a stone is dropped into a deep well and is heard to hit the water 3.41 s after being dropped. determine the depth of the well. ...?

Final answer:

Distance profoundly influences gravitational force as it changes inversely with the square of the distance between two objects. The gravitational force weakens significantly when the distance is increased, following Newton's universal law of gravitation.

Explanation:

Distance has a crucial impact on the gravitational force. According to Newton's universal law of gravitation, the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. This implies that if the distance between two objects doubles, the gravitational force between them becomes one-quarter as strong, following an inverse square relationship.

For example, if we consider two galaxies, the gravitational attraction between them is governed by the same principle. The greater the distance (r), the weaker the gravitational pull between the two galaxies. In the case of celestial bodies like a red giant star expanding, points on its surface get farther from the center of gravity, resulting in a decrease in the gravitational pull at those points.

Newton's insights allowed us to understand that the gravitational force drops to zero only at an infinite distance, which is why objects in the universe, no matter how far apart, still exert some gravitational influence on each other, although it becomes increasingly weaker with distance.

Final answer:

The period of oscillation of a 4.0kg object suspended from a spring when a force of 20.0N elongates it by 0.20m is approximately 1.26 seconds, calculated using the formula T = 2π√(m/k) where k is the spring constant.

Explanation:

The period of oscillation for a mass suspended from a spring depends on the spring constant k and the mass m. The period T is given by the formula T = 2π√(m/k), where m is the mass in kilograms and k is the spring constant in newtons per meter.

To find the spring constant, we use the fact that when a force F is applied to a spring, it stretches by a distance x, and F = kx. Thus, k = F/x. In this case, a force of 20.0N elongates the spring by 0.20m, so the spring constant k is 100 N/m.

With k = 100 N/m and m = 4.0 kg, we can calculate the period T as follows:

T = 2π√(4.0kg / 100 N/m) = 2π√(0.04)

T ≈ 1.26 seconds. Therefore, the period of oscillation of a 4.0kg object suspended from this spring is approximately 1.26 seconds.

B.  Analgesics are used to reduce pain

Positive acceleration occurs when an object speeds up.

Explanation:

Acceleration is the rate of change in velocity per unit time:

[tex]a=\frac{\Delta v}{\Delta t}[/tex]

where [tex]\Delta v[/tex] is the change in velocity while [tex]\Delta t[/tex] is the time interval. From the formula, we can understand that when [tex]\Delta v[/tex] is positive, so when the object is speeding up, the acceleration is positive; on the contrary, when [tex]\Delta v[/tex] is negative (so, when the object is slowing down), the acceleration is negative.

Positive acceleration occurs when there's an increase in an object's velocity over time, like when a car speeds up after pressing the gas pedal.

Positive acceleration occurs when an object speeds up. This concept is central to the understanding of motion in physics. Acceleration is defined as the rate of change of velocity per unit of time. When the velocity of an object increases, it means the object is speeding up, hence, undergoing positive acceleration. For instance, when you press the gas pedal in a car, you increase the car's velocity; that's an example of positive acceleration in the real world.

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the answer is the second option false

Answer:

false

Explanation:

Answer:

b)  line spectra

Explanation:

 The model of the atom as given by Rutherford was modified by Bohr. According to Rutherford's model, the electrons that orbit the nucleus electromagnetic radiation. As a result they lose energy and had to collapse into the nucleus, thereby making the atom unstable.

Bohr corrected that by proving that electrons revolve around the nucleus only in certain fixed orbits, with a specific energy. They can jump from one to another and lose or gain energy by emitting or absorbing energy in that process.

Electron cloud is the region where the electrons are most likely to occur. This was proposed by Schrodinger.

The period of the wave is 4 seconds

D. The net gravitational force on the astronaut is not balanced by a normal force

When an astronaut in orbit experiences apparent weightlessness, the net gravitational force on the astronaut is not balanced by a normal force.

When an astronaut in orbit experiences apparent weightlessness, the correct option is d. the net gravitational force on the astronaut is not balanced by a normal force. In orbit, the astronaut is still under the influence of gravity, but they are constantly falling towards the Earth due to their orbital velocity. This creates the sensation of weightlessness as the astronaut and their spacecraft are in freefall around the Earth.

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The wavelength of the radiation released when an electron moves from the n=5 to n=2 orbit is calculated using the Rydberg formula, resulting in a wavelength of 536 nm.

