An element of Group II loses two electrons in the process of a chemical combination. What is its ionic charge?

The chemical symbol of the chlorine element is represented Cl.

A chemical element can be described as a species of atoms that have a given number of protons in their nuclei which includes a pure substance consisting only of that species.

The chemical elements cannot be further broken down into simpler substances, unlike chemical compounds, by any chemical reaction.  The defining property of an element is the number of protons in the nucleus which is referred to as its atomic number.

Nearly all naturally occurring chemical elements occur on the Earth as compounds or mixtures. Air is primarily a mixture of nitrogen, oxygen, and argon, though it does contain compounds like carbon dioxide and water. A chemical symbol can bed described as a one- or two-letter designation of an element that has the first letter always capitalized.

The elements are organized in tabular form by increasing atomic numbers into rows called "periods" and into columns called "groups" that share physical and chemical properties. The modern periodic table summarizes various properties of the elements and the relationships between them.

Learn more about the chemical element, here:

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Answer: The chemical formula of the compound is [tex]Sr_3P_2[/tex]

Explanation:

Strontium is the 38th element of the periodic table. The electronic configuration of this element is [tex][Kr]5s^2[/tex]

This element will loose 2 electrons to attain stable electronic configuration to attain +2 oxidation state.

Phosphorus is the 15th element of the periodic table. The electronic configuration of this element is [tex]1s^22s^22p^63s^22p^3[/tex]

This element requires 3 electron to attain stable electronic configuration to attain -3 oxidation state.

So, by criss-cross method, the oxidation state of the ions are exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

Hence, the chemical formula of the compound is [tex]Sr_3P_2[/tex]

Final answer:

When 35.0 mol of C2H2 react completely according to the given equation, 70.0 mol of CO2 will be produced.

Explanation:

The student asked about the amount of CO2 produced when 35.0 mol C2H2 reacts completely, according to the balanced chemical equation provided for the combustion of acetylene (C2H2) in an acetylene torch: 2C2H2 + 5O2 → 4CO2 + 2H2O.

To find the amount of CO2 produced, we apply stoichiometry using the balanced equation. According to the equation, 2 moles of C2H2 produce 4 moles of CO2. Therefore, if 35.0 mol C2H2 react completely, the amount of CO2 produced can be calculated by setting up a ratio:

(35.0 mol C2H2) × (4 mol CO2 / 2 mol C2H2) = 70.0 mol CO2

Thus, 35.0 mol of C2H2 will produce 70.0 mol of CO2 when they react completely.

Answer:

[tex]N_2O_{3}[/tex]

Explanation:

Hi, the empirical formula is the minimal expression of the molecule composition and doesn't always represent the molecule in the reality.

On the other hand the molecular formula is a multiple of the empirical and represents how the molecule is composed in reality.

In this case they are the same.

Now, nitrogen has an atomic weight of 14 g/mol and oxygen one of 16 g/mol:

[tex]n_{nitrogen}=\frac{4.5g}{14g/mol}[/tex]

[tex]n_{nitrogen}= 0.321mol[/tex]

[tex]n_{oxygen}=\frac{7.715g}{16g/mol}[/tex]

[tex]n_{oxygen}= 0.482mol[/tex]

So the formula would be:

[tex]N_{0.321}O_{0.482}[/tex]

Dividing per 0.321:

[tex]NO_{1.5}[/tex]

In natural numbers:

[tex]N_2O_{3}[/tex]

Human activities can indeed accelerate the process of both physical and chemical weathering. Option C) is the correct answer.

Physical weathering involves the degradation of rock through physical processes, such as freeze-thaw cycles or abrasion. Chemical weathering, on the other hand, involves the decomposition of rock through chemical reactions, such as oxidation and hydration.

Human activities, such as deforestation, mining, and construction, can accelerate these processes. For instance, the removal of trees (deforestation) can lead to more intense freeze-thaw cycles, accelerating physical weathering. Mining, meanwhile, exposes more rock to air and water, facilitating chemical reactions and thus speeding up chemical weathering.

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The standard free energy of formation of nitric oxide (NO(g)) is 86.55 kJ/mol at 25 degrees Celsius. This refers to the energy change during the formation of one mole of the compound from its elements in their standard states. However, different compounds might have higher or lower values depending on various conditions.

The standard free energy of formation, or ΔGo°f, refers to the change in energy that occurs when one mole of a compound is formed from its elements in their most stable states at standard conditions (1 atm and 25 °C). It is zero for elemental substances in their standard states.

Nitric oxide (NO) in its gaseous form, specifically, has a ΔGo°f of 86.55 kJ/mol at 25 °C. This value may vary based on the temperature and other conditions of the reaction.

It's important to note that even though NO(g) has a high standard free energy of formation, it doesn't imply that NO(g) is the compound with the 'highest' ΔGo°f across all compounds. The ΔGo°f of a compound would depend on the complexity of the molecule, its elemental composition, and other factors. Therefore the ΔGo°f of different compounds can be looked up in tables in chemical reference books or databases.

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Answer:

The answers are options 1, 2, 3, and 5.

Explanation:

Hello!

Let's solve this!

