/√5, 1/√5, 0).

To find a vector w with the same direction as u but twice as long as v, we can multiply the unit vector parallel to u by 2 times the magnitude of v. w = 2(2/√5, 1/√5, 0) = (4/√5, 2/√5, 0).