To calculate the wavelength of the radiation released when an electron moves from the n=5 to the n=2 energy level, we can apply the Rydberg equation. In this case, n1 would represent the lower energy level (2), and n2 would represent the higher energy level (5). The Rydberg formula for wavelength is 1/λ = R (1/n1² - 1/n2²), where R is the Rydberg constant (approximately 1.097x10^7 m-1).

When we substitute our given values into this formula we find:

So, λ = 1/1/λ = 5.36 x 10^-7 m or 536 nm.

This represents the energy difference between the two levels as expressed through the wavelength of the emitted photon when the electron makes a transition from n=5 to n=2.

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To find the wavelength of radiation when an electron transitions from n=5 to n=2 in a hydrogen atom, use the Rydberg formula. After calculations, the wavelength is found to be approximately 434 nm.

This question relates to the calculation of the wavelength of the radiation emitted by a hydrogen atom when an electron transitions from the n=5 energy level to the n=2 energy level. We use the Rydberg formula for this calculation:

1/λ = R_H (1/n₁² - 1/n₂²)

where λ is the wavelength, R_H is the Rydberg constant (approximately 1.097 x 10⁷m⁻¹) n1 is the lower energy level, and n2 is the higher energy level. For this specific transition, n1=2 and n2=5.

Thus, the wavelength of the radiation released is approximately 434 nm.

Answer: C.

The gravity on the Moon is less than the gravity on Earth.

Explanation: plato :3

Final answer:

To find the magnitude and direction of the fourth displacement, we can use vector components. We need to add up the north and east components of the three given displacements, and then find the fourth displacement that brings the sum back to the starting point.

Explanation:

To find the magnitude and direction of the fourth displacement, we can use vector components. We need to add up the north and east components of the three given displacements, and then find the fourth displacement that brings the sum back to the starting point. Let's break down the given displacements:

First, let's convert the given angles to north and east components:

Now we can add up the north and east components:

North component: 0 + (-210sin(45°)) + 270sin(30°)

East component: -190 + (-210cos(45°)) + (-270cos(30°))

Finally, we can use these components to find the magnitude and direction of the fourth displacement using the Pythagorean theorem and trigonometry.

Final answer:

The magnitude and direction of the fourth displacement, use vector components to represent each displacement as a vector and add them together. Then subtract the vector sum from the starting point to find the magnitude and direction of the fourth displacement.

Explanation:

To find the magnitude and direction of the fourth displacement in the given scenario, we can use vector components. We start by representing each displacement as a vector with its magnitude and direction. The first displacement is 190 m straight west, which can be represented as (-190, 0) in vector form. The second displacement is 210 m in a direction 45.0° east of south, which can be represented as (210*cos(45°), -210*sin(45°)). The third displacement is 270 m at 30.0° east of north, which can be represented as (270*cos(30°), 270*sin(30°)). Adding these vectors together will give us the vector sum of the first three displacements. To find the fourth displacement, we need to subtract this vector sum from the starting point, which will give us the magnitude and direction of the fourth displacement.

The answer is true.

Answer:

True

Explanation:

Gravity is a force that helps to hold the universe together. The statement is true. The gravitational force is always attractive in nature. It depends on the masses and the distance between them. Mathematically, it is given by :

[tex]F=G\dfrac{m_1m_2}{d^2}[/tex]

Where

G = universal gravitational constant

m₁ and m₂ are masses

d is the distance between them

Gravity is responsible to hold the planets in an orbit around the sun. Ocean tides are also caused due to gravitational pull of the moon. If gravity is not present in the universe then there would be no moon, no stars etc.

Hence, the given statement is true.

The projectile will take about 9 s to reach the highest point in its path.

[tex]\texttt{ }[/tex]

Acceleration is rate of change of velocity.

[tex]\boxed {a = \frac{v - u}{t} }[/tex]

[tex]\boxed {d = \frac{v + u}{2}~t }[/tex]

where:

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

[tex]\texttt{ }[/tex]

Let's recall Range of Projectile formula as follows:

[tex]\boxed{ R = \frac{ v_o^2 \sin 2\theta}{g} }[/tex]

where:

R = range of projectile ( m )

v₀ = initial speed of projectile ( m/s )

θ = angle of projection

g = gravitational acceleration ( m/s² )

Let us now tackle the problem!