When an experiment is carried out and less product is obtained, it may be because:

There are impurities in the substances.

The reaction might not go to completion.

The amount of one of the reactants might be measured incorrectly.

The expected amount might be based on measurements with error.

We conclude that the answers are options 1, 2, 3, and 5.

Answer:

Explanation:

The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule. Covalent bonds are established between non-metallic elements, such as hydrogen H, oxygen O and chlorine Cl. These elements have many electrons in their outermost level (valence electrons) and have a tendency to gain electrons to acquire the stability of the electronic structure of noble gas.

An ionic bond is produced between metallic and non-metallic atoms, where electrons are completely transferred from one atom to another. During this process, one atom loses electrons and another one gains them, forming ions. Usually, the metal gives up its electrons forming a cation to the nonmetal element, which forms an anion.

So, a way to determine the type of bond will be knowing if the atoms are metallic or non-metallic.

He identified triads of elements that had similar properties.

Degradation means that a large molecule is broken down into simpler ones. In this case, glucose which has a chemical formula of C6H12O6 is broken down into simple parts.

Assuming that the reaction takes the form below, glucose is usually converted into 6 units of carbon dioxide CO2.

C6H12O6  + reactant  -->  6CO2  + product

Final answer:

When glucose is completely degraded, its six carbon atoms combine with oxygen to form carbon dioxide during cellular respiration. The energy from glucose's chemical bonds is stored in energy-carrier molecules.

Explanation:

When glucose is completely degraded, all six carbon atoms combine with oxygen to form carbon dioxide. The process of glucose degradation occurs during cellular respiration, specifically through the Krebs Cycle. After two turns of the cycle, the original glucose molecule has been broken down completely, and the energy from its chemical bonds has been stored in energy-carrier molecules. In total, 16 energy-carrier molecules are produced.

Answer:

Energy of one photon = [tex]4.81\times 10^{-19}J[/tex]

Explanation:

Frequency = [tex]7.26\times 10^{14}\ Hz[/tex]

Energy of a photon is given by:

E = hν

Where,

h = Plank's constant

ν = Frequency

h = [tex]6.626\times 10^{-34}J\ s[/tex]

ν = [tex]7.26\times 10^{14}\ Hz\ or\ 7.26\times 10^{14}\ s^{-1}[/tex]

E = hν

   [tex]=(6.626\times 10^{-34}Js)\times (7.26\times 10^{14}\ s^{-1})\\=4.81\times 10^{-19}J[/tex]

Energy of one photon = [tex]4.81\times 10^{-19}J[/tex]

Final answer:

The energy of a photon of blue light with a frequency of 7.26 × 10¹⁴ Hz is approximately 4.81 × 10⁻¹⁹ joules, calculated using Planck's formula E = hf.

Explanation:

The energy of exactly one photon of light with a frequency of 7.26 × 10¹⁴ Hz can be calculated using the formula E = hf, where E is the energy in joules, h is Planck's constant (6.626 × 10⁻³⁴ J·s), and f is the frequency in hertz. Substituting the given values into the formula:

E = (6.626 × 10⁻³⁴ J·s) × (7.26 × 10¹⁴ Hz)

This results in an energy of 4.81 × 10⁻¹⁹ J per photon. Thus, a blue photon with a frequency of 7.26 × 10¹⁴ Hz has an energy of approximately 4.81 × 10⁻¹⁹ joules.

the reason why is that salt is a solid while ice is a liquid solid

or something like that but don't forget to put that it is  a solid

Answer: False

Explanation:

Binary Solution is a homogeneous mixture of two components called as solute and solvent.

Solute is the component which is present in smaller proportion and is solid for solid in liquid solution and solvent is the component which is present in larger proportion and is liquid for solid in liquid solution.

For example: NaCl in water will have NaCl as solute and will be lesser in amount and water will be solvent and will be greater in amount.

Thus the statement that in a solution the solute is the substance present in the greatest amount is false.

By using the reaction and given data, we find that the 1.25 g sample contains approximately 83.9% Al(C₆H₅)₃.

The primary calculations involve moles and molecular weight to determine the mass percentage.

The result shows a high concentration of Al(C₆H₅)₃ in the sample.

To determine the weight percent of Al(C₆H₅)₃ in the original 1.25-g sample, we need to work step-by-step through the given reaction:

Given that 0.951 g of benzene (C₆H₆) is produced, we can use this information to find the moles of Al(C₆H₅)₃ reacted:

Next, we calculate the mass of Al(C₆H₅)₃:

Finally, we calculate the weight percent of Al(C₆H₅)₃ in the original sample:

Therefore, the weight percent of Al(C₆H₅)₃ in the original 1.25-g sample is approximately 83.9%.

Correct question is: A 1.25-g sample contains some of the very reactive compound Al(C₆H₅)₃ .On treating the compound with aqueous HCl, 0.951 g of C6H6 is obtained.
Al(C₆H₅)₃ (s) + 3HCl(aq) --> AlCl₃(aq) + 3C₆H₆(l)
Assuming that Al(C₆H₅)₃ was converted completely to products, what is the weight percent of Al(C₆H₅)₃ in original 1.25-g sample?