[tex]\texttt{ }[/tex]

Given:

initial vertical component of speed of projectile = u_y = 90 m/s

initial horizontal component of speed of projectile = u_x = 49 m/s

gravitational acceleration = g = 9.80 m/s²

Asked:

time taken to reach the highest point = t = ?

Solution:

As we know that the final vertical component of speed of projectile at the highest point is 0 m/s , therefore:

[tex]v_y = u_y - gt[/tex]

[tex]0 = 90 - 9.8t[/tex]

[tex]90 = 9.8t[/tex]

[tex]t = 90 \div 9.8[/tex]

[tex]t \approx 9 \texttt{ s}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Kinematics

Answer: The best and most correct answer among the choices provided by your question is the first choice.

The altitude of a triangle is the height of the triangle and the median of a triangle intersects each side.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

Explanation:

Answer:

A. 0.0 joules

Explanation:

We can calculate the initial kinetic energy of the car, which is given by:

[tex]K=\frac{1}{2}mv^2 = \frac{1}{2}(1,324 kg)(20 m/s)^2=2.65\cdot 10^5 J[/tex]

where m is the mass of the car and v its initial speed. After the collision, the car stops, so its final speed is zero. Therefore, the new kinetic energy of the car will be

[tex]K=\frac{1}{2}(1,324 kg)(0 m/s)^2 = 0 J[/tex]

This type of collision is called 'perfectly inelastic collision', and it occurs when there is the maximum loss of kinetic energy, as in this case. Therefore, the correct answer is

A. 0.0 joules

The kinetic energy of a car that crashes into a wall and stops is 0.0 joules since the car's velocity becomes zero after the perfectly inelastic collision.

When a car traveling at a certain speed crashes into a wall and stops, it undergoes a perfectly inelastic collision as it collides with the wall and comes to rest. The initial kinetic energy of the car can be calculated using the formula KE = ½ mv², where m is the mass of the car and v is the velocity of the car. However, after a perfectly inelastic collision with the wall, where the car comes to a complete stop, the kinetic energy is 0.0 joules because the velocity of the car is zero, and thus kinetic energy after the collision is also zero.

Answer : (1) wheelbarrow  (2) seesaw

Explanation :

(1) In second- class lever, the fulcrum is at one of the end or we can say the load is in between the effort and the fulcrum. The example of second- class lever is wheelbarrow.

(2) In first- class lever, the fulcrum is in between the applied force or the effort and the load. The example of first class lever is seesaw.

Answer:

Explanation:

Periodic table of element is organized on the basis of number of protons present in the nucleus of element. Nucleus contain both proton and neutron, whereas, electrons are present in the energy level i.e. outside nucleus so, it is the number of proton which determine the atomic number of an element thereby, it's position on the periodic table.

For example, carbon have six proton and oxygen have eight proton that is why carbon is placed ahead of oxygen in the periodic table.

The distance traveled by an object under the influence of gravity is 4.9t².

The distance traveled by an object under the influence of gravity is determined using second equation of motion as follows;

x(t) = v₀t + ¹/₂gt²

x(t) = 0 + ¹/₂gt²

x(t) = 4.9t²

Graph of the distance between t= 0 and t = 5 s

The graph of the motion of the object is presented in the image uploaded.

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The distance fallen by an object under the influence of gravity increases with the square of time. At t=0, the distance fallen is 0. Using the equation d = 0.5 * g * t^2, where g is the acceleration due to gravity, we can calculate the distance fallen at different time intervals.

The distance fallen by an object under the influence of gravity can be represented by a quadratic equation. At time t=0, the object starts from rest and its distance fallen is zero. As time increases, the object's distance fallen increases with the square of time.

Let's draw the distance fallen, as a function of time, from t=0 to t=5.00. At t=0, the distance fallen is 0. As time increases, the distance fallen can be calculated using the equation d = 0.5 * g * t^2, where g is the acceleration due to gravity (9.8 m/s^2).

Here is a table representing the distance fallen at different time intervals:

t = 0 s, d = 0 m
t = 1 s, d = 4.9 m
t = 2 s, d = 19.6 m
t = 3 s, d = 44.1 m
t = 4 s, d = 78.4 m
t = 5 s, d = 122.5 m

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Answer:

its molecules

Explanation: